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Unit 2: Algebraic Vectors
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Schedule for Algebraic Vectors
Today: Intro and Notation Tomorrow: Operations on algebraic vectors (adding & scalar multiplicaiton) Friday: The Dot Product ( π β π = π π cosπ) Monday: The Cross Product (multiplying 2 vectors - π Γ π ) Tuesday: Applications of the Dot Product and Cross Product Wednesday: Review Thursday: Test Friday: Warm-up to Unit 3: Linear Systems
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2.1 Introduction to Algebraic Vectors
Position Vector: The vector ππ with a tail at the origin, O and the tip at the point P.
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Example 1: The geometric vector π£ is defined to have a magnitude of 10 and a direction of N 45 Β° E. Determine the components of the position vector.
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Example 2: Draw vector ππ =[β2,3] and determine its magnitude & direction. β΄ If you have a vector π’ =[π,π] then π’ = π 2 + π 2 and π= tan β1 π π .
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Unit Vectors We can express any vectors in the π₯π¦-plane as a sum of scalar multiples of the vectors π and π , where π =[1,0] and π = 0,1 . Example: ππ = 5,6 =5 π +6 π In general, ordered pair notation and unit vector notation are equivalent.
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3 Dimensions (π
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3 Dimensions (π
3 ) We can express any vectors in the π₯π¦π§-plane as a sum of scalar multiples of the vectors π , π , π where π = 1,0,0 , π = 0,1,0 and π = 0,0,1 . Ordered triple: (π₯,π¦,π§) Example: ππ = 3,5,4 =3 π +5 π +4 π
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3 Dimensions (π
3 ) If you have a vector π’ =[π,π,π] then π’ = π 2 + π 2 + π 2 and the direction angles are πΌ,π½, πΎ, where 0β€πΌ,π½, πΎβ€ 180 Β° such that: πππ πΌ= π ππ πππ π½= π ππ πππ πΎ= π ππ
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Example: If you have a vector π’ = β2,3,0 , find π’ and the direction angles.
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