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LU Decomposition http://numericalmethods.eng.usf.edu
Chemical Engineering Majors Authors: Autar Kaw Transforming Numerical Methods Education for STEM Undergraduates 11/29/2018
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LU Decomposition http://numericalmethods.eng.usf.edu
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LU Decomposition LU Decomposition is another method to solve a set of simultaneous linear equations Which is better, Gauss Elimination or LU Decomposition? To answer this, a closer look at LU decomposition is needed.
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LU Decomposition Method [A] = [L][U] where
For most non-singular matrix [A] that one could conduct Naïve Gauss Elimination forward elimination steps, one can always write it as [A] = [L][U] where [L] = lower triangular matrix [U] = upper triangular matrix
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How does LU Decomposition work?
If solving a set of linear equations [A][X] = [C] If [A] = [L][U] then [L][U][X] = [C] Multiply by [L]-1 Which gives [L]-1[L][U][X] = [L]-1[C] Remember [L]-1[L] = [I] which leads to [I][U][X] = [L]-1[C] Now, if [I][U] = [U] then [U][X] = [L]-1[C] Now, let [L]-1[C]=[Z] Which ends with [L][Z] = [C] (1) and [U][X] = [Z] (2)
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LU Decomposition How can this be used? Given [A][X] = [C]
Decompose [A] into [L] and [U] Solve [L][Z] = [C] for [Z] Solve [U][X] = [Z] for [X]
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When is LU Decomposition better than Gaussian Elimination?
To solve [A][X] = [B] Table. Time taken by methods where T = clock cycle time and n = size of the matrix So both methods are equally efficient. Gaussian Elimination LU Decomposition
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Time taken by Gaussian Elimination Time taken by LU Decomposition
To find inverse of [A] Time taken by Gaussian Elimination Time taken by LU Decomposition Table 1 Comparing computational times of finding inverse of a matrix using LU decomposition and Gaussian elimination. n 10 100 1000 10000 CT|inverse GE / CT|inverse LU 3.28 25.83 250.8 2501
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Method: [A] Decompose to [L] and [U]
[U] is the same as the coefficient matrix at the end of the forward elimination step. [L] is obtained using the multipliers that were used in the forward elimination process
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Using the Forward Elimination Procedure of Gauss Elimination
Finding the [U] matrix Using the Forward Elimination Procedure of Gauss Elimination Step 1:
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Finding the [U] Matrix Matrix after Step 1: Step 2:
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Using the multipliers used during the Forward Elimination Procedure
Finding the [L] matrix Using the multipliers used during the Forward Elimination Procedure From the first step of forward elimination
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Finding the [L] Matrix From the second step of forward elimination
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Does [L][U] = [A]? ?
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Example: Liquid-Liquid Extraction
A liquid-liquid extraction process conducted in the Electrochemical Materials Laboratory involved the extraction of nickel from the aqueous phase into an organic phase. A typical set of experimental data from the laboratory is given below: Ni aqueous phase, a (g/l) 2 2.5 3 Ni organic phase, g (g/l) 8.57 10 12 Assuming g is the amount of Ni in organic phase and a is the amount of Ni in the aqueous phase, the quadratic interpolant that estimates g is given by:
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Example: Liquid-Liquid Extraction
The solution for the unknowns x1, x2, and x3 is given by Find the values of x1, x2, and x3 using LU Decomposition. Estimate the amount of nickel in organic phase when 2.3 g/l is in the aqueous phase using quadratic interpolation
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Example: Liquid-Liquid Extraction
Use Forward Elimination to find the [U] matrix Step 1
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Example: Liquid-Liquid Extraction
The matrix after the 1st step: Step 2
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Example: Liquid-Liquid Extraction
Find the [L] matrix Use the multipliers from the Forward Elimination Procedure From the first step of forward elimination From the second step of forward elimination
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Example: Liquid-Liquid Extraction
Does [L][U] = [A]?
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Example: Liquid-Liquid Extraction
Set [L][Z] = [C] Solve for [Z]
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Example: Liquid-Liquid Extraction
Complete the forward substitution to solve for [Z]
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Example: Liquid-Liquid Extraction
Set [U][X] = [Z] Solve for [X] The 3 equations become
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Example: Liquid-Liquid Extraction
Solve for [X]
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Example: Liquid-Liquid Extraction
The Solution Vector is:
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Example: Liquid-Liquid Extraction
The polynomial that passes through the three data points is then Solution Where g is grams of nickel in the organic phase and a is the grams/liter in the aqueous phase. When 2.3g/l is in the aqueous phase, using quadratic interpolation, the estimated amount of nickel in the organic phase is
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Finding the inverse of a square matrix
The inverse [B] of a square matrix [A] is defined as [A][B] = [I] = [B][A]
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Finding the inverse of a square matrix
How can LU Decomposition be used to find the inverse? Assume the first column of [B] to be [b11 b12 … bn1]T Using this and the definition of matrix multiplication First column of [B] Second column of [B] The remaining columns in [B] can be found in the same manner
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Example: Inverse of a Matrix
Find the inverse of a square matrix [A] Using the decomposition procedure, the [L] and [U] matrices are found to be
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Example: Inverse of a Matrix
Solving for the each column of [B] requires two steps Solve [L] [Z] = [C] for [Z] Solve [U] [X] = [Z] for [X] Step 1: This generates the equations:
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Example: Inverse of a Matrix
Solving for [Z]
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Example: Inverse of a Matrix
Solving [U][X] = [Z] for [X]
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Example: Inverse of a Matrix
Using Backward Substitution So the first column of the inverse of [A] is:
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Example: Inverse of a Matrix
Repeating for the second and third columns of the inverse Second Column Third Column
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Example: Inverse of a Matrix
The inverse of [A] is To check your work do the following operation [A][A]-1 = [I] = [A]-1[A]
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Additional Resources For all resources on this topic such as digital audiovisual lectures, primers, textbook chapters, multiple-choice tests, worksheets in MATLAB, MATHEMATICA, MathCad and MAPLE, blogs, related physical problems, please visit
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