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Conservation of Mass Problem

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Presentation on theme: "Conservation of Mass Problem"β€” Presentation transcript:

1 Conservation of Mass Problem

2 DISCLAIMER & USAGE The content of this presentation is for informational purposes only and is intended for students attending Louisiana Tech University only. The authors of this information do not make any claims as to the validity or accuracy of the information or methods presented. Any procedures demonstrated here are potentially dangerous and could result in damage and injury. Louisiana Tech University, its officers, employees, agents and volunteers, are not liable or responsible for any injuries, illness, damage or losses which may result from your using the materials or ideas, or from your performing the experiments or procedures depicted in this presentation. The Living with the Lab logos should remain attached to each slide, and the work should be attributed to Louisiana Tech University. If you do not agree, then please do not view this content. boosting application-focused learning through student ownership of learning platforms

3 What is the weight of the final batch of mud?
Class Problem: A batch of masonry cement is made by mixing three 5-gallon buckets of wet sand with one 70 lb bag of masonry mix and 3 gallons of water. The sand used in the mix is partially wet, containing an unknown amount of water. If the final batch of β€œmud” contains 11.3% water when the desired consistency is reached, then how many gallons of water did the sand used in the mixture contain? Assume wet sand and dry sand occupy the same volume. What is the weight of the final batch of mud? Convert all gal values to lb: Weight of 3 gal Water: 3π‘”π‘Žπ‘™βˆ™8.33 𝑙𝑏𝑠 π‘”π‘Žπ‘™ =24.99𝑙𝑏 70 lbs masonry mix 100% masonry mix Weight of Dry Sand: 15π‘”π‘Žπ‘™βˆ™ 𝑓𝑑 3 π‘”π‘Žπ‘™ βˆ™111 𝑙𝑏 𝑓𝑑 3 =222.6𝑙𝑏 Wet Sand 3 - 5gal buckets = 15gal 3gal water 100% water Apply Conservation of Mass Equations: π‘š 𝑖𝑛 βˆ’ π‘š π‘œπ‘’π‘‘ + π‘š π‘”π‘’π‘›π‘’π‘Ÿπ‘Žπ‘‘π‘’π‘‘ βˆ’ π‘š π‘π‘œπ‘›π‘ π‘’π‘šπ‘’π‘‘ = π‘š π‘“π‘–π‘›π‘Žπ‘™ βˆ’ π‘š π‘–π‘›π‘–π‘‘π‘–π‘Žπ‘™ 222.6lb dry sand X lb water 24.99 lb water Y lbs β€œmud” 11.3% water a% sand b% masonry mix π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ overall: π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ sand: X+222.6𝑙𝑏+70𝑙𝑏+24.99𝑙𝑏=Y 222.6𝑙𝑏=aY Useful Information/Conversions: Density of water = 8.33 lbs/gal Density of dry sand = 111 lbs/ft3 1 gal = ft3 π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ water: π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ mix: X+24.99𝑙𝑏=0.113Y 70𝑙𝑏=bY

4 π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ water: π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ overall:
a. How many gallons of water did the sand used in the mixture contain? 70 lbs masonry mix 100% masonry mix π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ water: π‘š 𝑖𝑛 = π‘š π‘œπ‘’π‘‘ overall: Wet Sand 3 - 5gal buckets = 15gal 3gal water 100% water X+24.99𝑙𝑏=0.113Y X+222.6𝑙𝑏+70𝑙𝑏+24.99𝑙𝑏=Y 222.6lb dry sand X lb water X+24.99𝑙𝑏 =Y X+222.6𝑙𝑏+70𝑙𝑏+24.99𝑙𝑏= X+24.99𝑙𝑏 0.113 Y lbs β€œmud” 11.3% water a% sand b% masonry mix X 𝑙𝑏= X+24.99𝑙𝑏 0.113 0.113(X 𝑙𝑏)=X+24.99𝑙𝑏 0.113X =X+24.99𝑙𝑏 10.898𝑙𝑏=0.887X X=12.286π‘™π‘βˆ™ π‘”π‘Žπ‘™ 8.33𝑙𝑏 =1.475π‘”π‘Žπ‘™ X=12.286𝑙𝑏 of water in wet sand b. What is the weight of the final batch of mud? X+24.99𝑙𝑏=0.113Y 12.286𝑙𝑏+24.99𝑙𝑏=0.113Y Useful Information/Conversions: Density of water = 8.33 lbs/gal Density of dry sand = 111 lbs/ft3 1 gal = ft3 37.276=0.113Y =Y π‘Œ= 𝑙𝑏 final batch of mud


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