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5.5, Day 2 More Synthetic Division
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If π π₯ = π₯ 3 + π₯ 2 β16π₯β16 has a zero of 4, what would the other zeros be?
If 4 is a zero, that means that x β 4 is a factor and I should be able to synthetically divide by 4 and find the other factors and from there find the other zeros. Good, we expected a remainder of zero, and now we need to factor π₯ 2 +5π₯+4 . 4 20 16 1 5 4 π₯ 2 +5π₯+4=(π₯+1)(π₯+4), so the other zeros are -1 and -4 What would f(-4) be for the above equation? zero
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If f(-1) = 0, completely factor π π₯ = π₯ 3 +2 π₯ 2 β5π₯β6.
If f(-1) = 0, then x + 1 is a factor, and I can synthetically divide by -1 and finish factoring. -1 -1 6 1 1 -6 π₯ 2 +π₯β6=(π₯+3)(π₯β2) Therefore the complete factorization of π₯ 3 + 2π₯ 2 β5π₯β6 is π₯+1 π₯+3 π₯β2 .
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If f(-2) = 0, completely factor π π₯ = 7π₯ 3 β10 π₯ 2 β39π₯+18.
-14 48 -18 7 -24 9 7 π₯ 2 β24π₯+9=(7π₯β3)(π₯β3) The complete factorization of 7π₯ 3 β 10π₯ 2 β39π₯ is π₯+2 7π₯β3 π₯β3 . What are all the zeros of 7π₯ 3 β10 π₯ 2 β39π₯+18 ? Zeroβs are -2, , and 3 Factor theorem---A polynomial f(x) has a factor of (x β k), if and only if f(k) = 0 .
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A companyβs profit C (in thousands of dollars) can be modeled by πΆ=β 5π₯ 3 +6 π₯ 2 +15π₯, where x is the number of items produced in thousands. The profit is $14,000 for producing 2000 items. What other number of items would produce about the same profit? When C = 14, there is a zero of 2. 0= β5π₯ 3 + 6π₯ 2 +15π₯β14 -10 -8 14 -5 -4 7 The expression that is left, β5 π₯ 2 β4π₯+7, does not factor, so use the quadratic formula to find an approximate zero that seems appropriate. Approx , or 850 items!
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