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Unit 9. Day 8..

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Presentation on theme: "Unit 9. Day 8.."β€” Presentation transcript:

1 Unit 9. Day 8.

2 We want the area of the circle
𝐢=πœ‹βˆ™π‘‘ 𝐢 𝐢=πœ‹βˆ™ 2π‘Ÿ 2 𝐢 = πœ‹βˆ™π‘Ÿ πœ‹βˆ™π‘Ÿ π‘Ÿ π‘Ÿ π‘Ÿ 2 We will find the area of this β€œrectangle” 𝐴= πœ‹βˆ™ π‘βˆ™β„Ž π‘™βˆ™π‘€ βˆ™ π‘Ÿ

3 Example A: Find the area of the circle. πœ‹β‰ˆ3.1415926… 𝐴=πœ‹βˆ™ π‘Ÿ 2
22 7 πœ‹β‰ˆ … πœ‹ 3.14 𝐴=πœ‹βˆ™ π‘Ÿ 2 7 π‘π‘š 7 π‘π‘š 7 π‘π‘š 7 π‘π‘š 𝐴= βˆ™ 𝐴= πœ‹ βˆ™ 49 π‘π‘š 2 𝐴=49πœ‹ π‘π‘š 2 𝐴=πœ‹βˆ™ π‘Ÿ 2 𝐴=πœ‹βˆ™ π‘Ÿ 2 𝐴= βˆ™ 𝐴= βˆ™ π΄β‰ˆ βˆ™ π‘π‘š 2 7 49 π‘π‘š 2 π΄β‰ˆ 3.14 βˆ™ 49 π‘π‘š 2 1 𝐴 β‰ˆ π‘π‘š 2 π΄β‰ˆ154 π‘π‘š 2

4 Example B: Find the area of the circle. πœ‹β‰ˆ3.1415926… 𝐴=πœ‹βˆ™ π‘Ÿ 2
22 7 πœ‹β‰ˆ … πœ‹ 3.14 𝐴=πœ‹βˆ™ π‘Ÿ 2 4 𝑖𝑛 8 𝑖𝑛 4 𝑖𝑛 4 𝑖𝑛 𝐴= βˆ™ 𝐴= πœ‹ βˆ™ 16 𝑖𝑛 2 𝐴=16πœ‹ 𝑖𝑛 2 𝐴=πœ‹βˆ™ π‘Ÿ 2 𝐴=πœ‹βˆ™ π‘Ÿ 2 𝐴= βˆ™ 𝐴= βˆ™ 𝑖𝑛 2 π΄β‰ˆ βˆ™ 16 𝑖𝑛 2 π΄β‰ˆ 3.14 βˆ™ 16 𝑖𝑛 2 π΄β‰ˆ 𝑖𝑛 2 β‰ˆ 𝑖𝑛 2 𝐴 β‰ˆ 𝑖𝑛 2

5 Example C: A sprinkler rotates in a circular pattern and sprays water over a distance of 12 feet. What is the area of the circular region covered by the sprinkler? Express your answer to the nearest square foot. Example D: Suzanne is making a circular table out of a square piece of wood. The square is 6 ft by 6 ft, and Suzanne wants to cut as big a circle as possible. How much waste will she have for this project? Express your answer to the nearest square foot.

6 Example C: A sprinkler rotates in a circular pattern and sprays water over a distance of 12 feet. What is the area of the circular region covered by the sprinkler? Express your answer to the nearest square foot. πœ‹β‰ˆ … 3.14 𝐴=πœ‹βˆ™ π‘Ÿ 2 𝐴= βˆ™ π΄β‰ˆ 3.14 βˆ™ 144 𝑓𝑑 2 𝐴 β‰ˆ π‘π‘š 2 12 𝑓𝑑 12 𝑓𝑑

7 Example D: Suzanne is making a circular table out of a square piece of wood. The radius of the circle that she is cutting is 3 feet. How much waste will she have for this project? Express your answer to the nearest square foot. 𝐴= 36 𝑓𝑑 2 πœ‹β‰ˆ … 3.14 𝐴=πœ‹βˆ™ π‘Ÿ 2 6 𝑓𝑑 𝐴= βˆ™ π΄β‰ˆ 3.14 βˆ™ 9 𝑓𝑑 2 𝐴 β‰ˆ 𝑓𝑑 2 3 𝑓𝑑 3 𝑓𝑑 6 𝑓𝑑 36 βˆ’ 28.26 7.74 𝑓𝑑 2 β‰ˆ8 𝑓𝑑 2


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