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Torque and RPM of Gears π
ππ 2 π
ππ 1 = π 1 π 2 = π 1 π 2 = π 1 π 2
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Torque Torque is the moment applied about the longitudinal axis of a body (typically called a shaft). Free Body Diagram of the Gear: x y What is Rx for loading shown? P d r T Rx = 0 Rx F Ry What if another Load, P, was applied? To keep the system in equilibrium, a resisting torque is applied to the shaft. Rx = -P Shaft torque constrains rotation Bearing constrains translation
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Gears Toothed members that transmit rotary motion from one shaft to another. The servos used with the Arduino contain a series of spur gears which transfer motion between parallel shafts. Pitch diameter is the effective diameter of the gear. If gear 1 has 30 teeth and gear 2 has 10 teeth, then the upper gear will turn ____ times when the lower gear turns ____ times. If gear 1 turns one revolution per minute and gear 2 turns three revolutions per minute, can you develop a relationship between revolutions per minute and gear teeth? d1 GEAR 1 GEAR 2 1 d2 3 3 πππ£πππ’π‘ππππ πππ ππππ’π‘π 1 πππ£πππ’π‘πππ πππ ππππ’π‘π = 30 π‘πππ‘β 10 π‘πππ‘β πΊπππ 2 πππ£πππ’π‘ππππ πππ ππππ’π‘π πΊπππ 1 πππ£πππ’π‘ππππ πππ ππππ’π‘π = ππππ‘β ππ πΊπππ 1 ππππ‘β ππ πΊπππ 2 π
ππ 2 π
ππ 1 = # ππ π‘πππ‘β ππ ππππ 1 # ππ π‘πππ‘β ππ ππππ 2 = π 1 π 2
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Gear Analysis T2 T1 F F Rx2 Ry2 x y d1
Every force has an equal and opposite force (Newtonβs 2nd Law) F d2 T2 Rx2 Ry2 Analysis of Gear 1: Analysis of Gear 2: πΉ π₯1 =πΉ+ π
π₯1 =0 πΉ π₯2 =βπΉ+ π
π₯2 =0 π
π₯1 =βπΉ π
π₯2 =πΉ πΉ π¦1 = π
π¦1 =0 πΉ π¦1 = π
π¦2 =0 π
π¦1 =0 π
π¦2 =0 π ππππ‘ππ1 = βπ 1 +πΉβ π 1 2 =0 π ππππ‘ππ2 = βπ 2 +πΉβ π 2 2 =0 + + π 1 =πΉβ π 1 2 π 2 =πΉβ π 2 2
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Gear Analysis T2 T1 F Rx2 Ry2 x y d1 d2 Gear 1: Gear 2: π
π₯1 =βπΉ
π
π₯2 =πΉ π
π¦1 =0 π
π¦2 =0 π 1 =πΉβ π 1 2 π 2 =πΉβ π 2 2 This is the same F. Solve for F with both equation and set them equal to each other. 2β π 1 π 1 =πΉ 2β π 2 π 2 =πΉ π
ππ 2 π
ππ 1 = π 1 π 2 = π 1 π 2 = π 1 π 2 2β π 1 π 1 = 2β π 2 π 2 # of teeth is often represented with N. π 1 π 2 is the same as # ππ π‘πππ‘β ππ ππππ 1 # ππ π‘πππ‘β ππ ππππ 2 π 1 π 2 = π 1 π 2
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Class Problem: Consider the gear train below
Class Problem: Consider the gear train below. Assume the gears are supported by bearings and that all gears have compatible teeth. Find the RPM of gears 2, 3 and 4 (gears 2 and 3 are joined like many of your servo gears). Find torque transmitted through gears 2, 3, and 4. Gear Teeth RPM Torque (in-lbs) 1 10 3600 2 30 3 8 4 40 π
ππ 2 π
ππ 1 = π 1 π 2 = π 1 π 2 = π 1 π 2 1200 30 1200 30 240 150 a. π
ππ 2 π
ππ 1 = π 1 π 2 b. π 2 π 1 = π 2 π 1 π
ππ 2 = π 1 π 2 π
ππ 1 π 2 = π 2 π 1 π 1 π
ππ 2 = =1200 =π
ππ 3 π 2 = ππβπππ =30 ππβπππ =π 3 Gear 2 and 3 are connected and so they must turn at the same speed π 4 = π 4 π 3 π 3 = ππβπππ π
ππ 4 = π 3 π 4 π
ππ 3 = =150ππβπππ =240
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Gear Summary Points to Remember:
1 Points to Remember: Bigger gear turns slower than smaller gear. Bigger gear has more torque than smaller gear. Both gears on a compound gear turn at the same rate and transmit the same torque. π
ππ 2 π
ππ 1 = π 1 π 2 = π 1 π 2 = π 1 π 2
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