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Published byTamsin Martin Modified over 6 years ago
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Points of intersection of linear graphs an quadratic graphs
Quadratic Equations Points of intersection of linear graphs an quadratic graphs
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Find the solutions for y = x2 – 2x + 2 and y = 7
Quadratic Equations Finding solutions Find the solutions for y = x2 – 2x + 2 and y = 7 We draw the quadratic curve y = x2 – 2x + 2 and the line y = 7 The solutions are where the quadratic curve crosses the straight line y = 7
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Quadratic Equations Solutions are x = and x = 3.45 y = 7
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Now review the solutions to x2 – 2x – 5 = 0
Quadratic Equations Now review the solutions to x2 – 2x – 5 = 0 Solutions are x = and x = 3.45 Is this a coincidence?
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The solutions for y = x2 – 2x + 2 and y = 7 are where x2 – 2x + 2 = 7
Quadratic Equations The solutions for y = x2 – 2x + 2 and y = 7 are where x2 – 2x + 2 = 7 Rearrange the equation by subtracting 7 from both sides x2 – 2x – 5 = 0
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Quadratic Equations y = x2 – 2x + 2 -7 y = x2 – 2x - 5 If we rearrange the equation we find that we have the same solutions because the process of rearranging translates (moves) the graph
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This applies to the intersections of other lines
Quadratic Equations This applies to the intersections of other lines Show where the curve of y = x2 + 2x – 4 crosses the line y = x - 3 Solutions are x = -1.6 x = 0.6
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The solutions for y = x2 – 2x - 4 and y = x - 3
Quadratic Equations The solutions for y = x2 – 2x - 4 and y = x - 3 are where x2 – 2x - 4 = x - 3 Rearrange the equation - x from both sides x2 –3x - 4 = - 3 + 3 to both sides x2 –3x - 1 = 0 The solutions to this will be the same as the solutions to x2 – 2x - 4 = x - 3
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