1. Connor, Kim, Erica & Arsel
Gay-Lussac's Law
Connor, Kim, Erica & Arsel

2. Joseph Louis Gay-Lussac (1778–1850)
A French chemist and physicist, Known for his studies on the physical properties of gases.
A balloon enthusiast as well, in 1804 he made a hot-air balloon ascent to a height of 20,000 feet in an early investigation of the Earth's atmosphere
In 1805, discovered that the basic composition of the atmosphere does not change with decreasing pressure
(increasing altitude).

3. Pressure-temperature law
Gay-Lussac’s Pressure-Temperature Law states that if the volume of a container is kept the same as the temperature of a gas goes up, the pressure in the container will also go up.
Temperature goes up- pressure goes down
Temperature goes down- pressure goes up
*only applies to gases with a constant volume

4. Mathematical relationship
The formula of Gay-Lussac’s law:
P stands for Pressure and T stands for temperature in kelvins.
P1 and T1 are the initial pressure and temperature and P2 and T2 are the final pressure and temperature.
Pressure can be in atmospheres or kilopascals.

5. Real life example
Pop: If a can of pop becomes heated, the can will explode.
Guy-Lussac’s law explains this, because as the temperature rises, the pressure inside the can increases at the same rate. As the pressure inside pushes outwards on the can, it will eventually explode.
Same goes if a can of pop if freezed

6. Practice Equation #1
A 20 L cylinder contains 6 atm of gas at 27°C. What would the pressure of the gas be if the gas was heated to 77 °C?
P1 = 6 atm
T1 = 27°C
P2 = ? atm
T2 = 77°C
Step 1: Convert from Celsius to Kelvin (K)
27°C = K
77°C = K

7. Answer: 7 ATM

8. Practice Equation #2
Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 °C to 30.0 °C.
P1: 1.00 atm
T1: 20.0 °C
P2: ?
T2: 30.0 °C

9. Answer 1.03 ATM

10. Practice Equation #3
If a gas in a closed container is pressurized from 12.0 atm to 25.0 atm and its original temperature was 32 C what would the final temperature of the gas be?
P1: 12.0atm
T1: 32 °C
P2: 25.0atm
T2: ?

11. Answer: K