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Chapter 8 Acid-Base Equilibria
8-1 Brønsted-Lowry Acids and Bases 8-2 Water and the pH Scale 8-3 The Strengths of Acids and Bases 8-4 Equilibria Involving Weak Acids and Bases 8-5 Buffer Solutions 8-6 Acid-Base Titration Curves 8-7 Polyprotic Acids 8-8 Lewis Acids and Bases 11/24/2018 OFB Chapter 8 1
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Acid and Base Definitions
Arrhenius (Section 4.3) Acids are H+ donors Bases are OH- donors Broadened Definition (Section 4.3) Acids are substances that increase [H+] Bases are substances that increase [OH-] Brønsted-Lowry (Section 8.1) Lewis (Section 8.8) 11/24/2018 OFB Chapter 8
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Chapter 8 Acid-Base Equilibria
Brønsted-Lowry Acids Bases Conjugate Base - Conjugate Acid 11/24/2018 OFB Chapter 8 2
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Brønsted-Lowry Acids and Bases
Acid-Base Equilibria Brønsted-Lowry Acids and Bases A Brønsted-Lowry acid is a substance that can donate a hydrogen ion. A Brønsted-Lowry base is a substance that can accept a hydrogen ion. In the Brønsted-Lowry Acid and Base concept, acids and bases occur as conjugate acid-base pairs. 11/24/2018 OFB Chapter 8
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Conjugate Base - subtract an H+ from the acid
Conjugate Acid add H+ to the base Examples is the conjugate base of H2O is the conjugated base of H3O+ (called the hydronium ion) is the conjugated acid of OH- (or shown as H+) is the conjugate acid of H2O 11/24/2018 OFB Chapter 8
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Conjugate Base - subtract an H+ from the acid
Conjugate Acid add H+ to the base H2O - H+ + H+ OH- conjugate base of H2O conjugate acid of H2O H3O+ Water is the conjugate acid of OH- Water is the conjugate base of H3O+ Hydroxide ion Hydronium ion 11/24/2018 OFB Chapter 8
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CH3CO2H + H2O ↔ H3O+ + CH3CO2- Pairs 1 2 2 1
Acetic Acid Acetate Ion Pairs acid base acid base Point of View #1 acid base Conjugate acid of H2O Conjugate base of CH3CO2H CH3CO2H + H2O ↔ H3O+ + CH3CO2- Point of View #2 acid base Conjugate base of H3O+ Conjugate acid of CH3CO2- CH3CO2H + H2O ↔ H3O+ + CH3CO2- 11/24/2018 OFB Chapter 8
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Autoionization of H2O H2O + H2O ↔ H3O+ + OH- Pairs 1 2 2 1
acid base acid base Point of View #1 acid base Conjugate acid of H2O #2 Conjugate base of H2O #1 H2O + H2O ↔ H3O+ + OH- # 1 # 2 Point of View #2 acid base Conjugate base of H3O+ Conjugate acid of OH- H2O + H2O ↔ H3O+ + OH- 11/24/2018 OFB Chapter 8
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Exercise 8-1: Trimethylamine (C3H9N) is a soluble weak base with a foul odor (it contributes to the smell of rotten fish). Write the formula of its conjugate acid. “… the formula of a conjugate acid is obtained by adding H+ to the formula of the base.” 11/24/2018 OFB Chapter 8
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Nomenclature When H+ is hydrated it is H3O+ and called a hydronium ion. Often H3O+ is written in a simpler notation H+ + 111.7° 11/24/2018 OFB Chapter 8
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1.) Water in NH3 serves as an acid
Amphoterism - an ion or molecule can act as an acid or base depending upon the reaction conditions 1.) Water in NH3 serves as an acid H2O + NH3 ↔ NH OH- 2.) Water in acetic acid serves as a base H2O + CH3CO2H ↔ H3O CH3CO2- 11/24/2018 OFB Chapter 8
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H2SO4 + CH3CO2H ↔ CH3CO2H2+ + HSO4-
3.) Acetic Acid is also amphoteric, if in the presence of a strong acid serves as a base H2SO4 + CH3CO2H ↔ CH3CO2H HSO4- Amphoterism - an ion or molecule can act as an acid or base depending upon the reaction conditions 11/24/2018 OFB Chapter 8
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Water Autoionization of water: 2 H2O(l) H3O+(aq) + OH-(aq)
[H3O+][OH-] [H2O]2 KW = 1.0 (at 25oC) 11/24/2018 OFB Chapter 8
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Strong Acids and Bases A strong acid is one that reacts essentially completely with water to produce H3O+(aq). Hydrochloric acid (HCl) is a strong acid: HCl (aq) + H2O(l) H3O+(aq) + Cl-(aq) (reaction essentially complete) Dissolving 0.10 mol of HCl in enough water to make 1.0 L of solution gives a final concentration of 0.10 M for H3O+(aq). [H3O+][OH-] = KW 11/24/2018 OFB Chapter 8
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A strong base is one that reacts essentially completely with water to produce OH-(aq) ions.
Strong Acids and Bases Sodium hydroxide (NaOH) is a strong base: Others are NH2- (amide ion) and H- (Hydride ion) NaOH(s) Na+(aq) + OH-(aq) (reaction essentially complete) Dissolving 0.10 mol of NaOH in enough water to make 1.0 L of solution gives a final concentration of 0.10 M for OH-(aq). [H3O+][OH-] = KW 11/24/2018 OFB Chapter 8
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The pH Function pH = -log10[H3O+] pH < 7 acidic solution
[H3O+] > [OH-] pH = 7 neutral solution [H3O+] = [OH-] pH > 7 basic solution [H3O+] < [OH-] 11/24/2018 OFB Chapter 8
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The pH Function EXAMPLE 8-3
Calculate the pH (at 25oC) of an aqueous solution that has an OH-(aq) concentration of 1.2 10-6 M. 11/24/2018 OFB Chapter 8
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If converting from pH to [H+]
pH = -log10[H3O+] If converting from pH to [H+] [H+] = 10 -pH = 10 -X 11/24/2018 OFB Chapter 8
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Recall [H3O+][OH-] = KW = 10 -14 pH + pOH = pKw = 14 11/24/2018
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The pH Function Exercise page 8-4:
Calculate [H3O+] and [OH-] in saliva that has a pH of 6.60 at 25oC. 11/24/2018 OFB Chapter 8
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Strengths of Acids and Bases
Strong acids (completely ionized in water, i.e., 100%) HI HBr HClO4 (perchloric acid) HCl HClO3 (chloric acid) H2SO4 HNO3 HA + H2O ↔ H3O+ + A – HA = generic acid 11/24/2018 OFB Chapter 8
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Table 8-2 Scale of pKa -11 To +14 Known Scale of pKa -11 To +50
E.g., Acetone = 19, methane = 48, ethane = 50 11/24/2018 OFB Chapter 8
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Strengths of Acids and Bases
B + H2O ↔ BH+ + OH- B = Base Kb is the Basicity constant 11/24/2018 OFB Chapter 8
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B + H2O ↔ BH+ + OH- BH+ + H2O ↔ B + H3O+ Kb is the Basicity constant
B = Base Kb is the Basicity constant BH+ + H2O ↔ B + H3O+ B = Base Ka is the Acidity constant 11/24/2018 OFB Chapter 8
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B + H2O ↔ BH+ + OH- BH+ + H2O ↔ B + H3O+ B = Base B = Base 11/24/2018
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Chapter 8 Acid-Base Equilibria
Base Strength strong acids have weak conjugate bases weak acids have strong conjugate bases The strength of a base is inversely related to the strength of its conjugate acid; the weaker the acid, the stronger its conjugate base, and vice versa pKa + pKb = pKw 11/24/2018 OFB Chapter 8 3
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HIn(aq) + H2O(l) H3O+(aq) + In-(aq)
Indicators (denoted by In) A soluble compound, generally an organic dye, that changes its color noticeably over a fairly short range of pH. Typically, a weak organic acid that has a different color than its conjugate base. HIn(aq) + H2O(l) H3O+(aq) + In-(aq) [H3O+][In-] [HIn] = Ka 11/24/2018 OFB Chapter 8
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Methyl Red Bromothymol blue Phenolphtalein 11/24/2018 OFB Chapter 8
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Equilibria Involving Weak
Acids and Bases Weak acids Ka < 1 i.e., pKa > 0 H3O+ (hydronium ion) Ka = 1 pKa =0 HA + H2O ↔ H3O+ + A- HA is a weak acid, Ka < 1 or pKa > 1 11/24/2018 OFB Chapter 8
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Problem: (a) Calculate pH and (b) the fraction of CH3CO2H ionized at equilibrium. Assume 1.0M CH3CO2H initially CH3CO2H + H2O ↔ H3O+ + CH3CO2- Init. conc. ∆ conc. Equil. conc. 11/24/2018 OFB Chapter 8
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Assume that y is small (less than 5% of the initial conc.)
A trick to solving: Assume that y is small (less than 5% of the initial conc.) 11/24/2018 OFB Chapter 8
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(b) Fraction CH3CO2H ionized at equilibrium
Problem: (a) Calculate pH and (b) the fraction of CH3CO2H ionized at equilibrium. Assume 1.0M CH3CO2H initially CH3CO2H + H2O ↔ H3O+ + CH3CO2- (b) Fraction CH3CO2H ionized at equilibrium 11/24/2018 OFB Chapter 8
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1 Weak Bases Similarly NH3 acts as a weak base in H2O Kb = 1.8 x 10-5
H20 + NH3 ↔ NH4+ + OH- acid1 base2 acid2 base1 1 11/24/2018 OFB Chapter 8
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As before, you can calculate a pH at equilibrium. Assume 0
As before, you can calculate a pH at equilibrium. Assume 0.01M NH3 initially. Calculate the pH of the resulting solution H20 + NH3 ↔ NH OH- Init. conc. ∆ conc. Equil. conc. 11/24/2018 OFB Chapter 8
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As before, you can calculate a pH at equilibrium. Assume 0
As before, you can calculate a pH at equilibrium. Assume 0.01M NH3 initially. Calculate the pH of the resulting solution 11/24/2018 OFB Chapter 8
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Other salts behave similarly, NH4Cl and AlCl3 give acid solutions.
Hydrolysis is a term applied to reactions of aquated ions that change the pH from 7 When NaCl is placed in water, the resulting solution is observed to be neutral (pH = 7) However when sodium acetate (NaC2H3O2) is dissolved in water the resulting solution is basic Other salts behave similarly, NH4Cl and AlCl3 give acid solutions. These interactions between salts and water are called hydrolysis 11/24/2018 OFB Chapter 8 3
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It is still a Brønsted-Lowry Acid and Base Reaction
Despite the special term, hydrolysis, there is no reason to treat hydrolysis in a special manner. It is still a Brønsted-Lowry Acid and Base Reaction 11/24/2018 OFB Chapter 8
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Example problem: Suppose a 0.1 mole solution sodium acetate is dissolved in 1 liter of water. What is the pH of the solution? Init. conc. ∆ conc. Equil. conc. Find Kb Find [OH-] Find [H+] Find pH 11/24/2018 OFB Chapter 8
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Ka x Kb = Kw Example problem: What is the pH of the solution?
CH3CO2- + H2O ↔ CH3CO2H + OH- Init. conc. 0.1M 0 ~0 ∆ conc. - y + y y Equil. conc. 0.1– y y y Ka x Kb = Kw Find Kb Find [OH-] Find [H+] Find pH 11/24/2018 OFB Chapter 8
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Anions Cations Raise pH Lower pH Non-Hyrolyzed Ions (a few)
Hydrolysis of Result Anions Cations Raise pH Lower pH Non-Hyrolyzed Ions (a few) 7 Anions, not hydrolyzed Cl -, Br -, I -, HSO4-, NO3-, ClO3-, ClO4- 10 Cations, not hydrolyzed Li+, Na+, K+, Rb+, Sc+, Mg++, Ca++, Sr++, Ba++, Ag+ 11/24/2018 OFB Chapter 8
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Anions Cations Raise pH Lower pH
Hydrolysis of Result Anions Cations Raise pH Lower pH Can predict pH of some salts (relative pH) Na3PO4 is basic (a non hydrolyzed cation and a hydrolyzed anion) FeCl3 is acidic (a hydrolyzed cation and a non hydrolyzed anion) 11/24/2018 OFB Chapter 8
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Chapter 8 Acid-Base Equilibria
Buffer Solutions: important in biochemical and physiological processes Organisms (and humans) have built-in buffers to protect them against large changes in pH. Buffers any solutions that maintain an approximately constant pH despite small additions of acids or bases 11/24/2018 OFB Chapter 8 3
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Death = 7.0 < pH > 7.8 = Death
Buffers any solutions that maintain an approximately constant pH despite small additions of acids or bases Human blood (pH=7.4) is maintained by a combination of CO3-2, PO4-3 and protein buffers, which accept H+ Death = 7.0 < pH > 7.8 = Death How Do Buffers Work? 11/24/2018 OFB Chapter 8
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[H+] depends on Ka and the ratio of acid to salt.
How Do Buffers Work? HA + H2O ↔ H3O+ + A – HA = generic acid [H+] depends on Ka and the ratio of acid to salt. Thus if both conc. HA and A- are large then small addictions of acid or base don’t change the ratio much 11/24/2018 OFB Chapter 8
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H+ depends on Ka and the ratio of acid to salt.
HA + H2O ↔ H3O+ + A – H+ depends on Ka and the ratio of acid to salt. Thus if both conc. HA and A- are large then small addictions of acid or base don’t change the ratio much Try Example 8-11 11/24/2018 OFB Chapter 8
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Extremely important for Organic Chemistry
8-8 Lewis Acids Extremely important for Organic Chemistry Recall from Chapter 3 that main group elements in a molecule are surrounded by 8 electrons (the Octet Rule). Hydrogen by 2 electrons Carbon is 6C or 1s2 2s2 2p2 Hydrogen is 1H or 1s1 11/24/2018 OFB Chapter 8
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Lewis Structures Covalent bonds 11/24/2018 OFB Chapter 8
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Lewis Structures Lone pair 11/24/2018 OFB Chapter 8
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Lewis Structures Electron deficient 11/24/2018 OFB Chapter 8
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Chapter 8 Acid-Base Equilibria
Lewis Acids-Bases Lewis Acid is any species that accepts electron pairs Called electrophiles (electron seeking) e.g., Boron, Al, Group III elements BF3, Mg2+, H+, H3O+ BH3, SnCl4, CH3+, AlCl3, HCl 11/24/2018 OFB Chapter 8 4
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Chapter 8 Acid-Base Equilibria
Lewis Acids-Bases Lewis Base is any species that donates electrons through coordination to its lone pair Called Nucleophiles (nucleus seeking) e.g., Group V, VI, VII elements Br -1, Cl -1, F -1, H -1, HO -1, :NH3, H2O:: 11/24/2018 OFB Chapter 8 4
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