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Agenda Ion Quiz #6 Finish up lab

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1 Agenda Ion Quiz #6 Finish up lab
Turn in lab and chemical formula sheet Notes on formula weight Practice

2 Chapter 6 Chemical Quantities
6.3 Molar Mass Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

3 Molar Mass The molar mass
Is the mass of one mol of an element or compound. Is the atomic mass expressed in grams. Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

4 Molar Mass from the Periodic Table
Is the atomic mass expressed in grams. Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

5 Learning Check Give the molar mass for: A. 1 mol K atoms = ________
B. 1 mol Sn atoms = ________

6 Solution Give the molar mass for: A. 1 mol K atoms = 39.10 g
B. 1 mol Sn atoms = g

7 Molar Mass of a Compound
The molar mass of a compound is the sum of the molar masses of the elements in the formula. Example: Calculate the molar mass of CaCl2. Element Number of Moles Atomic Mass Total Mass Ca 1 40.08 g/mol 40.08 g Cl 2 35.45 g/mol 70.90 g CaCl2 g

8 Molar Mass of K3PO4 Calculate the molar mass of K3PO4. Element
Number of Moles Atomic Mass Total Mass in K3PO4 K 3 39.10 g/mol 117.3 g P 1 30.97 g/mol 30.97 g O 4 16.00 g/mol 64.00 g K3PO4 212.3 g

9 Some One-Mol Quantities
32.07 g g g g g Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

10 Learning Check What is the molar mass of each of the following? A. K2O
B. Al(OH)3

11 Solution A. K2O g/mol 2 mol K (39.10 g/mol) + 1 mol O (16.00 g/mol) 78.20 g g = g B. Al(OH) g/mol 1 mol Al (26.98 g/mol) + 3 mol O (16.00 g/mol) + 3 mol H (1.008 g/mol) 26.98 g g g = g

12 Learning Check Prozac, C17H18F3NO, is an antidepressant that inhibits the uptake of serotonin by the brain. What is the molar mass of Prozac? 1) g/mol 2) g/mol 3) g/mol

13 Solution 3) 309.3 g/mol 17C (12.01) + 18H (1.008) + 3F (19.00)
Prozac, C17H18F3NO, is an antidepressant that inhibits the uptake of serotonin by the brain. What is the molar mass of Prozac? 3) g/mol 17C (12.01) + 18H (1.008) + 3F (19.00) + 1N (14.01) + 1 O (16.00) = = g/mol


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