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Paper 2 / section b Suggested answer.

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1 Paper 2 / section b Suggested answer

2 Section B Problem Solving Qualitative (Question 9)
1 Pressure is defined as force per unit area P=F/A, where F= force, A=area (ii) Depth of singking in Diagram 9.1 is deeper than in Diagram 9.2 The weight/load of the man in Diagram 9.2 and Diagram 9.1 is equal Area of contact with the sand in Diagram 9.2 is larger than in Diagram 9.1 (iii) The depth of sinking increases, pressure increases As the area of contact increases, the pressure exerted decreases 5

3 The fan blows /remove/push/force air out the vents
Question 9 9 (b) 1 The fan blows /remove/push/force air out the vents Produce a partial vacuum area in the vacuum cleaner/low pressure Atmospheric pressure is higher than the pressure inside the vacuum cleaner/Difference in pressure Push the dirt into the vacuum 4

4 9 (c) Suggestion Rationale 1 Type of fluid Oil 2
Incompressible/ No air bubble/Cannot be compress/water produce air bubble Any 5 correct 3 Characteristic of fluid High boiling point/ Low density/ High viscosity 4 Does not change to gases state easily/lighter/Less friction/Does not evaporate easily 5 Size of the master piston Small 6 To produce high pressure/small force used 7 Size of slave piston Big 8 To produce a big force on the disc/ Force is directly proportional to area 9 Material for fluid transmission pipe Plastic/ Aluminium / Steel 10 Strong/ Does not break easily/Does not rust easily/ Non corrosive/withstand temperature/prevent leakage TOTAL

5 Two bodies are said to be in thermal equilibrium when
Section C (Decision Making Skill) ( Section C: Question 11 ) 11 (a) (i) 1 Two bodies are said to be in thermal equilibrium when Both bodies are at the same temperature/ The net heat flow between the two bodies is zero/ There is no net heat flow between them (ii) Heat flows from hot water to thermometer Achieve thermal equilibrium Temperature of water is the same as temperature shown by thermometer No more heat flows at 100 oC 4

6 Heat released by M = Heat absorbed by water
Question 11 11 (b) 1 Heat released by M = Heat absorbed by water Substitution: (0.5) (800)(100-T)= (0.2)(4200)(T-30) T= oC Note: no e.c.f 4 (ii) No heat is lost to the surrounding

7 11 (c) Characteristics Explanation Hollow plastic stopper Bad conductor of heat /Reduce heat loss/bad conductor/good insulator/reduce heat escape to the surrounding/Trapped air Space X is vacuum Prevent heat lost from the sides through convection/heat cannot travel through vaccum Double walled tube made of glass High specific heat capacity/ Becomes hot very slowly Double walled tube coated by shiny paint Reflect heat from the wall of thermos flask/not absorb heat The most suitable is W Because Hollow plastic stopper, space X is vacuum, double walled tube made of glass and coated by shiny paint

8 Work done in moving one coulomb of charge from one point to another /
Section C (Decision Making Skill) ( Section C: Question 12 ) 12 (a) (i) 1 Work done in moving one coulomb of charge from one point to another / Energy dissipated per unit charge by the resistor / V= E/Q, E= work done, Q= quantity of charge (b) (ii) When I increases, V increases The resistance increases Because temperature increases (iii) Decrease

9 12 (c) Characteristics Explanation Shape of filament wire Coiled So that a very long wire can be fitted inside the glass bulb to give out a bright light / High resistance Thickness of the filament wire Thin To give more resistance per unit length/ More heat Type of wire Tungsten Has high melting point/ Does not break easily Pressure in the bulb Low pressure The bulb will not burst/explode after for a long time The most suitable is R Because Coiled , thin wire, nitrogen at low pressure

10 Efficiency = Power output x 100% Power input = 10 x 100%
Question 12 (d) 11 (d) (i) 1 Correct substitution I= P/V = 11/240 =0.046 A/ 0.05 A (ii) Heat loss= 11J -10 J=1J (III) Efficiency = Power output x 100% Power input = 10 x 100% = 90.91% 5


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