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Published byHenry Cummings Modified over 6 years ago
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Using the Tables for the standard normal distribution
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Tables have been posted for the standard normal distribution.
Namely The values of z ranging from -3.5 to 3.5
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If X has a normal distribution with mean m and standard deviation s then
has a standard normal distribution. Hence
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Example: Suppose X has a normal distribution with mean m =160 and standard deviation s =15 then find:
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This also can be explained by making a change of variable
Make the substitution when and Thus
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The Normal Approximation to the Binomial
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The Central Limit theorem
If x1, x2, …, xn is a sample from a distribution with mean m, and standard deviations s, Let Then the distribution of approaches the standard normal distribution as
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Hence the distribution of approaches
the Normal distribution with or the distribution of approaches the normal distribution with
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Thus The Central Limit theorem states
That sums and averages of independent R.Vs tend to have approximately a normal distribution for large n. Suppose that X has a binomial distribution with parameters n and p. Then where are independent Bernoulli R.V.’s
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Thus for large n the Central limit Theorem states that
has approximately a normal distribution with Thus for large n where X has a binomial (n,p) distribution and Y has a normal distribution with
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The binomial distribution
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The normal distribution m = np, s2 = npq
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Binomial distribution n = 20, p = 0.70
Approximating Normal distribution Binomial distribution
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Normal Approximation to the Binomial distribution
X has a Binomial distribution with parameters n and p Y has a Normal distribution
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Approximating Normal distribution P[X = a] Binomial distribution
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P[X = a]
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Example X has a Binomial distribution with parameters n = 20 and p = 0.70
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Using the Normal approximation to the Binomial distribution
Where Y has a Normal distribution with:
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Hence = = Compare with
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Normal Approximation to the Binomial distribution
X has a Binomial distribution with parameters n and p Y has a Normal distribution
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Example X has a Binomial distribution with parameters n = 20 and p = 0.70
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Using the Normal approximation to the Binomial distribution
Where Y has a Normal distribution with:
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Hence = = Compare with
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Comment: The accuracy of the normal appoximation to the binomial increases with increasing values of n
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Example The success rate for an Eye operation is 85%
The operation is performed n = 2000 times Find The number of successful operations is between 1650 and 1750. The number of successful operations is at most 1800.
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Solution X has a Binomial distribution with parameters n = 2000 and p = 0.85 where Y has a Normal distribution with:
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= =
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Solution – part 2. = 1.000
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