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BHASVIC MΞ±THS Skills 1 A1 DOUBLES ASSIGNMENT 13B
The diagram shows a sketch of the graph of π¦=π π₯ . The curve has a minimum at the point A (1, -1) passed through x-axis at the origin, and the points B (2, 0) and C (5, 0); the asymptotes have equations x = 3 and y = 2. Sketch on separate axes, the graph of (i) π¦= π π₯ (ii) π¦=βπ π₯+1 (iii) π¦=π β2π₯ State the number of solutions to the equation (i) 3 π π₯ =2 (ii) 2 π π₯ =3
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BHASVIC MΞ±THS Skills 2 A1 DOUBLES ASSIGNMENT 13B Let f(x) = 3 π₯ 2 β2.
g(x) = π₯ 3 β1 Find the derivative of the following: (a) f(x) (b) g(x) (c) f(x) g(x) (d) π π₯ π π₯
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BHASVIC MΞ±THS Skills 1 - Answers A1 DOUBLES ASSIGNMENT 13B
(a) (i) (ii) (iii) (b) (i) (ii) 4
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BHASVIC MΞ±THS Skills 2 β Answers A1 DOUBLES ASSIGNMENT 13B 6x 3 π₯ 2
15 π₯ 4 β6 π₯ 2 β6π₯ β3 π₯ 4 +6 π₯ 2 β6π₯ π₯ 3 β1 2
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BHASVIC MΞ±THS 1 A1 DOUBLES ASSIGNMENT 13B
Find the value of k for which π¦=3π₯+1 is a tangent to the curve π₯ 2 + π¦ 2 =π
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BHASVIC MΞ±THS 2 A1 DOUBLES ASSIGNMENT 13B
The function k is defined by k π₯ = π π₯ 2 , π>0, π₯ββ, π₯β 0 (a) Sketch the graph of π¦=k π₯ . (b) Explain why it is not necessary to sketch π¦= k π₯ and π¦=k π₯ . The function m is defined by m π₯ = π π₯ 2 , π<0, π₯ββ, π₯β 0. (c) Sketch the graph of π¦=m π₯ (d) State with a reason whether the following statements are true or false. (i) k π₯ = m π₯ (ii) k π₯ =m π₯ (iii) m π₯ =m π₯
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BHASVIC MΞ±THS 3 A1 DOUBLES ASSIGNMENT 13B
Two particles A and B have masses m kg and 3 kg respectively, where π>3. The particles are connected by a light inextensible string which passes over a smooth, fixed pulley. Initially A is 2.5 m above horizontal ground. The particles are released from rest with the string taut and the hanging parts of the string vertical, as shown I the figure. After A has been descending for 1.25 s, it strikes the ground. Particle A reaches the ground before B has reached the pulley. Show that the acceleration of B as it ascends if 3.2 m s-2. Find the tension in the string as A descends. Show that π= State how you have used the information that the string is inextensible. When A strikes the ground it does not rebound and the string becomes slack. Particle B then moves freely under gravity, without reaching the pulley, until the string becomes taut again. (e) Find the time between the instant when A strikes the ground and the instant when the string becomes taut again.
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BHASVIC MΞ±THS 4 A1 DOUBLES ASSIGNMENT 13B
A parcel of mass 8 kg rests on a smooth slope, and is connected by a light inextensible string which passes over a smooth pulley to a mass of 2kg, which hangs freely. The system is in equilibrium. Find the angle of the slope.
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BHASVIC MΞ±THS 5 A1 DOUBLES ASSIGNMENT 13B
A projectile is launched from a point on a horizontal plane with initial speed u m s -1 at an angle of elevation πΌ. The particle moves freely under gravity until it strikes the plane. The range of the projectile is R m. Show that the time of flight of the particle is 2π’ sin πΌ π seconds Show that π
= π 2 sin 2πΌ π . Deduce that, for a fixed u, the greatest possible range is when πΌ=45Β° Given that π
= 2 π’ 2 5π , find the two possible values of the angle of elevation at which the projectile could have been launched.
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BHASVIC MΞ±THS 6 A1 DOUBLES ASSIGNMENT 13B
The diagram shows a cuboid whose vertices are O, A, B, C, D, E, F and G. a, b, and c are the position vectors of the vertices A, B, and C respectively. The point M lies on OE such that O M : M E = 3 : 1. the straight line AP passes through point M. Given that A M : M P = 3 : 1, prove that P lies on the line EF and find the ratio F P : P E.
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BHASVIC MΞ±THS 7 A1 DOUBLES ASSIGNMENT 13B
(a) Prove, from first principles, that the derivative of 2 π₯ 3 is 6 π₯ 2 (b) Prove, from first principles, that the derivative of sin 2x is 2cos2x
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BHASVIC MΞ±THS 8 A1 DOUBLES ASSIGNMENT 13B
Given that f π₯ = 2π₯ π₯+5 + 6π₯ π₯ 2 +7π₯+10 , π₯>10 (a) Show that π π₯ = 2π₯ π₯+2 (b) Hence find fβ² 3
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BHASVIC MΞ±THS 9 A1 DOUBLES ASSIGNMENT 13B
The normal to the curve π¦= sec 2π₯ at the point π π 4 , 2 meets the line π¦=π₯ at the point Q. Find the exact coordinates of Q.
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BHASVIC MΞ±THS 10 A1 DOUBLES ASSIGNMENT 13B
The gradient of a curve is given by π β² π₯ = π₯ 2 β3π₯β 2 π₯ Given that the curve passes through the point (1, 1), find the equation of the curve in the form π¦=π(π₯).
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BHASVIC MΞ±THS 11 A1 DOUBLES ASSIGNMENT 13B
For each of these functions, find the inverse function, π β1 π₯ and state its domain: (i) π π₯ = π₯+6 5 , π₯ββ (ii) π π₯ = 5 π₯ , π₯ββ:π₯β 0 (iii) π:π₯β π₯+4 , π₯ββ:π₯β₯β4 (iv) π:π₯β 3π₯+2 π₯β1 , π₯ββ:π₯β 1 (b) (i) State why the inverse f-1(x) does not exist for π:π₯β2|(π₯β3 ) 2 β5 π₯ββ (ii) Change the domain of the above function so that the inverse does exist.
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BHASVIC MΞ±THS 12 A1 DOUBLES ASSIGNMENT 13B
By solving the equation π§ 4 +6 π§ 2 +25=0 for π§ 2 , or otherwise, express each of the four roots of the equation in the form π₯+ππ¦.
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 13B 1 - Answers π= 1 10
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BHASVIC MΞ±THS 2 - Answers A1 DOUBLES ASSIGNMENT 13B (a)
(b) Both these graphs would match the original graph. (c) (d) (i) True, π π₯ = π π₯ 2 = βπ π₯ 2 = π π₯ (ii) False, π π₯ = π π₯ 2 β βπ π₯ 2 =π π₯ (iii) True, π π₯ = βπ π₯ 2 = βπ π₯ 2 =π π₯
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BHASVIC MΞ±THS 3 - Answers A1 DOUBLES ASSIGNMENT 13B
(a) π =π’π‘+ 1 2 π π‘ 2 so 2.5= ΓπΓ , π=3.2 ms-2 (b) 39 N (c) For A, π
β :ππβπ=ππ π=π 9.8β3.2 , π=6.6π Substituting for π:39=6.6π π= 65 11 (d) Same tension in string either side of the pulley. (e) s
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 13B 4 - Answers 14.5o
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BHASVIC MΞ±THS 5 - Answers A1 DOUBLES ASSIGNMENT 13B
12Β° and 78Β° (nearest degree)
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BHASVIC MΞ±THS 6 - Answers A1 DOUBLES ASSIGNMENT 13B
Show that πΉπ = 2 3 a (multiple methods possible) Show that ππΈ = 1 3 a (multiple methods possible) Therefore FP and PE are parallel, so P lies on FE FP:PE = 2 : 1
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 13B 7 - Answers Proof
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BHASVIC MΞ±THS 8 - Answers A1 DOUBLES ASSIGNMENT 13B
= 2π₯ π₯ π₯+5 π₯+2 = 2π₯ π₯+5 π₯+5 π₯+2 = 2π₯ π₯+2 (b) 4 25
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 13B 9 - Answers π¦=4π₯βπ+2
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BHASVIC MΞ±THS 10 - Answers A1 DOUBLES ASSIGNMENT 13B
π¦= π₯ 3 3 β 3 2 π₯ 2 +2 π₯ β
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BHASVIC MΞ±THS 11 - Answers A1 DOUBLES ASSIGNMENT 13B
(a) (i) f β1(x) = 5x β 6, x οR (ii) f β1(x) = 5/x, {x ο R: x β 0} (iii) f β1 : x β x2 β 4, {x οR: x β₯ 0} (iv) f β1 : x β (x + 2)/(x β 3), {x οR: x β 3} (b) (i) The inverse is a 1 to many function (3bii) x ο R, x > 3 (ii) X β₯ 3
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 13B 12 - Answers Β± 1+2π ; Β± 1β2π
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