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ELL100: INTRODUCTION TO ELECTRICAL ENGG.

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Presentation on theme: "ELL100: INTRODUCTION TO ELECTRICAL ENGG."— Presentation transcript:

1 ELL100: INTRODUCTION TO ELECTRICAL ENGG.
Lecture 4 Course Instructors: J.-B. Seo, S. Srirangarajan, S.-D. Roy, and S. Janardhanan Department of Electrical Engineering, IITD

2 Common Signal Waveforms

3 Common Signal Waveforms

4 Common Signal Waveforms
Battery, Ideal sources Switch Oscillating Switch AC current, many places Caps

5 Signal Waveforms (2) Exponential Signals

6 Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant

7 Signal Waveforms (2) Exponential Signals e = 2.718
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant

8 Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant So, after ‘tau’ time an exponential function reduces by ~ 63 %

9 Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant So, after ‘tau’ time an exponential function reduces by ~ 63 %

10 Signal Waveforms (2) Exponential Signals
a : Instantaneous value of function A : Maximum Amplitude t : time variable Tau : time constant So, after ‘tau’ time an exponential function reduces by ~ 63 %

11 Example 1

12 Example 1

13 Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL

14 Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL

15 Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL

16 Example 1 Solution Step 1: Calculate VR Step 2: Calculate VL

17 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC

18 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC

19 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC

20 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC

21 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC

22 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution

23 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution

24 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution

25 Example 1 Solution Step 3: Calculate VRL Step 4: Calculate VC Solution

26

27 Signal Waveforms (3) a : Instantaneous value of function
A : Maximum Amplitude t : time variable in seconds T : time for 1 full cycle  Period f : frequency  cycles/sec or Hertz ω : frequency in radians/sec  2πf α : phase angle/offset angle (radians)

28 Signal Waveforms (3) a : Instantaneous value of function
A : Maximum Amplitude t : time variable in seconds T : time for 1 full cycle  Period f : frequency  cycles/sec or Hertz ω : frequency in radians/sec  2πf α : phase angle/offset angle (radians)

29 Signal Waveforms (3) a : Instantaneous value of function
A : Maximum Amplitude t : time variable in seconds T : time for 1 full cycle  Period f : frequency  cycles/sec or Hertz ω : frequency in radians/sec  2πf α : phase angle/offset angle (radians)

30 Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time.

31 Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time.

32 Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time. As per Sine wave equation, A = 20 A ω = 2πf = 2π (60) = 377 rad/s The positive maximum is reached when (ωt + α) = 0 or any multiple of 2π. Letting (ωt + α) = 0, α = - ωt = -377 * 2 * 10-3 = (-) rad Or α = * (360°/ 2π) = °

33 Example 2 A Sinusoidal current with a frequency of 60 Hz reaches a positive maximum of 20 A at t = 2 ms. Write the equation of current as a function of time. As per Sine wave equation, A = 20 A ω = 2πf = 2π (60) = 377 rad/s The positive maximum is reached when (ωt + α) = 0 or any multiple of 2π. Letting (ωt + α) = 0, α = - ωt = -377 * 2 * 10-3 = (-) rad Or α = * (360°/ 2π) = ° i = 20 cos (377t – 43.2°)

34 Signal Waveforms (4)

35 Periodic Waveforms

36 Periodic Waveforms (2)

37 Periodic Waveforms (2)

38 Periodic Waveforms (2)

39 Periodic Waveforms (2)

40 Periodic Waveforms (2) For sinusoidal wave total Q over full cycle = 0

41 Periodic Waveforms (3)

42 Periodic Waveforms (3)

43 Periodic Waveforms (3)

44 Periodic Waveforms (3)

45 Periodic Waveforms (3)

46 Periodic Waveforms (3)

47 Periodic Waveforms (4) Delivering equivalent Energy

48 Periodic Waveforms (4) Delivering equivalent Energy + = Ieff

49 Periodic Waveforms (4) Delivering equivalent Energy + = Ieff

50 Periodic Waveforms (4) = Ieff + Delivering equivalent Energy

51 Periodic Waveforms (4) = Ieff + Delivering equivalent Energy

52 Periodic Waveforms (5)

53 Periodic Waveforms (5)

54 Periodic Waveforms (5)

55 Periodic Waveforms (5)

56 Periodic Waveforms (5) Delivering equivalent Energy + = Ieff

57 Periodic Waveforms (5) = Ieff +
Delivering equivalent Energy + = Ieff So for sinosoidal current, the Ieff/DC equivalent = Im = Irms


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