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ELL100: INTRODUCTION TO ELECTRICAL ENGG.
Lecture 4 Course Instructors: J.-B. Seo, S. Srirangarajan, S.-D. Roy, and S. Janardhanan Department of Electrical Engineering, IITD
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Common Signal Waveforms
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Common Signal Waveforms
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Common Signal Waveforms
Battery, Ideal sources Switch Oscillating Switch AC current, many places Caps
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Signal Waveforms (2) Exponential Signals
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Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant
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Signal Waveforms (2) Exponential Signals e = 2.718
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant
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Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant So, after ‘tau’ time an exponential function reduces by ~ 63 %
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Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant So, after ‘tau’ time an exponential function reduces by ~ 63 %
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Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant So, after ‘tau’ time an exponential function reduces by ~ 63 %
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Example 1
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Example 1
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Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL
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Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL
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Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL
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Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution
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Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution
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Signal Waveforms (3) a : Instantaneous value of function
A : Maximum Amplitude t : time variable in seconds T : time for 1 full cycle Period f : frequency cycles/sec or Hertz ω : frequency in radians/sec 2πf α : phase angle/offset angle (radians)
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Signal Waveforms (3) a : Instantaneous value of function
A : Maximum Amplitude t : time variable in seconds T : time for 1 full cycle Period f : frequency cycles/sec or Hertz ω : frequency in radians/sec 2πf α : phase angle/offset angle (radians)
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Signal Waveforms (3) a : Instantaneous value of function
A : Maximum Amplitude t : time variable in seconds T : time for 1 full cycle Period f : frequency cycles/sec or Hertz ω : frequency in radians/sec 2πf α : phase angle/offset angle (radians)
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Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time.
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Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time.
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Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time. As per Sine wave equation, A = 20 A ω = 2πf = 2π (60) = 377 rad/s The positive maximum is reached when (ωt + α) = 0 or any multiple of 2π. Letting (ωt + α) = 0, α = - ωt = -377 * 2 * 10-3 = (-) rad Or α = * (360°/ 2π) = °
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Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time. As per Sine wave equation, A = 20 A ω = 2πf = 2π (60) = 377 rad/s The positive maximum is reached when (ωt + α) = 0 or any multiple of 2π. Letting (ωt + α) = 0, α = - ωt = -377 * 2 * 10-3 = (-) rad Or α = * (360°/ 2π) = ° i = 20 cos (377t – 43.2°)
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Signal Waveforms (4)
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Periodic Waveforms
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Periodic Waveforms (2)
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Periodic Waveforms (2)
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Periodic Waveforms (2)
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Periodic Waveforms (2)
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Periodic Waveforms (2) For sinusoidal wave total Q over full cycle = 0
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Periodic Waveforms (3)
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Periodic Waveforms (3)
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Periodic Waveforms (3)
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Periodic Waveforms (3)
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Periodic Waveforms (3)
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Periodic Waveforms (3)
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Periodic Waveforms (4) Delivering equivalent Energy
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Periodic Waveforms (4) Delivering equivalent Energy + = Ieff
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Periodic Waveforms (4) Delivering equivalent Energy + = Ieff
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Periodic Waveforms (4) = Ieff + Delivering equivalent Energy
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Periodic Waveforms (4) = Ieff + Delivering equivalent Energy
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Periodic Waveforms (5)
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Periodic Waveforms (5)
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Periodic Waveforms (5)
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Periodic Waveforms (5)
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Periodic Waveforms (5) Delivering equivalent Energy + = Ieff
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Periodic Waveforms (5) = Ieff +
Delivering equivalent Energy + = Ieff So for sinosoidal current, the Ieff/DC equivalent = Im = Irms
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