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Objective- To differentiate between probability and relative frequency and to solve problems involving both. If a woman were to have a baby in 1990, what.

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Presentation on theme: "Objective- To differentiate between probability and relative frequency and to solve problems involving both. If a woman were to have a baby in 1990, what."— Presentation transcript:

1 Objective- To differentiate between probability and relative frequency and to solve problems involving both. If a woman were to have a baby in 1990, what is the probability that it would be a boy? # of favorable outcomes Probability = # of possible outcomes boy 1 P (boy) = = = 50 % boy or girl 2 Probability involves predicting future events.

2 Probability involves predicting future events.
Relative Frequency involves data from past events. # of times an event occurred Relative Frequency = # of times it could have occurred # of boys born in 1990 2,129,000 r = = 0.512 total # of births in 1990 4,158,000 r % Based on relative frequency, the probability of having a boy is actually 51.2%.

3 In 1990, the state of Illinois tested 3840 skunks for rabies, of which 1446 actually had rabies. What was the relative frequency of skunks with rabies? frequency 1446 r = = 0.377 total opportunities 3840 r %

4 If a hurricane is likely to occur on any day of
the week, what is the probability that it will occur on a weekend? # of days in weekend 2 P (hurricane) = = # of days in week 7 2 or % 7

5 Probability and relative frequency are always
expressed as fractions ( or decimals ) between 0 and 1. Probability-future impossible certain Relative Frequency-past never occurred always occurred

6 + = 1 Complementary Events Two events are complementary if their
intersection is the empty set and their union is the set of all possible outcomes. Complementary P(Hurricane on weekend) P(Hurricane on weekday) + = 1 The sum of probabilities for complementary events always equals 1. P(It will rain) P(It will not rain) 30% % = 100%


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