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Welcome to Interactive Chalkboard
Algebra 1 Interactive Chalkboard Copyright © by The McGraw-Hill Companies, Inc. Send all inquiries to: GLENCOE DIVISION Glencoe/McGraw-Hill 8787 Orion Place Columbus, Ohio Welcome to Interactive Chalkboard
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Splash Screen
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Lesson 11-4 The Pythagorean Theorem Lesson 11-5 The Distance Formula
Contents
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Example 1 Find the Length of the Hypotenuse
Example 2 Find the Length of a Side Example 3 Pythagorean Triples Example 4 Check for Right Triangles Lesson 4 Contents
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Find the length of the hypotenuse of a right triangle if and
Pythagorean Theorem and Simplify. Take the square root of each side. Use the positive value. Answer: The length of the hypotenuse is 30 units. Example 4-1a
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Find the length of the hypotenuse of a right triangle if and
Answer: 65 units Example 4-1b
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Find the length of the missing side.
In the triangle, and units. Pythagorean Theorem and Evaluate squares. Subtract 81 from each side. Use a calculator to evaluate . Use the positive value. Answer: To the nearest hundredth, the length of the leg is units. Example 4-2a
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Find the length of the missing side.
Answer: about units Example 4-2b
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Multiple-Choice Test Item What is the area of triangle XYZ?
A 94 units2 B 128 units2 C 294 units2 D 588 units2 Read the Test Item The area of the triangle is In a right triangle, the legs form the base and height of the triangle. Use the measures of the hypotenuse and the base to find the height of the triangle. Example 4-3a
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The height of the triangle is 21 units.
Solve the Test Item Step 1 Check to see if the measurements of this triangle are a multiple of a common Pythagorean triple. The hypotenuse is units and the leg is units. This triangle is a multiple of a (3, 4, 5) triangle. The height of the triangle is 21 units. Example 4-3a
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Step 2 Find the area of the triangle.
Area of a triangle and Simplify. Answer: The area of the triangle is 294 square units. Choice C is correct. Example 4-3a
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Multiple-Choice Test Item What is the area of triangle RST?
A 764 units2 B 480 units2 C 420 units2 D 384 units2 Answer: D Example 4-3b
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Answer: Since , the triangle is not a right triangle.
Determine whether the side measures of 7, 12, 15 form a right triangle. Since the measure of the longest side is 15, let , and Then determine whether Pythagorean Theorem and Multiply. Add. Answer: Since , the triangle is not a right triangle. Example 4-4a
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Answer: Since the triangle is a right triangle.
Determine whether the side measures of 27, 36, 45 form a right triangle. Since the measure of the longest side is 45, let and Then determine whether Pythagorean Theorem and Multiply. Add. Answer: Since the triangle is a right triangle. Example 4-4b
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Determine whether the following side measures form right triangles.
b. 12, 22, 40 Answer: right triangle Answer: not a right triangle Example 4-4b
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End of Lesson 4
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Example 1 Distance Between Two Points
Example 2 Use the Distance Formula Example 3 Find a Missing Coordinate Lesson 5 Contents
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Find the distance between the points at (1, 2) and (–3, 0).
Distance Formula and Simplify. Evaluate squares and simplify. Answer: or about 4.47 units Example 5-1a
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Find the distance between the points at (5, 4) and (0, –2).
Answer: Example 5-1b
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Biathlon Julianne is sighting her rifle for an upcoming biathlon competition. Her first shot is 2 inches to the right and 7 inches below the bull’s-eye. What is the distance between the bull’s-eye and where her first shot hit the target? Draw a model of the situation on a coordinate grid. If the bull’s-eye is at (0, 0), then the location of the first shot is (2, –7). Use the Distance Formula. Example 5-2a
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Example 5-2a
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Answer: The distance is or about 7.28 inches.
Distance Formula and Simplify. or about 7.28 inches Answer: The distance is or about 7.28 inches. Example 5-2a
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Horseshoes Marcy is pitching a horseshoe in her local park
Horseshoes Marcy is pitching a horseshoe in her local park. Her first pitch is 9 inches to the left and 3 inches below the pin. What is the distance between the horseshoe and the pin? Answer: Example 5-2b
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Find the value of a if the distance between the points at (2, –1) and (a, –4) is 5 units.
Distance Formula Let and . Simplify. Evaluate squares. Simplify. Example 5-3a
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Subtract 25 from each side.
Square each side. Subtract 25 from each side. Factor. Zero Product Property or Solve. Answer: The value of a is –2 or 6. Example 5-3a
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Find the value of a if the distance between the points at (2, 3) and (a, 2) is
Answer: –4 or 8 Example 5-3b
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End of Lesson 5
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