Download presentation
Presentation is loading. Please wait.
1
Speed or rate of a chemical reaction
Chemical Kinetics Kinetics Speed or rate of a chemical reaction
2
Factors that influence reaction rate
3
Measuring Rate
4
Change of Rate with Time C4H9Cl + H2O → C4H9OH + HCl
What happens to the rate of this reaction with respect to time?
5
Change of Rate with Time C4H9Cl + H2O → C4H9OH + HCl
What happens to the rate of this reaction with respect to time?
6
Change of Rate with Time C4H9Cl + H2O → C4H9OH + HCl
7
Rates and Stoichiometry
A → B If the rate of disappearance of A is 5M/s what is the rate of appearance of B?
8
Rates and Stoichiometry
A → 2B If the rate of disappearance of A is 5M/s what is the rate of appearance of B?
9
In General aA + bB → cC + dD a t bt ct dt
Rate = [A] = -1[B] = 1[C] = 1[D] a t bt ct dt
10
Rates and Stoichiometry
A → 2C If the rate of disappearance of A is 5M/s what is the rate of appearance of C?
11
Concentration and Rate
Increase reactant concentration, increase rate. But by how much??? Rate Law
12
A → B [A] (M) Rate (M/sec) .1 2x10-3 .2 4x10-3 .4 8x10-3
Determine (a) the rate law, (b) the rate constant, (c) the rate when [A] = .15 M
13
A → B [A] (M) Rate (M/sec) .1 1x10-3 .2 4x10-3 .4 16x10-3
Determine (a) the rate law, (b) the rate constant, (c) the rate when [A] = .3 M
14
A + B → C [A] (M) [B] (M) Rate (M/sec) .1 .1 4x10-3 .1 .2 4x10-3
Determine (a) the rate law, (b) the rate constant, (c) the rate when [A] = .05 M and [B] = .1 M
15
Concentration of Reactants and Time
Rate law expressions allow us to calculate the rate of a reaction. These rate law expressions can then be converted to equations, using calculus, that can tell us what the concentration of a reactant is at a specific time
16
First Order Reaction A→B rate = -[A] t
17
First Order Reaction A→B rate = -[A] rate = k[A] t
18
First Order Reaction A→B rate = -[A] rate = k[A] t -[A] = k[A]
19
This is called the differential rate law
First Order Reaction A→B rate = -[A] rate = k[A] t -[A] = k[A] This is called the differential rate law
20
First Order Reaction ln [A]t - ln [A]o = -kt
21
First Order Reaction ln [A]t - ln [A]o = -kt ln [A]t = -kt [A]o
22
First Order Reaction ln [A]t = -kt ln [A]t - ln [A]o = -kt [A]o
ln [A]t = -kt + ln[A]o
23
ln [A]t = -kt Integrated Rate Laws
First Order Reaction ln [A]t - ln [A]o = -kt ln [A]t = -kt Integrated Rate Laws [A]o ln [A]t = -kt + ln[A]o
24
The decomposition of dinitrogen pentoxide is a first order reaction with a rate constant of 5.1 x s-1. (a) If the initial concentration was 0.25M, what is the concentration after 3.2 minutes? (b) How long will it take for the concentration to decrease to 0.15M? 2N2O5(g) → 4NO2(g) + O2(g)
25
First Order Reaction ln [A]t = -kt + ln[A]o
26
First Order Reaction ln [A]t = -k t + ln[A]o ↓ ↓ ↓ ↓ y = m x + b
27
Second Order Reaction A →B rate = -[A] t
28
Second Order Reaction A →B rate = -[A] rate = k[A]2 t
29
Second Order Reaction A →B rate = -[A] rate = k[A]2 t -[A] = k[A]2
30
Second Order Reaction A →B rate = -[A] rate = k[A]2 t
-[A] = k[A]2 This is called the differential rate law
31
Second Order Reaction Integrated Rate Law
32
Half-Life (t1/2 ) Time required for the concentration of the reactant to reach ½ of its initial value.
33
Half-Life (t1/2 ) Time required for the concentration of the reactant to reach ½ of its initial value. [A]t ½ = ½[A]o
34
Half-Life (t1/2 ) Time required for the concentration of the reactant to reach ½ of its initial value. [A]t ½ = ½[A]o First order reaction : t1/2 = /k
35
Half-Life (t1/2 ) Time required for the concentration of the reactant to reach ½ of its initial value. [A]t ½ = ½[A]o First order reaction : t1/2 = /k Second order reaction : t1/2 = 1/k[A]o
36
Note: nuclear decay is a ? order reaction
Half-Life (t1/2 ) Time required for the concentration of the reactant to reach ½ of its initial value. [A]t ½ = ½[A]o First order reaction : t1/2 = /k Second order reaction : t1/2 = 1/k[A]o Memorize! Note: nuclear decay is a ? order reaction
37
The recombination of iodine atoms to form molecular iodine in the gas phase follows second order kinetics and has a rate constant of 7.0 x 109 M-1. (a) If the initial concentration of I was 0.086M, calculate the concentration after 2.0 minutes. (b) Calculate the half-life of the reaction if the initial concentration of I is 0.60M. I + I → I2
38
In order for a reaction to occur, particles must collide
Collision Theory In order for a reaction to occur, particles must collide
39
The particles must collide at the proper angle
Two conditions 1. Orientation The particles must collide at the proper angle
40
Two conditions 2. Energy
41
The particles must collide with enough energy to stick
Two conditions 2. Energy The particles must collide with enough energy to stick
42
Cons Ran
43
Arrhenius Equation Shows the quantitative relationship between rate, activation energy, and temperature
44
Calculations Involving Ea
k = Ae –Ea/RT
45
Calculations Involving Ea
k = Ae –Ea/RT ln k = ln Ae–Ea/RT
46
Calculations Involving Ea
k = Ae –Ea/RT ln k = ln Ae–Ea/RT ln k = ln A – Ea/RT
47
Calculations Involving Ea
k = Ae –Ea/RT ln k = ln Ae–Ea/RT ln k = ln A – Ea/RT ln k = (-Ea/R) (1/T) + ln A
48
Calculations Involving Ea
k = Ae –Ea/RT ln k = ln Ae–Ea/RT ln k = ln A – Ea/RT ln k = (-Ea/R) (1/T) + ln A y = m x b
49
ln k = (-Ea/R) (1/T) + ln A y = m x b
50
Calculations Involving Ea
51
Reaction Mechanisms Most chemical reactions occur in a series of steps, not a single one as shown by a balanced chemical equation
52
Reaction Mechanisms Most chemical reactions occur in a series of steps, not a single one as shown by a balanced chemical equation The sequence of steps a reaction goes through is called the reaction mechanism
53
Reaction Mechanisms Elementary Reactions
Reactions that do occur in a single step
54
Reaction Mechanisms Elementary Reactions
Reactions that do occur in a single step NO + O3 → NO2 + O2
55
Reaction Mechanisms Elementary Reactions
Reactions that do occur in a single step NO + O3 → NO2 + O2
56
Reaction Mechanisms Multistep Reactions
NO2 + CO → NO + CO2
57
Reaction Mechanisms Multistep Reactions
NO2 + CO → NO + CO2 Occurs in 2 steps
58
Reaction Mechanisms Multistep Reactions
NO2 + CO → NO + CO2 Occurs in 2 steps NO2 + NO2 → NO3 + NO
59
Reaction Mechanisms Multistep Reactions
NO2 + CO → NO + CO2 Occurs in 2 steps NO2 + NO2 → NO3 + NO NO3 + CO → NO2 + CO2
60
Rate Laws (elementary reactions)
For an elementary reaction and only an elementary reaction we can use the coefficients from the balanced equation as the reaction orders.
61
Table 14.03 Figure 14-T03 Title: Table 14.3 Caption:
Elementary Reactions and Their Rate Laws Notes: Keywords:
62
Rate Laws (multistep reactions)
The slowest reaction in a multistep reaction will determine the rate of the reaction
63
Rate Laws (multistep reactions)
Reactions where the first step is the slowest
64
Rate Laws (multistep reactions)
Reactions where the first step is the slowest NO2 + CO → NO + CO2 NO2 + NO2 → NO3 + NO (slow) NO3 + CO → NO2 + CO2 (fast)
65
Rate Laws (multistep reactions)
Reactions where the second step is the slowest
66
Rate Laws (multistep reactions)
Reactions where the second step is the slowest 2NO + Br2 → 2NOBr NO + Br2 ⇌ NOBr2 (fast) NOBr2 + NO → 2NOBr (slow)
67
Catalyst Catalyst increase rate without being used up.
They are very specific They work by lowering activation energy
68
Catalyst work by lowering activation energy
69
Catalyst Homogeneous Same phase as reacting molecules
70
Catalyst Heterogeneous Different phase as reacting molecules
Work by adsorption
71
Catalyst Enzymes
72
Catalyst Enzymes Large molecular mass proteins
73
Lock and Key Model
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.