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First passage percolation on rotationally invariant fields

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Presentation on theme: "First passage percolation on rotationally invariant fields"β€” Presentation transcript:

1 First passage percolation on rotationally invariant fields
Allan Sly Princeton University September 2016 Joint work with Riddhipratim Basu (Stanford) and Vladas Sidoravicius (NYU Shanghai)

2 First Passage Percolation
Model: 𝑋 𝑖,𝑗 an IID random field of numbers 𝑇 π‘₯,𝑦 minimum sum along paths from x to y. 1 3 5 6 9 7 8 4 2 By Subadditive Ergodic Theorem: lim 1 𝑛 𝑇 0,𝑛 π‘₯ = πœ‡ π‘₯ π‘Ž.𝑠.

3 Variance Central question: What is the variance?
By Poincare inequality [Kesten ’91] π‘‰π‘Žπ‘Ÿ 𝑇 𝑛 π‘₯ =𝑂(𝑛) Using hypercontractivity for Boolean case π‘‰π‘Žπ‘Ÿ 𝑇 𝑛 π‘₯ =𝑂(𝑛/ log 𝑛 ) [Benjamini, Kalai, Schramm ’03] Extended to a wider range of distributions [Damron, Hanson, Sosoe ’15] For oriented last passage percolation with exponential or geometric entries π‘‰π‘Žπ‘Ÿ 𝑇 𝑛 π‘₯ ~ 𝐢 𝑛 2/3 [Johansson ’00]

4 Rotationally Invariant models
Our model: Take Ξ¦: ℝ 2 β†’ ℝ 2 rotationally invariant, smooth and compactly supported. Let Ξ“:ℝ→(π‘Ž,𝑏) be continuous and strictly increasing. Set 𝑋 π‘₯,𝑦 =Ξ“ Ξ¦ π‘’βˆ’π‘₯,π‘£βˆ’π‘¦ 𝑑𝐡(𝑒,𝑣) Define the distance as 𝑇 π‘₯,𝑦 = min 𝛾 𝛾 𝑋

5 Main Result Main result (Basu, Sidoravicius, S. β€˜16) For some πœ–>0,
π‘‰π‘Žπ‘Ÿ 𝑇 𝑛 =𝑂( 𝑛 1βˆ’πœ– ) The specifics of the model are not that important, should hold for models with Rotational invariance FKG Property Short range of dependence. E.G. Graph distances for supercritical random geometric graphs.

6 Basic Approach Mutli-scale: V n β‰”π‘‰π‘Žπ‘Ÿ 𝑇 𝑛 . Set 𝑍 𝑛 = 𝑀 log 𝑀 𝑛 = 𝑛 1βˆ’πœ– . We show that 𝑉 𝑀 π‘˜ ≀ 𝑍 𝑀 π‘˜ = 𝑀 2 π‘˜ . Enough to show that for all 𝑛, 𝑉 𝑛 ≀ 𝑍 𝑛 β‡’ 𝑉 𝑀𝑛 ≀ 𝑍 𝑀𝑛 = 𝑀 2 𝑍 𝑛 . Block version of Kesten’s bounds 𝑉 ℓ𝑛 ≀𝐢 β„“ 𝑉 𝑛 Chaos estimate – path is highly sensitive to noise.

7 Kesten’s martingale argument
Reveal the sites one by one: 𝑀 𝑖 =𝔼 𝑇 𝑛 β„± 𝑖 ] Then π‘‰π‘Žπ‘Ÿ 𝑇 𝑛 = Ξ£ 𝑖 π‘‰π‘Žπ‘Ÿ 𝑀 𝑖 βˆ’ 𝑀 π‘–βˆ’1 ≀ Ξ£ 𝑖 π”Όπ‘‰π‘Žπ‘Ÿ T n | β„± 𝑖 c The value of block i will only matter if it is on the optimal path so Ξ£ 𝑖 𝔼 π‘‰π‘Žπ‘Ÿ T n | β„± 𝑖 c ≍ 𝐢𝔼 #{𝑖 :π‘–βˆˆπ›Ύ}≍ 𝐢𝑛 With some extra tricks one can also get concentration bounds.

8 Multiscale version of Kesten argument
Split grid into blocks length 𝑛, height W n = 𝑛 1/2 𝑍 𝑛 1/4 Revealing blocks - analyze Doob martigale of 𝑇 ℓ𝑛 What we need Relate point to point with side to side Variance: 𝑉 ℓ𝑛 ≀ 𝐢 β„“ 𝑍 𝑛 Concentration: β„™ 𝑇 ℓ𝑛 βˆ’π”Ό 𝑇 ℓ𝑛 β‰₯π‘₯ β„“ 𝑍 𝑛 ≀ 𝐢 𝑒 βˆ’π‘ π‘₯ 2/3 𝔼 𝑇 ℓ𝑛 βˆ’πœ‡ β„“ 𝑛 ≀𝐢 β„“ 𝑍 𝑛 Transversal Fluctuations of order β„“ 3/4 π‘Š 𝑛

9 Side to side Diagonal Length
𝑛 2 + π‘Š 𝑛 2 = 𝑛 2 +𝑛 𝑍 𝑛 1/2 β‰ˆπ‘› 𝑍 𝑛 1/2 And 𝑍 𝑛 1/2 is the bound on the standard deviation.

10 Transversal fluctuations
To move up π‘˜ blocks, extra length is 2 π‘˜ 𝑍 𝑛 . For midpoint 𝑃 π‘˜βˆ’π‘π‘™π‘œπ‘π‘˜ π‘“π‘™π‘’π‘π‘‘π‘’π‘Žπ‘‘π‘–π‘œπ‘› ≀ 𝐢 𝑒 βˆ’π‘ π‘˜ 4/3 For other dyadic points use chaining. At least on segment must deviate from its mean by at least π‘˜ 𝑍 𝑛 π‘˜ π‘Š 𝑛

11 Side to side To compare the maximum side to side length 𝑇 𝑛 + with point to point 𝑋 𝑛 . Use chaining 𝔼 𝑇 𝑛 + βˆ’π”Ό 𝑇 𝑛 ≀ 𝐢 𝑍 𝑛 1/2

12 Side to side To compare the minimum side to side length 𝑇 𝑛 βˆ’ with point to point 𝑇 𝑛 + . Split up path 𝔼 𝑇 𝑛 + ≀𝔼 𝑇 4𝑛 5 βˆ’ +2𝔼 max 𝑖𝑗 𝑇 𝑛 10 ,𝑖,𝑗 𝐢 𝑍 𝑛 1/2 Max Min Max Max

13 Relating mean to πœ‡ By subadditivity 𝔼 𝑇 𝑛 >𝑛 πœ‡.
By enumerating over long paths we show that for C large if 𝔼 𝑇 𝑛 βˆ’ β‰₯π‘›πœ‡+𝐢 𝑍 𝑛 then lim 1 ℓ𝑛 𝑇 ℓ𝑛 > πœ‡.

14 Concentration 𝜏= Ξ£ 𝑖 # π‘π‘™π‘œπ‘π‘˜π‘  𝑖𝑛 πΆπ‘œπ‘™π‘’π‘šπ‘› 𝑖 2
𝜏= Ξ£ 𝑖 # π‘π‘™π‘œπ‘π‘˜π‘  𝑖𝑛 πΆπ‘œπ‘™π‘’π‘šπ‘› 𝑖 2 Similarly to transversal fluctuations β„™ 𝜏> 𝐢+π‘₯ β„“ ≀ 𝑒 βˆ’ π‘₯β„“ 2/3 Apply Doob martingale and Kesten’s concentration argument revealing columns one at a time. Can not take union bound over all paths because of sub-exponential tails

15 Proof by contradiction
Case 1: Either for some 1≀ℓ≀𝑀 we have 𝑉 ℓ𝑛 ≀ 𝛿 β„“ 𝑍 𝑛 in which case we show that 𝑉 𝑀𝑛 ≀ 𝐢 𝛿 𝑀 𝑍 𝑛 ≀ 𝑍 𝑀𝑛 . Case 2: For all ℓ≀𝑀 𝑉 ℓ𝑛 β‰₯ 𝛿 β„“ 𝑍 𝑛 Use chaos argument. This case never actually happens as we believe 𝑉 𝑛 ≍ 𝑛 2/3 .

16 Super-concentration – chaos
In the context of FPP: Super-concentration: Better than Poincare inequality i.e. 𝑉 𝑛 =π‘œ(𝑛) Chaos: with 𝛾 the optimal path and 𝛾′ the optimal path after resampling πœ– fraction of the field then π›Ύβˆ© 𝛾 β€² β‰€π‘œ(𝑛) Super-concentration ⇔ Chaos [e.g. Chatterjee β€˜14 ] Works well for block version.

17 Proving Chaos Aim: Resample πœ– fraction of the blocks and find good alternatives to the original path. Need to understand the field conditioned on the path before and after resampling Similar to [BSS β€˜14]

18 Percolation type estimates
We have control of the transversal fluctuations of the path. A percolation estimate says that all paths with reasonable fluctuations spend most of their time in β€œtypical” regions. Atypical

19 FKG type estimates Conditioning on the location and value of the path is a positive event for the rest of the field. We can use FKG to sample create regions that are very positive which the optimal path must avoid (before and after resampling.

20 Planting a configuration
For a region A, suppose that if 𝑋 𝐴 , 𝑋 𝐴 𝑐 =( 𝒳 𝐴 , 𝒳 𝐴 𝑐 ) such that 𝛾 does not intersect 𝐴 then β„™ 𝑋 𝐴 = 𝒳 𝐴 𝑋 𝐴 𝑐 = 𝒳 𝐴 𝑐 ,𝛾] β‰₯β„™[ 𝑋 𝐴 = 𝒳 𝐴 ] So we can plant configurations provided they avoid A. A

21 Big changes Using our assumption that π‘‰π‘Žπ‘Ÿ 𝑇 ℓ𝑛 β‰₯ 𝛿 𝑍 ℓ𝑛 we show that we can find regions with very long and very short geodesics. By interpolation between them in 1/πœ– steps we can find regions with a large change with positive probability after πœ– resampling. We look for regions which become much shorter.

22 Pulling the paths apart
We design a collection of events which together separate the old and new paths. Positive probability at each location. Concentration estimates separate path at 𝛿 fraction of location w.h.p.

23 Multi-scale Improvements
We look for improvements on a range of scales. Show that π›Ύβˆ© 𝛾 β€² ≀𝛿|𝛾|. Conclude 𝑉 𝑀𝑛 ≀ 𝑀 2 𝑍 𝑛 = 𝑍 𝑀𝑛

24 Lattice models Can rotational invariance be relaxed?
Should be sufficient that the limiting shape is smooth and has positive curvature in a neighbourhood of the direction.

25 Thank you for listening


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