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…Somebody at some point made this. Ehh it’s ok.
Semester 2 Review …Somebody at some point made this. Ehh it’s ok.
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Stoich
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Stoichiometry Vocab Limiting vs. Excess Reagent
Theoretical vs. Actual Yield % yield = (Actual yield / Theoretical yield) x 100
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Thermo.
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Vocab Thermochemistry Potential Energy Kinetic Energy Energy Heat Temperature Calorimetry Enthalpy Entropy Hess’s Law Specific Heat Capacity Endothermic Reactions Exothermic Reactions
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Specific Heat Calculations
q = (m)(c)(ΔT) heat = mass • specific heat • change in temp ∆𝑇= 𝑇 𝑓𝑖𝑛𝑎𝑙 − 𝑇 𝑖𝑛𝑖𝑡𝑖𝑎𝑙
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Application of Hess’s Law… Reg.
Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: SO3 (g) + H2O (g) H2SO4 (l) H2SO4 (l) H2S (g) + 2 O2 (g) ΔH = kJ H2O (g) H2O (l) ΔH = -44 kJ H2S (g) + 2 O2 (g) SO3 (g) + H2O (l) ΔH = -207 kJ Change in Enthalpy = -72.5kJ
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Application of Hess’s Law… Honors
Calculate the enthalpy of the following chemical reaction: CS2(ℓ) + 3O2(g) ---> CO2(g) + 2SO2(g) Given: C(s) + O2(g) ---> CO2(g) ΔH = kJ/mol S(s) + O2(g) ---> SO2(g) ΔH = kJ/mol C(s) + 2S(s) ---> CS2(ℓ) ΔH = kJ/mol
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Calculations CH4(g) + 2O2(g) CO2(g) + 2H2O(g) Enthalpies of formation: CH4: kJ/mol O2: 0.0 kJ/mol CO2: kJ/mol H2O: kJ/mol
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Calculations CH4(g) + 2O2(g) CO2(g) + 2H2O(g) Enthalpies of formation: CH4: kJ/mol X 1 mol = kJ O2: 0.0 kJ/mol X 2 mol = 0.0 kJ CO2: kJ/mol X 1 mol = kJ H2O: kJ/mol X 2 mol = kJ
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Calculations CH4(g) + 2O2(g) CO2(g) + 2H2O(g) Enthalpies of formation: ΔH = ( kJ kJ) – ( kJ kJ) ΔH = kJ
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Molarity
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Vocab: Be a part of the solution!
Solute: The particles that become dissolved. Solvent: the dissolving medium (what the solute dissolves in). Aqueous Solution: solution where the solvent is water. Concentration: a measure of the amount of solute that is dissolved in a given quantity of solvent.
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Solution making 101 To reach a specific concentration of solution, we must carefully calculate and measure out both the solute and the solvent. 𝑚𝑎𝑠𝑠 𝑜𝑓 𝑡ℎ𝑒 𝑠𝑜𝑙𝑢𝑡𝑒= 𝑑𝑒𝑠𝑖𝑟𝑒𝑑 𝑚𝑜𝑙𝑎𝑟𝑖𝑡𝑦 𝑚𝑜𝑙𝑎𝑟 𝑚𝑎𝑠𝑠 𝑑𝑒𝑠𝑖𝑟𝑒𝑑 𝑣𝑜𝑙𝑢𝑚𝑒 Volume must be in Liters!
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Calculations with Dilutions
M1V1 = M2V2 (Molarity)(Volume) = (Molarity)(Volume)
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Kinetics and Equilibrium
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Vrooom! Collision Theory: Particles must collide with proper orientation and enough energy to react. Factors that affect reactions rates: Concentration Surface area Particle size Temperature Catalysts
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Law of Mass Action Chemical Equilibrium: a state in which the forward and reverse reactions balance each other because they take place at equal rates. For the reaction: 𝑗𝐴+𝑘𝐵 ↔𝑙𝐶+𝑚𝐷 Where K is the Equilibrium Constant, and is unitless. Ignore pure solids and pure liquids with equilibrium.
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Le Chatelier’s Principle
If a change is imposed on a system at equilibrium, the position of the equilibrium will shift in a direction that tends to reduce that change. Possible changes: Concentration Pressure Volume Inert Gas Temperature
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Nuclear Chemistry
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Radiation Radioisotopes: Isotopes with unstable nuclei.
Three types of radiation: Alpha particles Beta particles Gamma rays
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Nuclear Equations
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Fission vs. Fusion Nuclear Fission: the splitting of a nucleus into fragments. This is accompanied by a very large release of energy. Nuclear Fusion: the combination of atomic nuclei. This releases more energy than fission and uses materials that are easier to come by. The activation energy is around 5,000,000K.
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Acids and Bases
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Not so Mathy Bronsted-Lowry acid vs. Bronsted-Lowry base
Conjugate acid and base Amphoterism Strong acids HCl, HBr, HI, HClO4, H2SO4, HNO3 Strong bases Group I and II hydroxides
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pH and pOH Calculations
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Gas Laws
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Not so Mathy What causes pressure?
What can we use to measure pressure? Relationships between pressure, volume, temperature and moles of gas.
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Gas Laws Boyle’s Law PV = PV Charles’s Law V/T = V/T
Gay-Lussac’s Law P/T = P/T Combined Gas Law PV/T = PV/T Ideal Gas Law PV = nRT Dalton’s Law of Partial Pressures Total pressure = Sum of partial n1/nT = P1/PT
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