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More Discussion of the Binomial Distribution: Comments & Examples

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1 More Discussion of the Binomial Distribution: Comments & Examples
j Thermo & Stat Mech - Spring Class 16

2 Requirements justifying use of the Binomial Distribution:
The Binomial Distribution applies ONLY to cases where there are only 2 possible outcomes: heads or tails, success or failure, defective or good item, etc. Requirements justifying use of the Binomial Distribution: 1. The experiment must consist of n identical trials. 2. Each trial must result in only one of 2 possible outcomes. 3. The outcomes of the trials must be statistically independent. 4. All trials must have the same probability for a particular outcome.

3 Binomial Distribution
3/21/06 Binomial Distribution The Probability of n Successes out of N Attempts is: p = Probability of a Success q = Probability of a Failure q = 1 – p, (p + q)N = 1

4 Mean of the Binomial Distribution
3/21/06 Mean of the Binomial Distribution l Thermo & Stat Mech - Spring Class 16

5 Standard Deviation (s) of the Binomial Distribution
3/21/06 Standard Deviation (s) of the Binomial Distribution 2 1 3

6 For The Binomial Distribution
3/21/06 For The Binomial Distribution

7 Common Notation for the Binomial Distribution
r items of one type & (n – r) of a second type can be arranged in nCr ways. Here: nCr is called the binomial coefficient In this notation, the probability distribution is: Wn(r) = nCrpr(1-p)n-r ≡ probability of finding r items of one type & n – r items of the other type. p = probability of a given item being of one type .

8 Binomial Distribution: Example
Problem: A sample of n = 11 electric bulbs is drawn every day from those manufactured at a plant. The probabilities of getting defective bulbs are random and independent of previous results. Probability that a given bulb is defective is p = 0.04. 1. What is the probability of finding exactly three defective bulbs in a sample? (Probability that r = 3?) 2. What is the probability of finding three or more defective bulbs in a sample? (Probability that r ≥ 3?)

9 Binomial Distribution, n = 11 Number of Defective Bulbs, r
Probability 11Crpr(1-p)n-r p = 0.04 11C0 (0.04)0(0.96)11 = 1 11C1 (0.04)1(0.96)10 = 2 11C2 (0.04)2(0.96)9 = 3 11C3 (0.04)3(0.96)8 = l Thermo & Stat Mech - Spring Class 16

10 P(r = 3 defective bulbs) =
Question 1: Probability of finding exactly three defective bulbs in a sample? P(r = 3 defective bulbs) = W11(r = 3) = l Thermo & Stat Mech - Spring Class 16

11 P(r = 3 defective bulbs) =
Question 1: Probability of finding exactly three defective bulbs in a sample? P(r = 3 defective bulbs) = W11(r = 3) = Question 2: Probability of finding three or more defective bulbs in a sample? P(r ≥ 3 defective bulbs) = 1- W11(r = 0) – W11(r = 1) – W11(r = 2) = 1 – – = l Thermo & Stat Mech - Spring Class 16

12 Binomial Distribution, Same Problem, Larger r
Number of Defective Bulbs, r Probability 11Crpr(1-p)n-r 11C0(0.04)0(0.96)11 = 1 11C1 (0.04)1(0.96)10 = 2 11C2 (0.04)2(0.96)9 = 3 11C3 (0.04)3(0.96)8 = 4 11C4 (0.04)4(0.96)7 = 5 11C5 (0.04)5(0.96)6 = Thermo & Stat Mech - Spring Class 16 l

13 Thermo & Stat Mech - Spring 2006 Class 16
Binomial Distribution n = 11, p = 0.04 Distribution of Defective Items Distribution of Good Items l Thermo & Stat Mech - Spring Class 16

14 The Coin Flipping Problem
3/21/06 The Coin Flipping Problem Consider a perfect coin. There are only 2 sides, so the probability associated with coin flipping is The Binomial Distribution. Problem: 6 perfect coins are flipped. What is the probability that they land with n heads & 1 – n tails? Of course, this only makes sense if 0 ≤ n ≤ 6! For this case, the Binomial Distribution has the form: l Thermo & Stat Mech - Spring Class 16

15 Binomial Distribution for Flipping 1000 Coins
3/21/06 Binomial Distribution for Flipping 1000 Coins Note: The distribution peaks around n = 500 successes (heads), as we would expect n = Np = 500 l Thermo & Stat Mech - Spring Class 16

16 Binomial Distribution for Selected Values of n & p
Thermo & Stat Mech - Spring Class 16

17 Binomial Distribution for Selected Values of n & p
n = 5, p = n = 5, p = 0.5 n = 10, p = 0.5 l Thermo & Stat Mech - Spring Class 16

18 Binomial Distribution for Selected Values of n & p
Thermo & Stat Mech - Spring Class 16

19 Binomial Distribution for Selected Values of n & p


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