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3.10 – NOTES Measuring Matter - Moles
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V. Measuring Matter A. Counting particles
It is convenient and easier to count certain items in groups: e.g. eggs in a dozen, paper in reams (500 sheets), etc. Matter is composed of items so small that we must mass out groups of atoms or molecules, and those groups are called moles.
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B. What is a mole? Definition: A mole (mol) is defined as the number of particles (carbon atoms) in exactly 12g of C-12. The number has been found to be x 1023; this is known as Avogadro’s number.
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C. Converting moles to particles and particles to moles
Conversion factor is 1 mole = x 1023 particles
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Examples a. How many atoms are in a 5.67 mole sample of Cu?
5.67 mol x x 1023atoms of Cu = 3.41 x 1024atoms 1 mole **maintain sig figs
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Examples b. How many molecules are in 0.0034 mole of water?
mol x x 1023m-c of H2O = 2.0 x m-c 1 mole **maintain sig figs
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Examples c. How many moles are in a 2.78 x 1024 atom sample of Ar?
2.78 x 1024 atoms Ar x mole = 4.62 moles 6.02 x 1023 atoms
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d. 9.12 x 1021 molecules of N2O = _____________ mole
9.12 x 1021 m-c of N2O x mole = moles 6.02 x 1023 m-c
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II. Mass and the Mole A. The mass of a mole of elements and compounds
Molar mass is __the sum of the elemental masses in a compound_. The molar mass of a substance contains x 1023 particles of the substance. Particles would be atoms for most elements; molecules for compounds. Molar mass is a conversion factor!
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1. What is the molar mass of oxygen gas?
2 x 16.0 = 32.0 g/mol
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2. What is the molar mass of calcium phosphate, Ca3(PO4)2?
Ca – 3 x 40.1 = P – 2 x 31.0 = O – 8 x 16.0 = 310. g/ mol
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B. Using molar mass Examples: 1. How many moles are in a 45 gram sample of sulfur dioxide, SO2? 45 g SO2 x 1 mol = mol 64.0 g
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2. 0.0718 mole of nitric acid, HNO3, would have a mass of ________________ g.
mol HNO3 x 63.0 g = g 1 mol
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C. Conversions from mass to particles and particles to mass
These problems have 2 steps since you must go through moles first.
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Examples: 1. How many atoms are in a 3.4 gram sample of gold?
3.4 g Au x 1 mol x x 1023atoms = 1.0 x 1022atoms 197 g mol *MM and Avogadro’s number should still have a minimum of 3 sig figs even though the given only has 2.
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2. 4.51 x 1023 molecules of fluorine gas would have a mass of _________________ g.
4.51 x 1023 mc F2 x _____1 mol____ x g = g 6.02 x 1023mc mol
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3. 2.543 x 1023 molecules of carbon dioxide will have ______ grams of oxygen.
2.543 x 1023 mc CO2 x 2 atoms O x ____1 mol_____ x g = g mc CO x 1023atoms mol **Use 4 sig figs for mass and Avogadro’s number since 4 sig figs were originally given.
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