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The Quadratic Formula
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Reminder Form of a quadratic equation: ax2 +bx + c = 0
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Solve for x: 2x2 + 4x + 1 = 0 No, not factorable
Can we solve by factoring? No, a > 1 Can we solve by completing the square?
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The Quadratic Formula:
π₯= βπΒ± π 2 β4ππ 2π
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Solve for x: 2x2 + 4x + 1 = 0 a b c π₯= Β± β βπ π2 - 4 π π 2 π
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Solve for x: 2x2 + 4x + 1 = 0 c a b π₯= β4 Β± β βπ 42 - 4 π2 - 4 π π 2 π
(2) (1) 2 (2) π
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Solve for x: 2x2 + 4x + 1 = 0 a b c π₯= β4 Β± β π₯= β4 Β± β 16 - 8 8 4 4
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Solve for x: 3x2 - 2x - 4 = 0 a b c π₯= Β± β βπ π2 - 4 π π 2 π β(β2) (3)
(-2)2 - 4 (3) (-4) 2 (3) π
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Solve for x: 3x2 - 2x - 4 = 0 a b c π₯= Β± β Β± β π₯= 2 4 + 48 2 52 6 6
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Solve for x: 2x2 - 3x + 6 = 0 a b c Β± β π₯= 2 β(β3) (2) (6) (2)
(-3)2 - 4 (2) (6) 2 (2)
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Solve for x: 2x2 - 3x + 6 = 0 a b c Β± β π₯= 3 9 - 48 4
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Solve for x: 2x2 - 3x + 6 = 0 a b c Β± β Β± β π₯= 4 4 3 3 9 - 48 - 39
No real solutions Β± β 3 9 - 48 Β± β 3 - 39 π₯= 4 4
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