1. You can use the table above to help you organize the information.
Assignment, red pen, pencil, highlighter, GP notebook, graphing calculator
U3D11
Have out:
Bellwork:
Last year the principal’s car was worth $28,000. Next year it will be worth $25,270.
FX – 133
a) What is the annual rate of depreciation?
year t
V(t)
last year
b) What is the car worth now? 1
now
next year 2
You can use the table above to help you organize the information.
total:

2. FX – 133
Last year the principal’s car was worth $28,000. Next year it will be worth $25,270.
a) What is the annual rate of depreciation?
V(t) = k(m)t
year t
V(t)
Initial value = $28,000 +1 +1 +1
multiplier = m
last year
28,000
25,270 = 28,000 m2
time = 2
V(t) = $25,270
28,000
28,000 1
now
100%
= m2 +1 +1
next year 2
25,270
– 95% 5% +1
0.95 = m +1
The annual rate of depreciation is 5%. +1
b) What is the car worth now?
The car is currently worth $26,600.
V(t) = 28,000(0.95)t +1
V(1) = 28,000(0.95)1 +1
total:
V(1) = $26,600 +1

3. Exponential Growth vs. Decay
Add to your notes:
Exponential Growth occurs when the multiplier is greater than 1. We also say the graph is “increasing.”
Graph: y x
Examples:
y = 2x
y = 1.5x
Exponential Decay occurs when the multiplier is between 0 and 1. (i.e., 0 < m < 1). We also say the graph is “decreasing.”
Graph:
Examples:
y = 0.84x y x
y = 0.3x

4. When you finish with the quiz,
Quiz Time!
It’s…
Clear your desk except for a pencil, highlighter, and a NON-graphing calculator.
When you finish with the quiz,
work on the worksheet.

5. It’s time to grade Quiz #2.
Take out a red pen.
It’s time to grade Quiz #2.