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4*6 Forces Acting During Acceleration: Apparent Weight on a Roller Coaster WDYS??? (p406) . WDYT??? Your weight (does/does not) change when you are riding.

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Presentation on theme: "4*6 Forces Acting During Acceleration: Apparent Weight on a Roller Coaster WDYS??? (p406) . WDYT??? Your weight (does/does not) change when you are riding."— Presentation transcript:

1 4*6 Forces Acting During Acceleration: Apparent Weight on a Roller Coaster
WDYS??? (p406) . WDYT??? Your weight (does/does not) change when you are riding a roller coaster. If you were sitting on a scale, it (would/would not) give different readings at different places on the roller coaster.

2 4*6 NOTES: (p410-415) Forces Acting During Acceleration
Using Newton’s 1st and 2nd Law to Explain Forces Acting During Constant Speed and Acceleration Newton’s 1st Law = Inertia Newton’s 2nd Law  a = F/m F = m×a m = F/a Constant velocity = Zero acceleration = NO Fnet Balanced = NO movement OR at a constant speed Unbalanced = movement where the vector is longer and the magnitude (#N) is larger

3 A. At constant speed Constant Speed UP = Constant Speed DOWN = SAME scale reading = Fweight = FN

4 B. Positive acceleration
Acceleration UP = LARGER scale reading = FN is GREATER than Fweight

5 c. Negative Acceleration
Acceleration DOWN = SMALLER scale reading = FN is LESS than Fweight

6 Force = m × a, its units are Newtons (N)
2. Calculating Acceleration Force = m × a, its units are Newtons (N) Weight = m × g, its units are Newtons (N) Therefore, Force = Weight Free Fall (broken elevator cable)  the scale would NOT push up at all and the reading would be ZERO

7 4*6 Physics Talk: (p414) Forces Acting During Acceleration
3. Apparent Weight Normal Force (FN) = Apparent Weight (FN) = (m × g) + (m × a) Acceleration UP = MORE Contact Force = LARGER “Apparent” Weight = You feel like you weigh MORE!!! Acceleration DOWN = LESS Contact Force = SMALLER “Apparent” Weight = You feel like you weigh LESS!!! Apparent Weight = (m × g) + (m × a)

8 Sample Problems (model)
A man with a mass of 50kg is on an elevator, the elevator is accelerating at +2 m/s/s. What is his apparent weight?

9 Sample Problems (team)
A woman with a mass of 25kg is on an roller coaster, the ride is accelerating at -2 m/s/s. What is her apparent weight?

10 Sample Problems (you) A kid with a mass of 15 kg is on an elevator, the elevator is accelerating at 3 m/s/s. What is his apparent weight?

11 Free Fall  the ONLY force acting on an object is GRAVITY; (Fweight)
4. Air Resistance Free Fall  the ONLY force acting on an object is GRAVITY; (Fweight) Acceleration due to GRAVITY is IDENTICAL for ALL objects falling on Earth…10m/s/s!!!!! Air Resistance  the force working AGAINST GRAVITY that pushes upward on falling objects; (FN) ***4-6 Cu/PTG***

12 4*6 TOTD No movement and constant speed are two examples of __________ forces. On a free-body diagram, if there is no movement or its at constant speed, then the arrow/forces = _____. _____ is the unit for both Force and Weight. One feels _____ when they are moving DOWN in an elevator because they have _____ contact force. The equation for Apparent Weight = __________.

13 BOOKWORK 4-6 CU (p 415 #1-5; write questions) 4-6 PTG (p. 418, #1-8 skip 4)


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