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The Effective Value of an Alternating Current (or Voltage)
© David Hoult 2009
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If the two bulbs light to the same brightness (that is, they have the same power) then it is reasonable to consider the current Iac to be (in some ways) equivalent to the current Idc
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If the two bulbs light to the same brightness (that is, they have the same power) then it is reasonable to consider the current Iac to be (in some ways) equivalent to the current Idc The simple average value of a (symmetrical) a.c. is equal to
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If the two bulbs light to the same brightness (that is, they have the same power) then it is reasonable to consider the current Iac to be (in some ways) equivalent to the current Idc The simple average value of a (symmetrical) a.c. is equal to zero
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The R.M.S. Value of an Alternating Current (or Voltage)
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If an a.c. supply is connected to a component of resistance R, the instantaneous power dissipated is given by
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If an a.c. supply is connected to a component of resistance R, the instantaneous power dissipated is given by power = i2 R
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The mean (average) power is given by
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The mean (average) power is given by
mean power = (mean value of i2) R
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The mean value of i2 is
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I2 The mean value of i2 is 2
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The square root of this figure indicates the effective value of the alternating current
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The square root of this figure indicates the effective value of the alternating current
r.m.s. = root mean square
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I Irms = 2 where I is the maximum (or peak) value of the a.c.
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The r.m.s. value of an a.c. supply is equal to the direct current which would dissipate energy at the same rate in a given resistor
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The r.m.s. value of an a.c. supply is equal to the direct current which would dissipate energy at the same rate in a given resistor We can use the same logic to define the r.m.s. value of the voltage of an alternating voltage supply.
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The r.m.s. value of an a.c. supply is equal to the direct current which would dissipate energy at the same rate in a given resistor We can use the same logic to define the r.m.s. value of the voltage of an alternating voltage supply. V Vrms = 2 where V is the maximum (or peak) value of the voltage
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We have been considering a sinusoidal variation of current (or voltage)
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We have been considering a sinusoidal variation of current (or voltage)
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We have been considering a sinusoidal variation of current (or voltage)
For this variation, the r.m.s. value would be
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We have been considering a sinusoidal variation of current (or voltage)
For this variation, the r.m.s. value would be equal to the maximum value
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