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Nucleophilic substitution and elimination reactions
Alkyl halides Nucleophilic substitution and elimination reactions
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Alkyl halides - industrial sources
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Alkyl halides - industrial sources
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Preparation from alcohols
SOCl2 - thionyl chloride
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Halogenation of hydrocarbons
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Addition of HX to alkenes
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Addition of halogens to alkenes and alkynes
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Finkelstein reaction
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Nucleophilic substitution reactions
The halide ion is the conjugate base of a strong acid. It is therefore a very weak base and little disposed to share its electrons. When bonded to a carbon, the halogen is easily displaced as a halide ion by stronger nucleophiles - it is a good leaving group. The typical reaction of alkyl halides is a nucleophilic substitution:
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Nucleophiles reagents that seek electron deficient centres
negative ions or neutral molecules having at least one unshared pair of electrons
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Leaving groups a substituent that can leave as a weakly basic molecule or ion
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Nucleophilic substitution
A knowledge of how reaction rates depend on reactant concentrations provides invaluable information about reaction mechanisms. What is known about this reaction?
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Nucleophilic substitution
[CH3Br]I [OH-]I initial rate 0.001 M 1.0 M 3 x 10-7 molL-1s-1 0.002 M 1.0 M 6 x 10-7 molL-1s-1 0.002 M 2.0 M 1.2 x 10-6 molL-1s-1 rate a [CH3Br] [OH-] rate = k[CH3Br][OH-]
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Order - a summary The order of a reaction is equal to the sum of the exponents in the rate equation. Thus for the rate equation rate = k[A]m[B]n, the overall order is m + n. The order with respect to A is m and the order with respect to B is n.
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Nucleophilic substitution
[(CH3)3CBr]I [OH-]I initial rate 0.001 M M 4 x 10-7 molL-1s-1 0.002 M 1.0 M 8 x 10-7 molL-1s-1 0.002 M 2.0 M 8 x 10-7 molL-1s-1 rate a [(CH3)3CBr] [OH-]0 rate = k[(CH3)3CBr]
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The SN2 mechanism rate = k[CH3Br][OH-] References of interest:
E.D. Hughes, C.K. Ingold, and C.S. Patel, J. Chem. Soc., 526 (1933) J.L. Gleave, E.D. Hughes and C.K. Ingold, J. Chem. Soc., 236 (1935)
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Stereochemistry of the SN2 reaction
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Stereochemistry of the SN2 reaction
A Walden inversion. P. Walden, Uber die vermeintliche optische Activät der Chlorumarsäure und über optisch active Halogen-bernsteinsäre, Ber., 26, 210 (1893)
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The SN1 mechanism
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Carbocations G.A. Olah, J. Amer. Chem. Soc., 94, 808 (1972)
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Carbocation stability
Hyperconjugation stabilizes the positive charge.
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Stereochemical consequences of a carbocation
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Stereochemical consequences of a carbocation
Why?
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Stereochemical consequences of a carbocation
retention inversion predominates
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Carbocation rearrangements
Williamson ether synthesis a rearrangement and elimination
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Carbocation rearrangements
1,2 hydride and alkyl shifts
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Carbocation rearrangements
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Steric effects in the SN2 reaction
Look at the transition state to see how substituents might affect this reaction.
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Steric effects in the SN2 reaction
The order of reactivity of RX in these SN2 reactions is CH3X > 1o > 2o > 3o
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Steric effects in the SN2 reaction
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Structural effects in SN1 reactions
3o > 2o > 1o > CH3X
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RO- > HO- >> RCO2- > ROH >H2O
Nucleophilicity Rates of SN2 reactions depend on concentration and nucleophilicity of the nucleophile. A base is more nucleophilic than its conjugate acid: CH3Cl + H2O CH3OH2+ slow CH3Cl + HO- CH3OH fast The nucleophilicity of nucleophiles having the same nucleophilic atom parallels basicity: RO- > HO- >> RCO2- > ROH >H2O
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I- > Br- > Cl- > F-
Nucleophilicity When the nucleophilic atoms are different, their relative strengths do not always parallel their basicity. In protic solvents, the larger the nucleophilic atom, the better: I- > Br- > Cl- > F- In protic solvents, the smaller the anion, the greater its solvation due to hydrogen bonding. This shell of solvent molecules reduces its ability to attack.
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Nucleophilicity Aprotic solvents tend to solvate cations rather than anions. Thus the unsolvated anion has a greater nucleophilicity in an aprotic solvent.
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Polar aprotic solvents
These solvents dissolve ionic compounds.
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Solvent polarity more polar
transition state less solvated than reagents A protic solvent will decrease the rate of this reaction and the reaction is 1,200,000 faster in DMF than in methanol.
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Solvent polarity less polar more polar
greater stabilization by polar solvent The transition state is more polarized. Therefore the rate of this reaction increases with increase in solvent polarity. A protic solvent is particularly effective as it stabilizes the transition state by forming hydrogen bonds with the leaving group.
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Solvent polarity Explain the solvent effects for each of the following second order reactions: a) 131I- + CH3I CH3131I + I- Relative rates: in water, 1; in methanol, 16; in ethanol, 44 b) (n-C3H7)3N + CH3I (n-C3H7)3N+CH3 I- Relative rates: in n-hexane, 1; in chloroform,
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I- > Br- > Cl- > H2O > F- > OH-
Leaving group ability Weak bases are good leaving groups. They are better able to accommodate a negative charge and therefore stabilize the transition state. Thus I- is a better leaving group than Br-. I- > Br- > Cl- > H2O > F- > OH-
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SN1 v SN2 SN1 SN2 kinetics: 1st order second order
reactivity: 3o > 2o > 1o > CH3X CH3X > 1o > 2o > 3o rearrangements no rearrangements partial inversion inversion of configuration eliminations possible
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Problems Try problems 6.6 – 6.11 and 6.14 – 6.16 in chapter 6 of Solomons and Fryhle.
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Functional group transformations using SN2 reactions
R = Me, 1o, or 2o
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Problems Try problems 6.12 and 6.17 in chapter 6 of Solomons and Fryhle.
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ROH + HX - an SN reaction
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Experimental facts 1. The reaction is acid catalyzed
2. Rearrangements are possible 3. Alcohol reactivity is 3o > 2o > 1o < CH3OH
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The mechanism
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Reaction of primary alcohols with HX
SN2
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