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Solving Systems of Equations by Elimination

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Presentation on theme: "Solving Systems of Equations by Elimination"— Presentation transcript:

1 Solving Systems of Equations by Elimination
Teacher Twins©2014

2 Warm Up (4, -1) (8, -1) (5, -8) Solve each system by substitution.
4x + 5y = 11 y = 3x – 13 x = -2y + 6 6x – 8y = 56 y = -4x + 12 y = -2x + 2 (4, -1) (8, -1) (5, -8)

3 Solving Systems of Equations by Elimination

4 Elimination Using Addition

5 Solve the system by elimination. 5x + 3y = 12 -4x – 3y = 24
To do elimination you must have opposites. In this problem the 3y and -3y are opposites. x = 36 x = 36 Add the equations together. 5x + 3y = 12 5(36) + 3y = 12 y = 12 y = -56 Find the y value by using one of the equations. Answer – ( 36, -56)

6 Try on your own. -4x + 3y = -3 4x – 5y = 5 (0, -1)

7 Solve the system by elimination. 7x + 3y = -6 7x – 2y = -31
To do elimination you must have opposites. In this problem the 7x and 7x are not opposites. You must make them opposites by multiplying one of the equations by -1 (or subtracting the equations). 7x + 3y = -6 -7x + 2y = 31 Multiplied by -1 y = 25 y = 5 Find the x value by using one of the equations. 7x + 3y = -6 7x + 3(5) = -6 x = -3 Answer – (-3, 5)

8 Try on your own 6x – 3y = 27 2x – 3y = 11 (4, -1)

9 Closure (-3, 1) Solve the system by elimination. -4x + 5y = 17


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