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EE 5340 Semiconductor Device Theory Lecture 12 - Fall 2009

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Presentation on theme: "EE 5340 Semiconductor Device Theory Lecture 12 - Fall 2009"— Presentation transcript:

1 EE 5340 Semiconductor Device Theory Lecture 12 - Fall 2009
Professor Ronald L. Carter

2 Soln to Poisson’s Eq in the D.R.
Ex W(Va-dV) W(Va) -xp xn x -xpc xnc -Emax(V) -Emax(V-dV) L 12 Oct 01

3 Effect of V  0 L 12 Oct 01

4 Charge neutrality => Qp’ + Qn’ = 0, => Naxp = Ndxn
Junction C (cont.) r +Qn’=qNdxn +qNd dQn’=qNddxn -xp x -xpc xn xnc -qNa Charge neutrality => Qp’ + Qn’ = 0, => Naxp = Ndxn dQp’=-qNadxp Qp’=-qNaxp L 12 Oct 01

5 Junction Capacitance The junction has +Q’n=qNdxn (exposed donors), and (exposed acceptors) Q’p=-qNaxp = -Q’n, forming a parallel sheet charge capacitor. L 12 Oct 01

6 Junction C (cont.) So this definition of the capacitance gives a parallel plate capacitor with charges dQ’n and dQ’p(=-dQ’n), separated by, L (=W), with an area A and the capacitance is then the ideal parallel plate capacitance. Still non-linear and Q is not zero at Va=0. L 12 Oct 01

7 Junction C (cont.) The C-V relationship simplifies to L 12 Oct 01

8 Junction C (cont.) If one plots [Cj]-2 vs. Va Slope = -[(Cj0)2Vbi]-1 vertical axis intercept = [Cj0]-2 horizontal axis intercept = Vbi Cj-2 Vbi Va Cj0-2 L 12 Oct 01

9 Junction Capacitance Estimate CJO Define y  Cj/CJO
Calculate y/(dy/dV) = {d[ln(y)]/dV}-1 A plot of r  y/(dy/dV) vs. V has slope = -1/M, and intercept = VJ/M L 12 Oct 01

10 dy/dx - Numerical Differentiation
L 12 Oct 01

11 Practical Junctions Junctions are formed by diffusion or implantation into a uniform concentration wafer. The profile can be approximated by a step or linear function in the region of the junction. If a step, then previous models OK. If linear, let the local charge density r=qax in the region of the junction. L 12 Oct 01

12 Practical Jctns (cont.)
Na(x) N N Shallow (steep) implant Na(x) Linear approx. Box or step junction approx. Nd Nd Uniform wafer con x (depth) x (depth) xj L 12 Oct 01

13 Linear graded junction
Let the net donor concentration, N(x) = Nd(x) - Na(x) = ax, so r =qax, -xp < x < xn = xp = xo, (chg neu) r = qa x r Q’n=qaxo2/2 -xo x xo Q’p=-qaxo2/2 L 12 Oct 01

14 Linear graded junction (cont.)
Let Ex(-xo) = 0, since this is the edge of the DR (also true at +xo) L 12 Oct 01

15 Linear graded junction (cont.)
Ex -xo xo x -Emax |area| = Vbi-Va L 12 Oct 01

16 Linear graded junction (cont.)
L 12 Oct 01

17 Linear graded junction, etc.
L 12 Oct 01

18 Doping Profile If the net donor conc, N = N(x), then at x, the extra charge put into the DR when Va->Va+dVa is dQ’=-qN(x)dx The increase in field, dEx =-(qN/e)dx, by Gauss’ Law (at x, but also all DR). So dVa=-xddEx= (W/e) dQ’ Further, since qN(x)dx, for both xn and xn, we have the dC/dx as ... L 12 Oct 01

19 Arbitrary doping profile (cont.)
L 12 Oct 01

20 Arbitrary doping profile (cont.)
L 12 Oct 01

21 Arbitrary doping profile (cont.)
L 12 Oct 01

22 Arbitrary doping profile (cont.)
L 12 Oct 01

23 Example An assymetrical p+ n junction has a lightly doped concentration of 1E16 and with p+ = 1E18. What is W(V=0)? Vbi=0.816 V, Neff=9.9E15, W=0.33mm What is C’j0? = 31.9 nFd/cm2 What is LD? = 0.04 mm L 12 Oct 01

24 Reverse bias junction breakdown
Avalanche breakdown Electric field accelerates electrons to sufficient energy to initiate multiplication of impact ionization of valence bonding electrons field dependence shown on next slide Heavily doped narrow junction will allow tunneling - see Neamen*, p. 274 Zener breakdown L 12 Oct 01

25 Effect of V  0 L 12 Oct 01

26 Ecrit for reverse breakdown [M&K]
Taken from p. 198, M&K** L 12 Oct 01

27 Reverse bias junction breakdown
L 12 Oct 01

28 Ecrit for reverse breakdown [M&K]
Taken from p. 198, M&K** Casey Model for Ecrit L 12 Oct 01

29 Reverse bias junction breakdown
Assume -Va = VR >> Vbi, so Vbi-Va-->VR Since Emax~ 2VR/W = (2qN-VR/(e))1/2, and VR = BV when Emax = Ecrit (N- is doping of lightly doped side ~ Neff) BV = e (Ecrit )2/(2qN-) Remember, this is a 1-dim calculation L 12 Oct 01

30 Junction curvature effect on breakdown
The field due to a sphere, R, with charge, Q is Er = Q/(4per2) for (r > R) V(R) = Q/(4peR), (V at the surface) So, for constant potential, V, the field, Er(R) = V/R (E field at surface increases for smaller spheres) Note: corners of a jctn of depth xj are like 1/8 spheres of radius ~ xj L 12 Oct 01

31 BV for reverse breakdown (M&K**)
Taken from Figure 4.13, p. 198, M&K** Breakdown voltage of a one-sided, plan, silicon step junction showing the effect of junction curvature.4,5 L 12 Oct 01

32 References [M&K] Device Electronics for Integrated Circuits, 2nd ed., by Muller and Kamins, Wiley, New York, 1986. [2] Devices for Integrated Circuits: Silicon and III-V Compound Semiconductors, by H. Craig Casey, Jr., John Wiley & Sons, New York, 1999. Bipolar Semiconductor Devices, by David J. Roulston, McGraw-Hill, Inc., New York, 1990. L 12 Oct 01


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