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Warmup: Graph f(x) = 4 + log3 (x+2) Check using document camera Check Homework using document camera Return Quiz 1 Go over Quiz 1 using doc camera
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Introduction to Compound Interest: a Develop Task
M3U3D5 Introduction to Compound Interest: a Develop Task Objective: Write expressions in equivalent forms to solve problems. Essential Question: How can we use logarithms to solve exponential equations involving compound interest?
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Turn to page 29. Work pages WITH Students
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Let’s summarize the properties we discovered and add a few more.
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NOTICE!!! 20 = 1 Log2 1 = 0 21 = 2 Log2 2 = 1 22 = 4 Log2 4 = 2 23 = 8 Log2 8 = 3 24 = 16 Log2 16 = 4 25 = 32 Log2 32 = 5
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Properties of Logarithms
There are four basic properties of logarithms that we have been working with. For every case, the base of the logarithm can not be equal to 1 and the values must all be positive (no negatives in logs)
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Change of Base Formula Example log58 =
This is also how you graph in another base. Enter y1=log(8)/log(5). Remember, you don’t have to enter the base when you’re in base 10!
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Product Rule logbMN = logbM + logbN Ex: logbxy = logbx + logby
Ex: log6 = log 2 + log 3 Ex: log39b = log39 + log3b
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Quotient Rule
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Power Rule
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These next two problems tend to be some of the trickiest to evaluate.
Actually, they are merely identities and the use of our simple rule will show this.
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Example 1: Solution: First, we write the problem with a variable.
Now take it out of the logarithmic form and write it in exponential form.
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Example 2: Solution: First, we write the problem with a variable.
Now take it out of the exponential form and write it in logarithmic form.
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If Loga ab = y then y = b AND…
Ask your teacher about the last two examples. They may show you a nice shortcut. If Loga ab = y then y = b AND… If aLoga b = y then y = b
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Finally, we want to take a look at the Property of Equality for Logarithmic Functions.
Basically, with logarithmic functions, if the bases match on both sides of the equal sign , then simply set the arguments equal.
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Example 3: Solution: Since the bases are both ‘3’ we simply set the arguments equal.
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Example 4: Solution: But we’re not finished… Solution:
Since the bases are both ‘8’ we simply set the arguments equal. Factor Solution: But we’re not finished…
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Example 4 continued… It appears that we have 2 solutions here.
If we take a closer look at the definition of a logarithm however, we will see that not only must we use positive bases, but also we see that the arguments must be positive as well. Therefore -2 is not a solution. Let’s end this lesson by taking a closer look at this.
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Our final concern then is to determine why logarithms like the one below are undefined.
Can anyone give us an explanation ?
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Example 5: One easy explanation is to simply rewrite this logarithm in exponential form. We’ll then see why a negative value is not permitted. First, we write the problem with a variable. Now take it out of the logarithmic form and write it in exponential form. What power of 2 would gives us -8 ? Hence expressions of this type are undefined.
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Classwork: p Homework: p. 25 #1-6 all,
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