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Bill Vining 232 PSCI 436-2698 viningwj@oneonta.edu Chemistry 112 Sections 1-7 Bill Vining 232 PSCI 436-2698 viningwj@oneonta.edu.

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Presentation on theme: "Bill Vining 232 PSCI 436-2698 viningwj@oneonta.edu Chemistry 112 Sections 1-7 Bill Vining 232 PSCI 436-2698 viningwj@oneonta.edu."— Presentation transcript:

1 Bill Vining 232 PSCI 436-2698 viningwj@oneonta.edu
Chemistry 112 Sections 1-7 Bill Vining 232 PSCI

2 Hess’s Law If you can add the reactions, you can add the H’s.

3 Hess’s Law Enthalpy is a State Function.

4 Rules for manipulating Reaction Equations
Reverse reactions: Change sign of H Multiple by a constant: Multiply sign of H by that constant

5 A. Mg + 2 HCl  MgCl2 + H2 B. MgO + 2 HCl  MgCl2 + H2O
Hess’s Law: Your Lab A. Mg + 2 HCl  MgCl2 + H2 0.52 g Mg mL 1 M HCl leads to 21 oC temperature increase B. MgO + 2 HCl  MgCl2 + H2O 0.71 g MgO mL 1 M HCl leads to a 4 oC temperature increase

6 Hess’s Law: Your Lab Mg(s) + ½ O2(g)  MgO(s) H = ???

7 Standard Enthalpy of Formation
Formation Reaction: Reaction that forms one mole of a compound from its elements in their natural states. K2CO3(s)?? Standard enthalpy of formation: Enthalpy change on forming one mole of a compound from its elements under standard conditions.

8

9 Elements!

10 Using Standard Enthalpy of Formation: Diagramatically

11 Using Standard Enthalpy of Formation: Mathematically
C3H8(g) + 5 O2(g)  3 CO2(g) + 4 H2O(l)

12 C3H8(g) + 5 O2(g)  3 CO2(g) + 4 H2O(l)
+2220 kJ -2220 kJ +574 kJ -574 kJ


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