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Quadratic Simultaneous Equations
Grade 9 Advanced Algebra Quadratic Simultaneous Equations Lesson Objective: to recap how to solve linear simultaneous equations and how to solve simultaneous equations when one of them is quadratic
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Quadratic Simultaneous Equations
Expand the brackets (3+π₯) 2 = 3+π₯ 3+π₯ (3+π₯) 2 =9+ π₯ 2 +6π₯ π₯ 2 + π¦ 2 =29 π¦βπ₯=3 quadratic linear Substitute this into hereβ¦ π₯ π₯ 2 +6π₯=29 Tidy up the equation a little bitβ¦ Rearranging the linear equationβ¦ 2π₯ 2 +6π₯+9=29 π¦=3+π₯ Prepare our equation so we can use The Quadratic Formula Substitute it into the quadratic equation π₯ 2 + (3+π₯) 2 =29 2π₯ 2 +6π₯β20=0
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Quadratic Simultaneous Equations
2π₯ 2 +6π₯β20=0 Remember our original equations? π₯ 2 + π¦ 2 =29 π¦βπ₯=3 Substitute x = 5 or -2 into the second equation (itβs a lot easier!) a = 2 b = 6 c = -20 π¦=β2 ππ 5 π₯= β6Β± β(4Γ2Γβ20 2Γ2 Pair up your answersβ¦ πβππ π₯=β5, π¦=β2 πβππ π₯=2, π¦=5 π₯=β5 ππ 2
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Independent Task π₯ 2 + π¦ 2 =25 π¦=π₯β7 Hints
Substitute the linear equation into the quadratic equation Expand the brackets Prepare your equation so you can use The Quadratic Formula Find two values for x Substitute your two values for x into the linear equation to find two values for y Pair up your answers
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Quadratic Simultaneous Equations
π₯ 2 + π¦ 2 =25 π¦=π₯β7 quadratic Substituting into the quadratic equation linear π₯ 2 + π₯ 2 β14π₯+49=25 Tidy up the equation a little bitβ¦ Substitute the linear equation into the quadratic equation 2π₯ 2 β14π₯+49=25 π₯ 2 + (π₯β7) 2 =25 Prepare our equation so we can use The Quadratic Formula Expand the brackets (π₯β7) 2 = π₯β7 π₯β7 (π₯β7) 2 = π₯ 2 β14π₯+49 2π₯ 2 β14π₯+24=0
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Quadratic Simultaneous Equations
2π₯ 2 β14π₯+24=0 Going back to our original equationsβ¦ π₯ 2 + π¦ 2 =25 π¦=π₯β7 Substitute x = 3 or 4 into the linear equation a = 2 b = -14 c = 24 π¦=β4 ππ β3 π₯= β(β14)Β± (β14) 2 β(4Γ2Γ24) 2Γ2 Pair up your answersβ¦ πβππ π₯=3 π¦=β4 πβππ π₯=4, π¦=β3 π₯=3 ππ 4
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Quadratic Simultaneous Equations
π₯ 2 + π¦ 2 =18 π¦β2π₯=3 π₯ 2 + π¦ 2 =40 x+π¦=4 π₯ 2 + π¦ 2 =5 π¦=3π₯+1 π₯ 2 + π¦ 2 =13 xβ2π¦=1
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Quadratic Simultaneous Equations
Solutions π₯=β3, π¦=β3 π₯=0.6, π¦=4.2 π₯=6, π¦=β2 π₯=β2, π¦=6 π₯=0.4, π¦=2.2 π₯=β1,π¦=β2 π₯=β3, π¦=β2 π₯=3.4, π¦=1.2
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