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Electrochemistry Lesson 3 Oxidation Numbers.

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Presentation on theme: "Electrochemistry Lesson 3 Oxidation Numbers."— Presentation transcript:

1 Electrochemistry Lesson 3 Oxidation Numbers

2 Ho Ho Ho Silver crystals on a copper frame

3 Oxidation Numbers HV2O4-  V6+ Is the above equation oxidation or reduction? Oxidation numbers are assigned numbers that are used to determine if oxidation or reduction has occurred.

4 Rules for Oxidation Numbers Oxidation #
1. All elements are zero: N2 Pb Na O2

5 Rules for Oxidation Numbers Oxidation #
2. Monatomic Ions are their charge Na+ +1 -1 Br- +2 MgSO4 -2 Al2S3

6 Rules for Oxidation Numbers Oxidation #
3. O in a compound is -2 exception: peroxides -1 Na2O -2 CO2 -2 O2 CH3COOH -2 -1 exception HOOH

7 Rules for Oxidation Numbers Oxidation #
4. H in a compound is +1 exception: metal hydrides -1 H2O +1 +1 C12H22O11 H2 -1 NaH

8 oxidation #s SO42- Total charge +6 -2 -2 x 4 +6 -8 = -2
Rules for Oxidation Numbers 5. The sum of the oxidation numbers must equal the charge oxidation #s SO42- Total charge +6 -2 -2 x 4 +6 -8 = -2

9 oxidation #s PO43- Total charge +5 -2 +5 -8 = -3

10 oxidation #s Cr2O72- Total charge +6 -2 12 / 2 +12 -14 = -2

11 Ca(NO3)2 +2

12 Na2C4O8 +1 +7/2 -2 +2 +14 -16 = 0

13 CH3COOH

14 Rewrite C2H4O2 +1 -2 +4 -4 = 0

15 Zn(OH)42- +2 -2 +1 +2 -8 +4 = -2

16 H2PtCl6 +1 +4 -1 +2 +4 -6 = 0

17 H3PO3 +1 +3 -2 +3 +3 -6 = 0

18 Al(NO3)3 +3 +5 -2 +3 +15 -18 = 0

19 Na2O2 Exception - does not work, O must be -1 +1 -1 -2 +2 -2 -4 = 0

20 CaH2 +2 +1 -1 +2 +2 -2 = 0 Exception - does not work, H must be -1

21 Fe(H2O)5(OH)2+

22 Fe(H2O)5(OH) ? = +2

23 Fe(H2O)5(OH) = +2

24 Is the above equation oxidation or reduction?
Oxidation Numbers HV2O4-  V6+ Is the above equation oxidation or reduction? Increase +6 +3 If the oxidation number increases it is oxidation.

25 Using Oxidation Numbers
If the oxidation number of the central atom increases going from left to right, its oxidation. ClO2-  ClO4- Increase is oxidation +3 +7 oxidation reducing agent 4 electrons lost

26 Using Oxidation Numbers
If the oxidation number of the central atom decreases going from left to right, its reduction. NO3-  HNO2 +5 +3 decrease is reduction reduction 2 electrons gained oxidizing agent

27 Label the oxidizing agent and the reducing agent.
ReO4- + IO-  IO3- + Re Reduced Oxidized Ox Agent Red Agent

28 Label the oxidizing agent and the reducing agent. +3 +5 +5 +2
3As2O NO H2O + 4H+  6H3AsO NO oxidized reduced red agent ox agent Numa Numa


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