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Copyright © 2014 Pearson Education, Inc.
6.2 Parallelograms Objectives Use Relationships Among Sides and Angles of Parallelograms. Use Relationships Among Consecutive Angles and Diagonals of Parallelograms. Copyright © 2014 Pearson Education, Inc.
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Copyright © 2014 Pearson Education, Inc.
Definition A parallelogram is a quadrilateral with both pairs of opposite sides parallel. Parallelograms have special properties regarding their sides, angles, and diagonals. Copyright © 2014 Pearson Education, Inc.
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Copyright © 2014 Pearson Education, Inc.
Definition In a parallelogram (and in all other convex quadrilaterals), opposite sides do not share a vertex, and opposite angles do not share a side. Copyright © 2014 Pearson Education, Inc.
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Opposite Sides of a Parallelogram
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Opposite Angles of a Parallelogram
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Copyright © 2014 Pearson Education, Inc.
Proof Use the given figure for a proof of Theorem Given: ▱ABCD Prove: AB ≅ CD and BC ≅ DA Solution Start a two-column proof. This is on the next slide. Copyright © 2014 Pearson Education, Inc.
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Copyright © 2014 Pearson Education, Inc.
Statements Reasons 1. ABCD is a parallelogram. 1. Given 2. Definition of parallelogram 3. If lines are parallel, then alternate interior angles are congruent. 4. Reflexive Property of Congruence 5. ASA 6. Corresponding parts of congruent triangles are congruent. (cpoctac) Copyright © 2014 Pearson Education, Inc.
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Copyright © 2014 Pearson Education, Inc.
Definition Angles of a polygon that share a side are consecutive angles. In the diagram, ∠A and ∠B are consecutive angles because they share side AB. Copyright © 2014 Pearson Education, Inc.
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Consecutive Angles of a Parallelogram
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Diagonals of a Parallelogram
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Using Consecutive Angles
Multiple Choice What is m∠P in ▱PQRS? a. 26° b. 64° c. 116° d. 126° Solution ▱PQRS means parallelogram PQRS Copyright © 2014 Pearson Education, Inc.
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Using Consecutive Angles
Multiple Choice What is m∠P in ▱PQRS? a. 26° b. 64° c. 116° d. 126° Solution m∠P + m∠S = 180° m∠P + 64° = 180° m∠P = 116° The correct answer is c. Copyright © 2014 Pearson Education, Inc.
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Using Algebra to Find Lengths
Solve a system of linear equations to find the values of x and y in ▱KLMN. What are KM and LN? Solution To find these lengths, we set up a system of two equations and solve by substitution. Copyright © 2014 Pearson Education, Inc.
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Using Algebra to Find Lengths
Equation (1) y + 10 = 2x – 8 Equation (2) x = y + 2 y + 10 = 2x − 8 y + 10 = 2(y + 2) − 8 y + 10 = 2y + 4 − 8 y + 10 = 2y − 4 10 = y − 4 14 = y To find the value of x, choose Equation 1 or Equation 2 and substitute 14 for y. We choose Equation 2. x = y + 2 x = = 16 Copyright © 2014 Pearson Education, Inc.
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Using Algebra to Find Lengths
Now, let’s find KM and LN. By looking at the parallelogram, we see that KM = 2(KP) and LN = 2(LP). KM = 2(KP) = 2(y + 10) = 2( ) = 48 Thus, x = 16 and y = 14. Also, KM = 48 units and LN = 32 units. Copyright © 2014 Pearson Education, Inc.
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Multiple Parallel Lines and Transversals
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Using Parallel Lines and Transversals
In the figure, AB = BC = CD = 2 and EF = What is EH? Solution We are given the length of segment EF. Thus, to find EH, we need the length of segments FG and GH. Copyright © 2014 Pearson Education, Inc.
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