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Expanding brackets and substitution
Slideshow 8, Room 307 Mathematics, Mr Richard Sasaki
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Objectives Recall how to substitute into expressions
Practice expanding brackets Expand brackets before substituting into expressions
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Substitution To substitute, we swap algebraic symbols for numbers so we can get a numeric answer. Example Calculate π₯+π¦ when π₯=4 and π¦=7. Try the short worksheet. π₯+π¦ = 4+7 = 11 Usual algebraic rules for expressions apply.
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Substitution Answers 9 2 56 144 75 32 8.5 ππ + ππ; π = ππ, π = πππ 67
830 Yen 12 4 π = π + π + π
+ π + π = (-3) π π + (-2) + (-27) + (-2.5) = -32 β π ππ + π ππ = -32 π ππ 8
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Expanding brackets To substitute numbers into expressions with brackets, it can be easier to expand them first. This lesson, we will expand each expression before substituting.
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= 32 + 24 = 56 = 4(2π₯ + 3π¦) 8π₯ + 12π¦ Expanding brackets Example
Simplify 4(2π₯ + 3π¦) and substitute π₯ = 4 and π¦ = 2 into it. 4(2π₯ + 3π¦) = 8π₯ + 12π¦ = Thatβs about it, try the last worksheets! 56 =
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Answers 18 36 6 ππππππ 72 π(ππ + ππ) 1 ππππ πππ π(ππ β ππ) 510
ππ+ππ 18 ππ β ππ 36 πππ β πππ 6 ππππππ 72 π(ππ + ππ) πππ ππ 1 π π πππ ππ + ππ ππππ πππ π(ππ β ππ) 510 πππ β πππ ( ) 8 -24 π=π π π π
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One last example. Example For π₯ + π¦ 2 , simplify and substitute for π₯ = 1 and π¦ = 2. Letβs try with substitution first. (1 + 2)2 = 9 How about expanding first? π₯2 + π¦2? Mmmβ¦ = 5 Well that didnβt work. π₯ + π¦ 2 β π₯2 + π¦2. So what is it?
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π₯2 π₯π¦ π¦π₯ π¦2 Letβs look at (x + y) 2 as an area. π₯ π¦ π₯
Here we want the total area. I made the size of π₯ look different to π¦ but this doesnβt matter. π¦π₯ π¦ π¦2
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So if we add each part together we getβ¦
π₯ + π¦ 2 = π₯2 + π₯π¦ +π¦π₯ + π¦2 = π₯2 + 2π₯π¦ + π¦2 How about π₯ β π¦ 2 ? And how about (π₯ + π¦)(π₯ β π¦)?
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