1. How Tides Affect the Volumetric Flow of the Columbia River
Moon River
How Tides Affect the Volumetric Flow of the Columbia River

2. Volumetric Flow C = Velocity of the water Q = A*C
The volume of fluid = Q
Acircle = πr2
C = Velocity of the water

3. Volumetric Flow Through a Pipe
Plugging in the data…
Given: Pipe – 2 m, Velocity = 4m/s
Equations:
Q = A*C
Acircle = πr2 =
A = 3 * (2)2. Area = 12 m2
C = Velocity of the water
C = 4 m/s
Q = (12 m2) * (4 m/s)
Q = 48 m3/s

4. Volumetric Flow Through a Pipe
What would the volumetric flow be if we slowed the water flowing into the pipe, and the pipe was only ½ filled with water?
Q = 48 m3/s / 2
Q = 24 m3/s

5. Applying This Concept to the Columbia River
Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.25 m/s Equations: Q = A*C Acircle = πr2 The river can be thought of as a ½ pipe, so the surface area should be halved.

6. Applying This Concept to the Columbia River
Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.5 m/s Equations: Q = A*C Acircle = πr2 (3)(12.5)2 = 469 m2. Because the river is like a ½ pipe… 469/2 = m2.

7. Applying This Concept to the Columbia River
Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.25 m/s Equations: Q = A*C Acircle = m2. C = 2.25 m/s Q = (234.5 m2)(2.25 m/s) Q = m3/s