1. James Scholar Opportunity
REACT: is an outreach program that goes to elementary schools to teach students chemistry.
September 10th, 11th, or 12th, at 5pm.
319 Greg Hall
Questions? Send an to the REACT student president Madeline McDevitt at

2. Chemistry 202 Dr. Don DeCoste 3014 Chemistry Annex
11am-12pm Mondays and Wednesdays (after lecture)
10-11 am Tuesdays and 1-2 pm Thursdays
By appointment; open door policy

3. Chemistry Learning Center
2021 Chemistry Annex
Chemistry TAs available from 9 am – 5pm Mondays – Fridays. Link to the schedule is on the website (Contact Information)
Chemistry 202 TAs in the CLC:
Tuesdays: 3 – 5 pm (Siva)
Wednesdays: 1 – 3 pm (Tiffany)
Thursdays: 11am – 1 pm (Alex)

4. Lon-Capa 1st HW assignment due tonight by 10 pm.
1st Quiz due Sunday, 9/9 by 10 pm. It will open today at 5 pm.

5. For Today Textbook Homework Videos Chapter 4: Solution Stoichiometry
Precipitation Stoichiometry I: Net Ionic Equations
Precipitation Stoichiometry II: Complete Equations
Challenge Problem: Chapter 4 #121

6. For Monday (etc.)
Check the website!

7. Concentration of Vinegar?
Knowing that vinegar is an aqueous solution that is 5.00% acetic acid [HC2H3O2(aq)] by mass and has a density of 1.01 g/mL, determine the concentration of vinegar in molarity.

8. NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g)
How Much Vinegar?
NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g)
We have 10.5 g of baking soda. Knowing that vinegar is 0.841M acetic acid, determine the minimum volume of vinegar required for a complete reaction. [~149 mL]

9. Solubility Rules

10. Clicker Question
A 15.0 g sample consisting of a mixture of silver nitrate and sodium nitrate is dissolved in water. This aqueous mixture then reacts with an excess of aqueous potassium chloride to form 3.97 g of solid. Calculate the percent by mass of silver nitrate in the first mixture.
a) 22.3% d) 72.9%
b) 31.4% e) I cannot do this problem.
c) 47.1%

12. Clicker Question
Consider the reaction between 50.0 mL of 0.200M NaOH and 75.0 mL of 0.100M HCl. Which of the following statements is true?
a) After the reaction, the concentration of Na+ is greater than the concentration of OH-.
b) The NaOH was the limiting reactant.
c) After the reaction, the concentration of Na+ is equal to the concentration of Cl–.
d) After the reaction, the concentration of Na+ is still 0.200M because Na+ is a spectator ion.
e) None of the above statements (a-d) is true.