1. Happy New Year!! HMWK: Start Part 7 HP posted on Weebly – due 1/11
Warm-up… on loose leaf
How many moles are in  3 L of a 1.2 M solution?
2. Given the equation 2SO2 + O2 → 2SO3:
a. Which way will equilibrium shift if O2 is added?
b. Which way will equilibrium shift if O2 is taken away?
c. Write the equilibrium expression for the reaction.  (Note:  all are gases)
 How many moles are in 45 g of LiCl?
4. If you take that amount of moles and dissolve it in 5 L of water, what is the concentration of the solution?

2. ANSWERS How many moles are in 3 L of a 1.2 M solution?
M = m M = 0.4 moles
L L.
2. Given the equation 2SO2 + O2 → 2SO3:
Which way will equilibrium shift if O2 is added?
To the right to use up what is added.
b. Which way will equilibrium shift if O2 is taken away?
To the left to replace what is lost
c. Write the equilibrium expression for the reaction.  (Note:  all are gases)
Keq = [SO3] 2
[ SO2]2 [O2]1
 How many moles are in 45 g of LiCl?
45 g LiCl x 1 mole LiCl = moles LiCl
g LiCl
If you take that amount of moles and dissolve it in 5 L of water, what is the concentration of the solution? Molarity = M M LiCl = M LiCL
L L

3. Acids and Bases Introduction
Get a note guide and NCFE exam review packet off the front table.
Sit in your assigned seat and put your phone away!
HMWK:
Part 7 HP posted to Weebly–due 1/11
Work on last page of NCFE review packet on pH

4. Acids Sour taste Examples: HCl (stomach acid), H2SO4
HC2H3O2 (acetic acid) – (vinegar = acetic acid & water)
Citric acid (lemon juice)
Electrolyte
Releases H+ when dissolved in water, producing hydronium ions! H+ + H2O  H3O+
Hydronium ions are the hydrated form of H+

5. Acids (cont’d) React with metals to produce H2 gas.
Ex. HCl + Zn  ZnCl2 + H2
When diluting acids, always slowly pour the acid into water while stirring.
Acid/Base Indicators:
Turns litmus paper RED.
Phenolphthalein does not change color.

6. Bases Bitter taste, slippery feel
Examples: NaOH, Mg(OH)2 (milk of magnesia), NH3 (ammonia), soap, household cleaners
Releases OH- (hydroxide ions) when dissolved in water.
Electrolyte.
Acid/Base Indicators:
Turns litmus paper BLUE.
Phenolphthalein turns bright pink.

7. Neutralization Reaction
ACID + BASE  SALT + WATER
Salt: ionic compound formed from the negative part of the acid and the positive part of the base.
Example:
  2HCl + Mg(OH)2 MgCl2 + 2H2O
What type of reaction is this? Synthesis, Decomposition, Single Replacement, Double Replacement, or Combustion?

8. Complete and Balance the Neutralization Reactions
HCl + NaOH 
HC2H3O2 + Ca(OH)2 
HBr + Al(OH)3 
NaCl + H2O
Ca(C2H3O2)2 + H2O
AlBr3 + H2O

9. Naming Acids
Acids are a group of ionic compounds with unique properties.
An acid is a compound that contains one or more hydrogen atoms and produces hydrogen ions (H+) when dissolved in water.
Chemical formula of an acid: HnX
X = monatomic anion or polyatomic anion
n = number of hydrogen atoms

10. How to name an acid… Depends on the name of the ANION
1. When the name of the anion (X) ends in –ide
A. The acid name begins with the prefix hydro-
B. The stem of the anion has a suffix –ic followed by the word acid
Example: HCl – (X = chloride) hydrochloric acid
2. When the name of the anion (X) ends in –ite
A. The stem of the anion has a suffix –ous, followed by the word acid
Example: H2SO3 – (X = sulfite) sulfurous acid
3. When the name of the anion (X) ends in –ate
A. The stem of the anion has a suffix –ic, followed by the word acid
Example: H3PO4 – (X = phosphate) phosphoric acid

11. Naming Common Acids -ide Chloride, Cl- Hydro-(stem)-ic acid
Textbook Table 9.5
Anion Ending
Example
Acid Name
-ide
Chloride, Cl-
Hydro-(stem)-ic acid
Hydrochloric acid
-ite
Sulfite, SO32-
(stem)-ous acid
Sulfurous acid
-ate
Phospate, PO43-
(stem)-ic acid
Phosphoric acid

12. Practice: H2S HNO2 H2CO3 HC2H3O2 HF H2O Hydrosulfuric acid
X = sulfide
Hydrosulfuric acid
X = nitrite
Nitrous acid
X = carbonate
Carbonic acid
Acetic acid
X = acetate
X = fluoride
Hydrofluoric acid
Water is NOT an Acid pH = 7
X = oxide
Dihydrogen monoxide

13. More practice Complete the neutralization reactions.
HNO3 + Ca(OH)2 
HCN + NaOH 
H3PO4 + Ni(OH)2 
Name the following acids. HI
H2SO3
HClO4

14. Naming Bases
A base is an ionic compound that produces hydroxide ions when dissolved in water.
Bases are named in the same way as other ionic compounds
The name of the cation, followed by the name of the anion
Anion will always be hydroxide (OH1-)
Exception: NH3 - ammonia

15. Practice: LiOH Al(OH)3 Fe(OH)3 Mg(OH)2 Pb(OH)2 OH Lithium hydroxide
Aluminum hydroxide
Iron (III) hydroxide
Magnesium hydroxide
Lead (II) hydroxide
Hydroxide

16. Thursday…
Get out pH note packet from yesterday!
HMWK:
Work on pH page of NCFE packet.
HP part 7 due Wednesday… 1/11/17

17. 3 Definitions of Acids & Bases
1) Arrhenius Theory
Acids: ionize to produce H+ ions in aqueous solution
Monoprotic: HNO3, HCl, HC2H3O2
Diprotic: H2SO4, H2SO3
Triprotic: H3PO4
HNO3  NO3- + H+
H2SO4  SO H+

18. Arrhenius Theory cont.
Bases: dissociate to produce OH- ions in aqueous solution
NaOH, KOH, Ca(OH)2, Al(OH)3
NaOH  Na+ + OH-
Ca(OH)2  Ca2+ + 2OH-

19. Definitions (cont’d) 2) Brønsted-Lowry Theory
Hydrogen ion (H+) = a proton
Acids: proton donors – ex. HCl
Bases: proton acceptors – ex. NH3

20. Conjugate Acids and Bases
A conjugate acid is the product that ACCEPTS the proton
A Conjugate base is the product that DONTATES the proton
Label: Acid, Base, Conjugate Base, Conjugate Acid
NH3 (aq) + H2O (l) NH4+ (aq) + OH- (aq)
HCl (g) + H2O (l) H3O+ (aq) + Cl- (aq)
BASE ACID CA CB
ACID BASE CA CB

21. More Examples ACID BASE CB CA ACID BASE CB CA
Show the direction of H+ transfer.
Label: Acid, Base, Conjugate Base, Conjugate Acid
H2SO4 + OH- HSO41- + H2O
HSO41- + H2O SO42- + H3O+
ACID BASE CB CA
ACID BASE CB CA

22. Practice
For the following equations, label the acid, base, conjugate acid, and conjugate base.
Remember you are following the PROTON transfer.
HNO2 + H2O  NO2- + H3O+
HCl + NH3  NH4+ + Cl-

23. Definitions (cont’d)
3) Lewis Theory
Acids: electron-pair acceptor
Bases: electron-pair donor
HCl (g) + H2O (l) H3O+ (aq) + Cl- (aq)
In the equation above, which compound is accepting the electron pair and which is donating?
WORKSHEET on pH.. Due at the end of the period
HCl ACCEPTS e- pair
H2O DONATES e- pair

24. Friday… 1-6-17 Get out pH note packet… HMWK:
Work on pH page of NCFE packet.
HP part 7 due Wednesday… 1/11/17
Test on Solutions, Equilibrium and pH on Wed. 1/11/17

25. pH Scale

26. pH Scale
pH Scale: logarithmic scale in which [H+] is expressed as a number from 0 to 14.

27. pH Scale Acidic Neutral Basic 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
COPY THIS ON YOUR PAPER!!
[H+]
[OH-]

28. pH – Examples (no calculator)
What is the pH if [HCl] = 1 x 10-4 M?
What is the [H+] if the pH = 9?
What is the pH if [NaOH] = 1 x 10-2 M
What is the concentration of [OH-] if the pOH is 3?
5)What is the concentration of [H+] if the pOH is 10? 4
1 x 10-9 12
1 x 10-3
1 x 10-4

29. pH calculations – easy practice
What is the pH of the solution?
[H3O+] = 1 x 10-4 M
[H+] = 1 x M
[HCl] = 1 x 10-2 M
What is the concentration of H3O+ if the pH is 5?
What is the concentration of H+ if the pH is 11?

30. pH calculations – easy practice
What is the pH of the solution?
[H3O+] = 1 x 10-4 M 4
[H+] = 1 x M 10
[HCl] = 1 x 10-2 M 2
What is the concentration of H3O+ if the pH is 5? 1 x 10 -5
What is the concentration of H+ if the pH is 11? 1 x

31. (cont’d) What is the pOH of each solution? [OH-] = 1 x 10-4 M
[NaOH] = 1 x M
What is the pH of a solution if the pOH is 4?
What is the pH of each solution?
[OH-] = 1 x 10-8 M
[KOH] = 1 x 10-3 M
What is the [H3O+] in a solution if [OH-] = 1 x 10-3 M?
What is the [OH-] in a solution if [H3O+] = 1x 10-5 M?

32. What is the pOH of each solution?
[OH-] = 1 x 10-4 M 4
[NaOH] = 1 x M 10
What is the pH of a solution if the pOH is 4? 10
What is the pH of each solution?
[OH-] = 1 x 10-8 M 6
[KOH] = 1 x 10-3 M 11
What is the [H3O+] in a solution if [OH-] = 1 x 10-3 M?
1 x
8) What is the [OH-] in a solution if [H3O+] = 1x 10-5 M?
1 x 10-9

33. pH equations pH= - log [H+] pOH = - log [OH-] pH + pOH = 14
[H+] x [OH-] = 1 x 10-14

34. Practice – Using the equations
Find the pH of the following solutions. Is the solution acidic or basic?
0.01 M HCl
0.050 M Ca(OH)2
2.6 x M Mg(OH)2
1 x 10-7 M HC2H3O2
Find the concentration of hydrogen ions if the pH is 3.
Find the concentration of hydroxide ions if the pH is 5.6.
Find the [H3O+] in a solution if [OH-] = 3 x 10-6 M
pH = 2
pH = 12.7
2.4 7
1 x 10-3
3.98 x 10(-9)
3.33 x 10(-9)

35. pH= - log [ 0.05] pOH =1.3  pH =12.7 Base 2.6 x 10-12 M Mg(OH)2
0.01 M HCl pH= - log [0.01] = 2 Acid
0.050 M Ca(OH)2
pH= - log [ 0.05] pOH =1.3  pH =12.7 Base
2.6 x M Mg(OH)2
pH= - log [ 2.6 x 10-12] pOH = so pH = 2.5 Acid
1 x 10-7 M HC2H3O2 pH = -log 1 x pH =7 Neutral
Find the concentration of hydrogen ions if the pH is 3.
1 x 10 -3
Find the concentration of hydroxide ions if the pH is 5.6. pOH = = -log [OH]- 4 x 10 -9
Find the [H3O+] in a solution if [OH-] = 3 x 10-6 M
H+ + OH - = 3x M Solve for H+ x = 3.33 x 10 -9
pH = 2
pH = 12.7
2.4 7
1 x 10-3
3.98 x 10(-9)
3.33 x 10(-9)

36. Welcome back!! Let’s pick up where we left off…
get out your pH notes from Friday and a calculator.
Then pH lab…..
HMWK:
HP part 7 due and last test on ….

37. Find the concentration of hydroxide ions if the pH is 5. 6. pOH = 8
Find the concentration of hydroxide ions if the pH is 5.6. pOH = = -log [OH] divide by -1 on each side… gives you..
-8.4 = log [OH] there is no special base so this is log base ten which means….
[OH] =  4 x 10 -9
Find the [H+] in a solution if [OH-] = 3 x 10-6 M
[H+] x [OH-]= 1 x Solve for [H+]
[H+] x [3x10-6] = 1 x
[3x10-6] [3x10-6]
[H+] = 3.33 x 10 -9

38. Strong Acids and Bases Strong Acids: completely ionize in water
Ex. HCl, HBr, HI, HNO3, H2SO4, HClO3
Strong Bases: completely dissociate into ions in water
Ex. NaOH, LiOH, KOH, Ca(OH)2, Sr(OH)2, Ba(OH)2

39. Weak Acids and Bases Weak Acids: only some molecules ionize in water
Ex: acetic acid (less than 0.5% of molecules ionize)
Weak Bases: do not completely dissociate into ions in water
Ex: ammonia (only 0.5% of molecules dissociate)

40. Concentrated vs. Strong
“Concentrated” – refers to the amount dissolved in solution.
“Strong” – refers to the fraction of molecules that ionize.  
For example, if you put a lot of ammonia into a little water, you will create a highly concentrated solution. However, since only 0.5% of ammonia molecules ionize in water, this basic solution will not be very strong.

41. Acid-Base Titration
Uses a neutralization reaction to determine the concentration of an acid or base.
Standard Solution: the reactant that has a known molarity
Endpoint: the point at which the unknown has been neutralized.

42. Make sure you finish with correct units!!
Titration Examples
Example #1) .08 L of 0.100M NaOH is used to neutralize .02 L of HCl. What is the molarity of HCl? NaOH + HCl  NaCl + H2O
.08 L NaOH x .100 mols NaOH x 1 mol HCl x =
1 L NaOH mol NaOH L HCl
0.4 M
Molarity of NaOH
Molar Ratio
Make sure you finish with correct units!!

43. Titration Examples (cont’d)
Example #2) A 0.1M Mg(OH)2 solution was used to titrate an HBr solution of unknown concentration. At the endpoint, 21.0 mL of Mg(OH)2 solution had neutralized 10.0 mL of HBr. What is the molarity of the HBr solution?
MAVA = MBVB
0.1 x 21 ml = ? X 10 ml
X = 0.21 M HBr

44. Titration examples can be done with….
M1V1 = M2 V2
Or MAVA = MBVB

45. Titration Practice M = 1.4 M HPO4 .3M x 35ml = 10ml x M M = 10.5 HCl
What is the molarity of an Al(OH)3 solution if 30.0 mL of the solution is neutralized by 26.4 mL of a 0.25 M HBr solution?
30 ml x M = 26.4 x 0.25
.22M Al 9(OH3)
2) A 0.3 Ca(OH)2 solution was used to titrate an HCl solution of unknown concentration. At the endpoint, 35.0 mL of Ca(OH)2 solution had neutralized 10.0 mL of HCl. What is the molarity of the HCl solution?
.3M x 35ml = 10ml x M
M = 10.5 HCl
3) When 34.2 mL of a 1.02 M NaOH solution is added from a buret to mL of a phosphoric acid solution that contains phenolphthalein, the solution changes from colorless to pink.  What is the molarity of the phosphoric acid? 34.2ml x 1.02 M = 25 ml x M
M = 1.4 M HPO4