1. Factoring With Stick Man, Day Two

2. Table of Contents
46: Warm-Up, Guided Practice, Reflection
47: How Do I Factor Quadratics Using Stick Man?

3. Warm-Up Quizizz Miss Masik: Click here
Students: Click here or go to:

4. Learning Intention/Success Criteria
LI: We are learning to factor quadratics when A is not one. SC: I know how to -recognize if a quadratic can be factored -identify the roots and y-intercept of a quadratic -identify the solutions of the equation by factoring -multiply and add integers -check my work by multiplying binomials

5. EQ: How Do I Factor Quadratics When A is Not One?
12/1/2018

6. Example 1a: Factor 8x2 – 2x – 1 = 0
A: B: C: 8 -2 -1 -8
A • C
= -7 1 -8 2 -4
= -2 B -2
(8x + 2)(8x – 4)
_____
_____
(4x + 1)
(2x – 1)

7. Check Your Work:
(4x + 1)
(2x – 1)
4x • 2x
= 8x2
4x • - 1
= -4x
1 • 2x
= 2x
1 • - 1
= -1
8x2 – 4x + 2x – 1
8x2 – 2x – 1

8. Example 1b: Solve the quadratic 8x2 – 2x – 1 = 0
- 1
- 1
+ 1
+ 1
________
________
4x = -1
__ 4
__ 4
2x = 1
__ 2
__ 2
x =
x =

9. Guided Practice 1
Factor: 6x2 – 5x + 1 = 0

10. Guided Practice 1 Factor: 6x2 – 5x + 1 = 0 A] (3x – 1)(2x – 1) = 0
B] (3x + 1)(2x + 1) = 0
C] (3x + 1)(2x – 1) = 0
D] (3x – 1)(2x + 1) = 0

11. Guided Practice 1 Solved
Factor: 6x2 – 5x + 1 = 0 6
A • C
(3x – 1)
(2x – 1)
= -7 -1 -6
F O I L
3x • 2x
= 6x2 -2 -3
= -5
3x • -1
= -3x B
-1 • 2x
= -2x -5
-1 • -1
= 1
(6x – 2)(6x – 3)
_____
_____
6x2 – 3x – 2x + 1
(3x – 1)
(2x – 1)
6x2 – 5x + 1

12. Guided Practice 1 Continued
Solve: 6x2 – 5x + 1 = 0
A] 1/3 and 1/2
B] -1/3 and -1/2
C] -1/3 and 1/2
D] 1/3 and -1/2

13. Guided Practice 1 Solved
Solve: 6x2 – 5x + 1 = 0
(3x – 1)(2x – 1) = 0
2x – 1 = 0
3x – 1 = 0
+ 1
+ 1
_________
+ 1
+ 1
_________
3x = 1
__ 3
__ 3
2x = 1
__ 2
__ 2
x = 1/3
x = 1/2

14. Example 2a: Solve the quadratic 5x2 + 11x + 6
A: B: C: 5 11 6 30
A • C 1 30
= 31 2 15
= 17 3 10
= 13 5 6
= 11 B 11
(5x + 5)(5x + 6)
_____
(x + 1)(5x + 6)

15. Check Your Work:
(x + 1)
(5x + 6)
x • 5x
= 5x2
x • 6
= 6x
1 • 5x
= 5x
1 • 6
= 6
5x2 + 6x + 5x + 6
5x2 + 11x + 6

16. Example 2b: Solve the quadratic 5x2 + 11x + 6 = 0
- 1
- 1
- 6
- 6
________
________
x = -1
5x = -6
__ 5
__ 5
x =

17. Guided Practice 2
Factor: 2g2 – 9g + 7 = 0

18. Guided Practice 2 Factor: 2g2 – 9g + 7 = 0 A] (g + 1)(2g + 7) = 0
B] (g – 1)(2g – 7) = 0
C] (2g + 1)(g + 7) = 0
D] (2g – 1)(g – 7) = 0

19. Guided Practice 2 Solved
Factor and Solve: 2g2 – 9g + 7 = 0 14
A • C
(g – 1)
(2g – 7)
= -15 -1
-14
F O I L
g • 2g
= 2g2 -2 -7
= -9
g • -7
= -7g B
-1 • 2g
= -2g -9
-1 • -7
= 7
(2g – 2)(2g – 7)
_____
2g2 – 7g – 2g + 7
(g – 1 )
(2g – 7)
2g2 – 9g + 7

20. Guided Practice 2 Continued
What are the roots: 2g2 – 9g + 7 = 0
A] (1/3, 0) and (1/2, 0)
B] (-1/3, 0) and (-1/2, 0)
C] (-1/3, 0) and (1/2, 0)
D] (1/3, 0) and (-1/2, 0)

21. Guided Practice 2 Solved
Factor and Solve: 2g2 – 9g + 7 = 0
(g – 1)(2g – 7) = 0
g – 1 = 0
2g – 7 = 0
+ 1
+ 1
___________
___________
+ 7
+ 7
g = 1
2g = 7
___ 2
___ 2
g =

22. Example 3a: Factor: 4x2 + 34x + 42
First: Second: Third:
2 • 2 • x • x
2 • 17 • x
2 • 21 2
(2x2 + 17x + 21)

23. A: B: C: 2 17 21 42
A • C 1 42
= 43 2 21
= 23 3 14
= 17 6 7
= 13 B 17 2
(2x + 3)
(2x + 14)
______
2(2x + 3)(x + 7)

24. Check Your Work:
2(2x + 3)(x + 7)
2x • x
= 2x2
2x • 7
= 14x
3 • x
= 3x
3 • 7
= 21
2(2x2 + 14x + 3x + 21)
2(2x2 + 17x + 21)
4x2
+ 34x
+ 42

25. Example 3b: Solve: 4x2 + 34x + 42 = 0
___________
- 3
- 3
___________
- 7
- 7
2x = -3
__ 2
__ 2
x = -7
x = _-3_

26. Questions?
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27. Exit Note Explain the lesson in under 50 words.
Place your answer in the jar with the level you feel like you’re at for this lesson.