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Warm Up Test Friday HW- Solving Quadratics Worksheet
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Homework Check
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Lesson: Solving Quadratics
February 11, 2014
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Now we are going to talk about quadratic equations
Recallβ¦β¦.. What have we learned so far about quadratic functions? Now we are going to talk about quadratic equations The standard form of a quadratic equation is ππ π +ππ+π =0
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Solving Quadratic Equations
Quadratic equations can be solved by a variety of methods, including graphing and finding square roots. When solving the quadratic equation( ππ π +ππ+π=π ) by graphing the solutions of the equation are the x-intercepts of the related function. We have talked about x-intercepts before in our unit on functions, what can you recall about x-intercepts?
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Solving by Graphing The solutions of a quadratic equation and the x-intercepts of the graph of the related function are often called roots of the equation or zeros of the function. Letβs practice finding the solutions by graphing
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Solving by factoring We have just learned many ways to factor polynomials in the standard form ππ π +ππ+π, we can also use this to help us find solutions. Letβs factor the following π π βππ If you recall the standard form of a quadratic equation is ππ π + ππ+π=πall we have to do is set our answer to zero and solve for x to get our zeros. (Can you see where they got the term zero from)
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Solving by Factoring We can use something called the zero-product property to help us find the zeros. Letβs use the problem we just factored and set equal to zero. Using the zero product property
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Using the Zero-Product Property
What are the solutions of the following equations? (4t + 1) (t β 2 )=0 (x + 1)(x β 5)= 0 (2x + 3)(x β 4)=0 (7n - 2)(5n β 4)=0
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Solving by Factoring Factor and solve the following to find the solutions π₯ 2 +8π₯+15=0 What about this one? 4π₯ 2 β21π₯=18
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Solving by Using Square Roots
You can solve equations of the form π₯ 2 =π by finding the square roots of each side. Example: 3π₯ 2 β75=0
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Solve by Using Square Roots
What are the solutions of each equation? π 2 β36=0 3π₯ 2 +15=0 4π 2 +16=16
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Independent Practice Time
Time to do more problems without me!!!
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Exit Ticket What are the solutions to the following? 3π₯ 2 β27π₯+54=0
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