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Solve Systems of Equations by Elimination

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Presentation on theme: "Solve Systems of Equations by Elimination"— Presentation transcript:

1 Solve Systems of Equations by Elimination

2 Steps for Elimination:
Arrange the equations with like terms in columns Multiply, if necessary, to create opposite coefficients for one variable. Add the equations. Substitute the value to solve for the other variable. Check

3 EXAMPLE 1 (continued) (-1, 3)

4 EXAMPLE 2 4x + 3y = 16 2x – 3y = 8 (4, 0)

5 EXAMPLE 3 3x + 2y = 7 -3x + 4y = 5 (1, 2)

6 EXAMPLE 4 2x – 3y = 4 -4x + 5y = -8 (2, 0)

7 EXAMPLE 5 5x + 2y = 7 -4x + y = –16 (3, -4)

8 EXAMPLE 5 2x + 3y = 1 4x – 2y = 10 (2, -1)

9 Classwork (-1, 4) (-1, 2) (-2, 2) (1, 5) (5, -2) (4, -1) (-1/2, 4)
Add/Subtract Use elimination to solve each system of equations. 6x + 5y = m – 4n = a + b = 1 6x – 7y = m + 2n = a + b = 3 -3x – 4y = x – 3y = x – 2y = 6 -3x + y = x – 3y = x + y = 3 2a – 3b = x + 2y = x – y = 6 2a + 2b = x + 4y = x + 2y = 3 (-1, 4) (-1, 2) (-2, 2) (1, 5) (5, -2) (4, -1) (-1/2, 4) (1/2, 2) (1, -1)

10 Classwork (1, 1) (-3, 4) (-1, 2) (-1, 2) (4, -2) (-4, -2) (2, -1)
Multiply Use elimination to solve each system of equations. 2x + 3y = m + 3n = a - b = 2 x + 2y = m + 2n = a + 2b = 3 4x + 5y = x – 3y = x – 4y = -4 6x - 7y = x – y = x + 3y = -10 4x – y = a – 3b = x + 2y = 5 5x + 2y = a + 2b = x - 4y = 10 (1, 1) (-3, 4) (-1, 2) (-1, 2) (4, -2) (-4, -2) (2, -1) (-1/2, 2) (2.5, 0)


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