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Exponential & Log Functions

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Presentation on theme: "Exponential & Log Functions"β€” Presentation transcript:

1 Exponential & Log Functions
Unit 13 Day 4

2 Warm up! Solve: π‘₯+2 βˆ— 216 3π‘₯ = 1 216 A total of $12,000 is invested at an annual rate of 9%. Find the balance after 5 years if it is compounded a)Quarterly b)Monthly c)Continuously. Describe the transformations and graph: 𝑦= π‘₯βˆ’3 βˆ’2 𝑓 π‘₯ =βˆ’ π‘™π‘œπ‘” 3 π‘₯βˆ’2 +4 X=-1/6 A=$18, A=$18, A=$18,819.75 a=2, b=1, h=3, k=0 a=-1, b=1, h=2, k=4

3 Warm up answers 𝑦= π‘₯βˆ’3 βˆ’2 𝑓 π‘₯ =βˆ’ π‘™π‘œπ‘” 3 π‘₯βˆ’2 +4

4 Think-Ink-Pair-Share
How would you solve… 9 π‘₯ =49

5 Changing Forms To change between exponential and logarithmic forms…

6 Changing Forms Examples
π‘™π‘œπ‘” 4 2=π‘₯ 4 π‘₯ =2 9 π‘₯ =3 π‘™π‘œπ‘” 9 3=π‘₯ ln π‘₯ =4 𝑒 4 =π‘₯

7 You Try! =8 π‘™π‘œπ‘” 4 8= 3 2 π‘™π‘œπ‘” =βˆ’2 4 βˆ’2 = 1 16

8 Logarithmic Properties
loga1 = 0 (a0=1) Inverse Property loga ax = x loga a = 1 (a1=a) One-to-one property loga x = loga y then x = y also applies to exponential functions ax = ay then x = y

9 Using the Properties Evaluate the following expressions 𝑙𝑛 𝑒 2 =
𝑙𝑛 𝑒 2 = 2 π‘™π‘œπ‘” = -1 ln 𝑒 3π‘₯+4𝑦 = 3x +4y

10 You Try! Evaluate the following expressions 𝑒 𝑙𝑛π‘₯ = π‘™π‘œπ‘” 5 5 3 =
π‘™π‘œπ‘” = 1.5 6 π‘™π‘œπ‘” 6 20𝑑 = 20t

11 Solving Exponential & Logarithmic Equations Example 1
Solve for x π‘™π‘œπ‘” 3 π‘₯=4 Change forms 3 4 =π‘₯ (on non-calculator part of test, this is an acceptable answer) π‘₯=81

12 Solving Exponential & Logarithmic Equations Example 2 & 3
Solve for x ln π‘₯ =βˆ’3 Use the inverse property π‘₯= 𝑒 βˆ’3 (exact answer/form) x=0.050 𝑒 π‘₯ =7 π‘₯= ln 7 π‘œπ‘Ÿ 1.95

13 Solving Exponential & Logarithmic Equations Example 4
Solve for x ln π‘₯ βˆ’ ln 3 =0 ln π‘₯ = ln (3) π‘₯=3

14 Solving Exponential & Logarithmic Equations Example 5
How would you solve? 𝑒 2π‘₯ βˆ’3 𝑒 π‘₯ +2=0 πΉπ‘Žπ‘π‘‘π‘œπ‘Ÿ! 𝑒 π‘₯ βˆ’1 𝑒 π‘₯ βˆ’2 =0 𝑒 π‘₯ βˆ’1 = 𝑒 π‘₯ βˆ’2 =0 𝑒 π‘₯ = 𝑒 π‘₯ =2 π‘₯= ln 1 =0 π‘₯= ln 2 =0.693

15 You Try! Solve for x. π‘™π‘œπ‘” 2 π‘₯+3 βˆ’ π‘™π‘œπ‘” 2 3π‘₯βˆ’4 =0
π‘™π‘œπ‘” 2 π‘₯+3 βˆ’ π‘™π‘œπ‘” 2 3π‘₯βˆ’4 =0 7/2 or 3.5 log π‘₯=3 *remember log x = log10x x=1000 π‘™π‘œπ‘” 2 π‘₯ 2 +2π‘₯ = π‘™π‘œπ‘” 2 π‘₯+6 x=-3 x=2 𝑒 2π‘₯ βˆ’3 𝑒 π‘₯ +2=0 x=ln4 2π‘₯𝑙𝑛 π‘₯ +π‘₯=0 π‘₯=0 π‘₯=𝑒 βˆ’1

16 Solving Exponential & Logarithmic Equations Example 5Extraneous Solutions
Extraneous solutions occur when a solution is x = ln(c) and c ≀ 0 Solve for x 𝑒 2π‘₯ βˆ’3 𝑒 π‘₯ βˆ’4=0 𝑒 π‘₯ +1 𝑒 π‘₯ βˆ’4 =0 𝑒 π‘₯ +1 = 𝑒 π‘₯ βˆ’4 =0 𝑒 π‘₯ =βˆ’ 𝑒 π‘₯ =4 π‘₯= ln βˆ’ 𝒙= π₯𝐧 πŸ’ Extraneous!

17 Applications Example 1 If you invest $500 at 6.75% compounded continuously, how long until it doubles? 𝐴=𝑃 𝑒 π‘Ÿπ‘‘ 1000=500 𝑒 𝑑 2= 𝑒 (𝑑) ln 2=0.0675𝑑 t=10.27 years

18 You Try! Applications If you invest $1000 for 7 years and now have $ , what was your interest rate (compounded continuously)? r = 5.99%

19 Exit Ticket On a scale of 1 to 5 with 1 being β€œwere you speaking English?” 5 being β€œI totally got this!” How would you rate your understanding of today’s lesson? Explain in a few words.


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