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Good morning Happy Friday
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Exponentials Initial value Growth or decay factor
Re-call exponential form is π¦=πβ π π₯ , aβ 0, and b>0 π represents: Initial value π represent the Growth or decay factor
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Is it growth or decay? For each I.D. growth or decay, initial value and growth/decay factor: 1) π¦=8 3 π₯ 2) π¦=2 1 2 π₯ 3) π¦= π₯ 4) π¦= π₯
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Answers Growth, a= 8 and factor is b= 3
Decay, a = 2 and factor is b= Β½ Growth a= 1/3 and factor is b=2 Decay a= and factor is b=0.25
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Good Morning Exponentials
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Sketching a graph Make a table of values: π¦= 3 π₯ x y -1 1 2 3 1/3 1 3
1 2 3 1/3 1 3 9 27
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Plot values to get the graph
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Finding equations Given points: 0,1 πππ 2, 36 Find the equations by substituting points in and solving for βaβ and βbβ
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By Hand Use equation π¦=πβ π π₯ to solve for a. when x=0 then y=1.
So 1=πβ π 0 well π 0 =1 so π=1 Now use second point and solve for b. 36=1β π 2 So π=Β±6 but we know π>0 so B=6
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SO our equation is π¦=1β 6 π₯ You try: write the exponential from the point given 0,1 πππ 2, 49 0, 3 πππ 2, 12 1, (4, 72)
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Solutions π¦= 5 π₯ π¦=3 β 2 π₯ Hmmm how do we do that one by hand?
We get stuck with 9=πβ π 1 πππ 72=πβ π 4
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Steps to do it in the calculator given points/ data
Stat β Edit β πππ‘ππ πππ‘π ππ πΏ 1 πππ πΏ 2 ππ‘ππ‘ βπΆπππβπΈπ₯ππ
ππ π¦=πβ π π₯ π=π πππ ππ’ππππ π=π πππ ππ’ππππ
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Recall parent function Transformations
If we had the function π¦= π₯ 2 How did we describe the transformation(s): π¦= π₯β3 2 π¦= π₯ 2 +4 π¦=β π₯ 2 π¦= βπ₯ 2
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The same translations apply to exponential functions
We can use the characteristic point we know for exponentials to help use I.D. graphs The point is 0,1
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Examples π¦= 2 π₯ πππππ‘ ππ π‘βπ ππππβ ππ 0,1 πππ 2,4 If we transform the graph: π¦= 2 π₯+1 the graph has been shifted one unit to the left so instead of 0,1 π‘βπ πππππ‘ ππ πππ€ β1, 1
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Try it π¦= 2 π₯ Describe the translation(s) use the point 0,1 as a reference. π¦= 2 π₯ +3 π¦=β 2 π₯ π¦= 2 βπ₯ π¦= 2 π₯β3 +4
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