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Good morning Happy Friday.

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Presentation on theme: "Good morning Happy Friday."β€” Presentation transcript:

1 Good morning Happy Friday

2 Exponentials Initial value Growth or decay factor
Re-call exponential form is 𝑦=π‘Žβˆ— 𝑏 π‘₯ , aβ‰ 0, and b>0 π‘Ž represents: Initial value 𝑏 represent the Growth or decay factor

3 Is it growth or decay? For each I.D. growth or decay, initial value and growth/decay factor: 1) 𝑦=8 3 π‘₯ 2) 𝑦=2 1 2 π‘₯ 3) 𝑦= π‘₯ 4) 𝑦= π‘₯

4 Answers Growth, a= 8 and factor is b= 3
Decay, a = 2 and factor is b= Β½ Growth a= 1/3 and factor is b=2 Decay a= and factor is b=0.25

5 Good Morning Exponentials

6 Sketching a graph Make a table of values: 𝑦= 3 π‘₯ x y -1 1 2 3 1/3 1 3
1 2 3 1/3 1 3 9 27

7 Plot values to get the graph

8 Finding equations Given points: 0,1 π‘Žπ‘›π‘‘ 2, 36 Find the equations by substituting points in and solving for β€œa” and β€œb”

9 By Hand Use equation 𝑦=π‘Žβˆ— 𝑏 π‘₯ to solve for a. when x=0 then y=1.
So 1=π‘Žβˆ— 𝑏 0 well 𝑏 0 =1 so π‘Ž=1 Now use second point and solve for b. 36=1βˆ— 𝑏 2 So 𝑏=Β±6 but we know 𝑏>0 so B=6

10 SO our equation is 𝑦=1βˆ— 6 π‘₯ You try: write the exponential from the point given 0,1 π‘Žπ‘›π‘‘ 2, 49 0, 3 π‘Žπ‘›π‘‘ 2, 12 1, (4, 72)

11 Solutions 𝑦= 5 π‘₯ 𝑦=3 βˆ— 2 π‘₯ Hmmm how do we do that one by hand?
We get stuck with 9=π‘Žβˆ— 𝑏 1 π‘Žπ‘›π‘‘ 72=π‘Žβˆ— 𝑏 4

12 Steps to do it in the calculator given points/ data
Stat β†’ Edit β†’ π‘’π‘›π‘‘π‘’π‘Ÿ π‘‘π‘Žπ‘‘π‘Ž 𝑖𝑛 𝐿 1 π‘Žπ‘›π‘‘ 𝐿 2 π‘†π‘‘π‘Žπ‘‘ β†’πΆπ‘Žπ‘™π‘β†’πΈπ‘₯𝑝𝑅𝑒𝑔 𝑦=π‘Žβˆ— 𝑏 π‘₯ π‘Ž=π‘ π‘œπ‘šπ‘’ π‘›π‘’π‘šπ‘π‘’π‘Ÿ 𝑏=π‘ π‘œπ‘šπ‘’ π‘›π‘’π‘šπ‘π‘’π‘Ÿ

13 Recall parent function Transformations
If we had the function 𝑦= π‘₯ 2 How did we describe the transformation(s): 𝑦= π‘₯βˆ’3 2 𝑦= π‘₯ 2 +4 𝑦=βˆ’ π‘₯ 2 𝑦= βˆ’π‘₯ 2

14 The same translations apply to exponential functions
We can use the characteristic point we know for exponentials to help use I.D. graphs The point is 0,1

15 Examples 𝑦= 2 π‘₯ π‘π‘œπ‘–π‘›π‘‘ π‘œπ‘› π‘‘β„Žπ‘’ π‘”π‘Ÿπ‘Žπ‘β„Ž 𝑖𝑠 0,1 π‘Žπ‘›π‘‘ 2,4 If we transform the graph: 𝑦= 2 π‘₯+1 the graph has been shifted one unit to the left so instead of 0,1 π‘‘β„Žπ‘’ π‘π‘œπ‘–π‘›π‘‘ 𝑖𝑠 π‘›π‘œπ‘€ βˆ’1, 1

16 Try it 𝑦= 2 π‘₯ Describe the translation(s) use the point 0,1 as a reference. 𝑦= 2 π‘₯ +3 𝑦=βˆ’ 2 π‘₯ 𝑦= 2 βˆ’π‘₯ 𝑦= 2 π‘₯βˆ’3 +4


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