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Section 6.1 Slope Fields
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Differential Equations
An equation like ππ¦ ππ₯ =π₯ π π¦ is called a differential equation because it contains a derivative. If you find all of the functions y that satisfy the differential equation, then you have solved the differential equation.
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Slope field A slope field for the first order differential equation ππ¦ ππ₯ =π π₯, π¦ is a plot of short line segments with slopes f(x, y) for a lattice of points (x, y) in the plane. A slope field can give you a general idea of what the solution to the differential equation looks like.
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Indefinite integrals Depending on where you place your pencil and begin drawing, the slope field can provide many different graphs that satisfy a particular differential equation. We have seen this before with indefinite integrals. The indefinite integral is the set of all antiderivatives to a function f(x): π π₯ ππ₯=πΉ π₯ +πΆ
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Find the following indefinite integralsβ¦ 1. 4π₯ 3 dx
Examples Find the following indefinite integralsβ¦ π₯ 3 dx π₯ π₯ β cos π₯ dx Adding a constant does not change the derivative because it does not affect the value of the slope at a given value x.
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Initial value problems
Often the goal is to find a particular equation f(x) that both satisfies the differential equation and a given initial condition. The initial condition is a value of f for one value of x. Graphically, it gives you a place to start in your slope field. Analytically it allows you to solve for the value of the constant in your indefinite integral.
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Example Solve the initial value problemβ¦. ππ¦ ππ₯ = 6π₯ 2 β12π₯+7, π¦ β2 =8
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Initial value examples
Solve the initial value problem. 1. π β²β² π₯ = π₯ β3/2 , π β² 4 =2, π 0 =0. 2. π β²β² π₯ = sin π₯ , π β² 0 =1, π 0 =6.
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Physics application A ball is thrown upward with an initial velocity of 64 feet per second from an initial height of 80 feet. (a) Find the position function giving the height h as a function of time t. (b) When does the ball hit the ground? (-32 ft/sec2 is the acceleration due to gravity.)
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