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Horizontal and Vertical Circles

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Presentation on theme: "Horizontal and Vertical Circles"— Presentation transcript:

1 Horizontal and Vertical Circles
Car on Curve Car on banked Curve Horizontal vs. Vertical Circle Vertical circle at top Examples

2 More complicated examples 1
Car on Track with Friction Example 5-6 μ mg = mv2/r

3 More complicated examples 2
Car on Banked Track Example 5-7 Don’t use tilted axes FN cosθ = mg, FN sinθ = mv2/r tanθ = v2/rg

4 Horizontal vs. Vertical Circle
Horizontal - circular perp. (┴) to gravity Vertical – circular inline with gravity Situations Ball on a cord (tension only pulls in) Car going over hump (normal pushes up)

5 Vertical circle at the top
“Inside” Problem – Ball on string. Starts fast, slows down mg + FT = mv2/r “Outside Problem” – Car on hump. Starts slow, speeds up mg - FN = mv2/r mg FT Need both mg and FT at high speeds. As RHS gets smaller, mg takes over and FT not needed Required ma starts high, gets smaller as v decreases mg FN FN balances mg at low speeds. As RHS gets larger, more mg required and FN not needed Required ma starts low, gets larger as v increases

6 Vertical Circle Examples
Situations Ball on a cord (tension only pulls in) Car going over hump (normal pushes up) Example 5-4 (ball on vertical string) (“inside problem”) Problem 14 (sports car on hump) (“outside problem”) Problem 15 (ferris wheel) Problem 16 (bucket with water)

7 Examples - “Inside” Vertical Circle
Example 5-4 (ball on vertical string) 0.15 kg ball on 1.1 m cord What speed does string go slack at top? 𝐹 𝑇 +𝑚𝑔= 𝑚 𝑣 2 𝑟 𝑣= 𝑟𝑔 What is tension for v = 5 m/s? Problem 16 (bucket with water) 2 kg bucket on 1.1 m cord Tension at bottom 25 N, what is speed at bottom? 𝐹 𝑇 −𝑚𝑔= 𝑚 𝑣 2 𝑟 𝑣= 𝑟 𝐹 𝑇 −𝑚𝑔 𝑚 = 𝑚 25𝑁−19.6𝑁 2 𝑘𝑔 =1.72 𝑚/𝑠 𝐹 𝑇 +𝑚𝑔= 𝑚 𝑣 2 𝑟 𝑣= 𝑟𝑔 =3.3 𝑚/𝑠

8 Examples - “Outside” Vertical Circle
Problem 14 (sports car on hump) 950 kg car, 95 m radius hump Goes over top at 22 m/s What is normal force of road? 𝑚𝑔−𝐹 𝑁 = 𝑚 𝑣 2 𝑟 𝐹 𝑁 =𝑚𝑔− 𝑚 𝑣 2 𝑟 What is normal force on 72 kg driver? What speed does driver feel weightless? 𝑚𝑔−𝐹 𝑁 = 𝑚 𝑣 2 𝑟 𝑣= 𝑟𝑔 Problem 15 (ferris wheel) 7.5 m radius ferris wheel weightless at top 𝑚𝑔−𝐹 𝑁 = 𝑚 𝑣 2 𝑟 𝑣= 𝑟𝑔 =8.6 m/s 𝑓= 𝑣 2𝜋𝑟 =0.18 𝑟𝑒𝑣 𝑠 =10.9 𝑟𝑒𝑣 𝑚𝑖𝑛

9 Example – Roto-Ride 4.6 m drum radius
0.5 rev/sec frequency (14.45 m/s) Radial 𝐹 𝑁 = 𝑚 𝑣 2 𝑟 Vertical 𝐹 𝑓𝑟 =𝑚𝑔=0 𝜇 𝐹 𝑁 =𝑚𝑔 Dividing vertical by Radial 𝜇= 𝜇 𝐹 𝑁 𝐹 𝑁 = 𝑚𝑔 𝑚 𝑣 2 𝑟 = 𝑟𝑔 𝑣 2 =0.22


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