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UIUC CS 497: Section EA Lecture #6
Reasoning in Artificial Intelligence Professor: Eyal Amir Spring Semester 2004 (Based on slides by Lise Getoor and Alvaro Cardenas (UMD) (in turn based on slides by Nir Friedman (Hebrew U)))
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Last Time Tree decomposition in first-order logic Applications:
Provably better computational bounds when low treewidth in propositional logic Eliminate possible interactions between clauses Applications: Planning, spatial reasoning
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Today Probabilistic graphical models Treewidth methods:
Variable elimination Clique tree algorithm Applications du jour: Sensor Networks
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Independent Random Variables
Two variables X and Y are independent if P(X = x|Y = y) = P(X = x) for all values x,y That is, learning the values of Y does not change prediction of X If X and Y are independent then P(X,Y) = P(X|Y)P(Y) = P(X)P(Y) In general, if X1,…,Xp are independent, then P(X1,…,Xp)= P(X1)...P(Xp) Requires O(n) parameters
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Conditional Independence
Unfortunately, most of random variables of interest are not independent of each other A more suitable notion is that of conditional independence Two variables X and Y are conditionally independent given Z if P(X = x|Y = y,Z=z) = P(X = x|Z=z) for all values x,y,z That is, learning the values of Y does not change prediction of X once we know the value of Z notation: I ( X , Y | Z )
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Example: Family trees Noisy stochastic process: Example: Pedigree
Homer Bart Marge Lisa Maggie Noisy stochastic process: Example: Pedigree A node represents an individual’s genotype Modeling assumptions: Ancestors can effect descendants' genotype only by passing genetic materials through intermediate generations
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Markov Assumption Ancestor X Y1 Y2 Non-descendent We now make this independence assumption more precise for directed acyclic graphs (DAGs) Each random variable X, is independent of its non-descendents, given its parents Pa(X) Formally, I (X, NonDesc(X) | Pa(X)) Parent Non-descendent Descendent
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Markov Assumption Example
Earthquake Radio Burglary Alarm Call In this example: I ( E, B ) I ( B, {E, R} ) I ( R, {A, B, C} | E ) I ( A, R | B,E ) I ( C, {B, E, R} | A)
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I-Maps A DAG G is an I-Map of a distribution P if all Markov assumptions implied by G are satisfied by P (Assuming G and P both use the same set of random variables) Examples: X Y X Y
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Factorization Given that G is an I-Map of P, can we simplify the representation of P? Example: Since I(X,Y), we have that P(X|Y) = P(X) Applying the chain rule P(X,Y) = P(X|Y) P(Y) = P(X) P(Y) Thus, we have a simpler representation of P(X,Y) X Y
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Factorization Theorem
Thm: if G is an I-Map of P, then Proof: By chain rule: wlog. X1,…,Xp is an ordering consistent with G From assumption: Since G is an I-Map, I (Xi, NonDesc(Xi)| Pa(Xi)) Hence, We conclude, P(Xi | X1,…,Xi-1) = P(Xi | Pa(Xi) )
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Factorization Example
Earthquake Radio Burglary Alarm Call P(C,A,R,E,B) = P(B)P(E|B)P(R|E,B)P(A|R,B,E)P(C|A,R,B,E) versus P(C,A,R,E,B) = P(B) P(E) P(R|E) P(A|B,E) P(C|A)
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Consequences each conditional probability can be specified compactly
We can write P in terms of “local” conditional probabilities If G is sparse, that is, |Pa(Xi)| < k , each conditional probability can be specified compactly e.g. for binary variables, these require O(2k) params. representation of P is compact linear in number of variables
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Summary We defined the following concepts
The Markov Independences of a DAG G I (Xi , NonDesc(Xi) | Pai ) G is an I-Map of a distribution P If P satisfies the Markov independencies implied by G We proved the factorization theorem if G is an I-Map of P, then
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Conditional Independencies
Let Markov(G) be the set of Markov Independencies implied by G The factorization theorem shows G is an I-Map of P We can also show the opposite: Thm: G is an I-Map of P
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Proof (Outline) X Z Example: Y
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Implied Independencies
Does a graph G imply additional independencies as a consequence of Markov(G)? We can define a logic of independence statements Some axioms: I( X ; Y | Z ) I( Y; X | Z ) I( X ; Y1, Y2 | Z ) I( X; Y1 | Z )
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d-seperation A procedure d-sep(X; Y | Z, G) that given a DAG G, and sets X, Y, and Z returns either yes or no Goal: d-sep(X; Y | Z, G) = yes iff I(X;Y|Z) follows from Markov(G)
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Paths Intuition: dependency must “flow” along paths in the graph
A path is a sequence of neighboring variables Examples: R E A B C A E R Earthquake Radio Burglary Alarm Call
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Paths We want to know when a path is
active -- creates dependency between end nodes blocked -- cannot create dependency end nodes We want to classify situations in which paths are active.
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Path Blockage Blocked Unblocked Blocked Active Three cases: E R A E R
Common cause Blocked Unblocked Blocked Active E R A E R A
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Path Blockage Blocked Active Blocked Unblocked Three cases: E A C
Common cause Intermediate cause Blocked Active Blocked Unblocked E C A
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Path Blockage Blocked Active Blocked Unblocked Three cases: E B A C E
Common cause Intermediate cause Common Effect Blocked Active Blocked Unblocked E B A C E B A C
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Path Blockage -- General Case
A path is active, given evidence Z, if Whenever we have the configuration B or one of its descendents are in Z No other nodes in the path are in Z A path is blocked, given evidence Z, if it is not active. A C B
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Example d-sep(R,B)? E B R A C
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Example d-sep(R,B) = yes d-sep(R,B|A)? E B R A C
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Example d-sep(R,B) = yes d-sep(R,B|A) = no d-sep(R,B|E,A)? E B R A C
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d-Separation X is d-separated from Y, given Z, if all paths from a node in X to a node in Y are blocked, given Z. Checking d-separation can be done efficiently (linear time in number of edges) Bottom-up phase: Mark all nodes whose descendents are in Z X to Y phase: Traverse (BFS) all edges on paths from X to Y and check if they are blocked
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Soundness Thm: If G is an I-Map of P d-sep( X; Y | Z, G ) = yes then P satisfies I( X; Y | Z ) Informally: Any independence reported by d-separation is satisfied by underlying distribution
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Completeness Thm: If d-sep( X; Y | Z, G ) = no
then there is a distribution P such that G is an I-Map of P P does not satisfy I( X; Y | Z ) Informally: Any independence not reported by d-separation might be violated by the underlying distribution We cannot determine this by examining the graph structure alone
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Summary: Structure We explored DAGs as a representation of conditional independencies: Markov independencies of a DAG Tight correspondence between Markov(G) and the factorization defined by G d-separation, a sound & complete procedure for computing the consequences of the independencies Notion of minimal I-Map P-Maps This theory is the basis for defining Bayesian networks
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Inference We now have compact representations of probability distributions: Bayesian Networks Markov Networks Network describes a unique probability distribution P How do we answer queries about P? We use inference as a name for the process of computing answers to such queries
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Today Probabilistic graphical models Treewidth methods:
Variable elimination Clique tree algorithm Applications du jour: Sensor Networks
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Queries: Likelihood There are many types of queries we might ask.
Most of these involve evidence An evidence e is an assignment of values to a set E variables in the domain Without loss of generality E = { Xk+1, …, Xn } Simplest query: compute probability of evidence This is often referred to as computing the likelihood of the evidence
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Queries: A posteriori belief
Often we are interested in the conditional probability of a variable given the evidence This is the a posteriori belief in X, given evidence e A related task is computing the term P(X, e) i.e., the likelihood of e and X = x for values of X
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A posteriori belief This query is useful in many cases:
Prediction: what is the probability of an outcome given the starting condition Target is a descendent of the evidence Diagnosis: what is the probability of disease/fault given symptoms Target is an ancestor of the evidence the direction between variables does not restrict the directions of the queries
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Queries: MAP In this query we want to find the maximum a posteriori assignment for some variable of interest (say X1,…,Xl ) That is, x1,…,xl maximize the probability P(x1,…,xl | e) Note that this is equivalent to maximizing P(x1,…,xl, e)
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Queries: MAP We can use MAP for: Classification Explanation
find most likely label, given the evidence Explanation What is the most likely scenario, given the evidence
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Complexity of Inference
Thm: Computing P(X = x) in a Bayesian network is NP-hard Not surprising, since we can simulate Boolean gates.
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Approaches to inference
Exact inference Inference in Simple Chains Variable elimination Clustering / join tree algorithms Approximate inference – next time Stochastic simulation / sampling methods Markov chain Monte Carlo methods Mean field theory – your presentation
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Variable Elimination General idea: Write query in the form Iteratively
Move all irrelevant terms outside of innermost sum Perform innermost sum, getting a new term Insert the new term into the product
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Example “Asia” network: Visit to Asia Smoking Lung Cancer Tuberculosis
Abnormality in Chest Bronchitis X-Ray Dyspnea
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Need to eliminate: v,s,x,t,l,a,b Initial factors
We want to compute P(d) Need to eliminate: v,s,x,t,l,a,b Initial factors “Brute force approach” Complexity is exponential in the size of the graph (number of variables) = T. N=number of states for each variable
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Need to eliminate: v,s,x,t,l,a,b Initial factors
We want to compute P(d) Need to eliminate: v,s,x,t,l,a,b Initial factors Eliminate: v Compute: Note: fv(t) = P(t) In general, result of elimination is not necessarily a probability term
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Need to eliminate: s,x,t,l,a,b Initial factors
V S L T A B X D We want to compute P(d) Need to eliminate: s,x,t,l,a,b Initial factors Eliminate: s Compute: Summing on s results in a factor with two arguments fs(b,l) In general, result of elimination may be a function of several variables
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Need to eliminate: x,t,l,a,b Initial factors
V S L T A B X D We want to compute P(d) Need to eliminate: x,t,l,a,b Initial factors Eliminate: x Compute: Note: fx(a) = 1 for all values of a !!
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Need to eliminate: t,l,a,b Initial factors
V S L T A B X D We want to compute P(d) Need to eliminate: t,l,a,b Initial factors Eliminate: t Compute:
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We want to compute P(d) Need to eliminate: l,a,b Initial factors
V S L T A B X D We want to compute P(d) Need to eliminate: l,a,b Initial factors Eliminate: l Compute:
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We want to compute P(d) Need to eliminate: b Initial factors
V S L T A B X D We want to compute P(d) Need to eliminate: b Initial factors Eliminate: a,b Compute:
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Different elimination ordering: Need to eliminate: a,b,x,t,v,s,l
Initial factors Intermediate factors: Complexity is exponential in the size of the factors!
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Variable Elimination We now understand variable elimination as a sequence of rewriting operations Actual computation is done in elimination step Exactly the same computation procedure applies to Markov networks Computation depends on order of elimination
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Markov Network (Undirected Graphical Models)
A graph with hyper-edges (multi-vertex edges) Every hyper-edge e=(x1…xk) has a potential function fe(x1…xk) The probability distribution is
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Complexity of variable elimination
Suppose in one elimination step we compute This requires multiplications For each value for x, y1, …, yk, we do m multiplications additions For each value of y1, …, yk , we do |Val(X)| additions Complexity is exponential in number of variables in the intermediate factor
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Undirected graph representation
At each stage of the procedure, we have an algebraic term that we need to evaluate In general this term is of the form: where Zi are sets of variables We now plot a graph where there is undirected edge X--Y if X,Y are arguments of some factor that is, if X,Y are in some Zi Note: this is the Markov network that describes the probability on the variables we did not eliminate yet
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Chordal Graphs elimination ordering undirected chordal graph Graph:
Maximal cliques are factors in elimination Factors in elimination are cliques in the graph Complexity is exponential in size of the largest clique in graph V S L T A B X D L T A B X V S D
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Induced Width The size of the largest clique in the induced graph is thus an indicator for the complexity of variable elimination This quantity is called the induced width of a graph according to the specified ordering Finding a good ordering for a graph is equivalent to finding the minimal induced width of the graph
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PolyTrees A polytree is a network where there is at most one path from one variable to another Thm: Inference in a polytree is linear in the representation size of the network This assumes tabular CPT representation A C B D E F G H
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Today Probabilistic graphical models Treewidth methods:
Variable elimination Clique tree algorithm Applications du jour: Sensor Networks
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Junction Tree Why junction tree? Objective
More efficient for some tasks than variable elimination We can avoid cycles if we turn highly-interconnected subsets of the nodes into “supernodes” cluster Objective Compute is a value of a variable and is evidence for a set of variable
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Properties of Junction Tree
An undirected tree Each node is a cluster (nonempty set) of variables Running intersection property: Given two clusters and , all clusters on the path between and contain Separator sets (sepsets): Intersection of the adjacent cluster ADE ABD DEF AD DE Cluster ABD Sepset DE
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Potentials Potentials: Marginalization Multiplication Denoted by
, the marginalization of into X Multiplication , the multiplication of and
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Properties of Junction Tree
Belief potentials: Map each instantiation of clusters or sepsets into a real number Constraints: Consistency: for each cluster and neighboring sepset The joint distribution
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Properties of Junction Tree
If a junction tree satisfies the properties, it follows that: For each cluster (or sepset) , The probability distribution of any variable , using any cluster (or sepset) that contains
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Building Junction Trees
DAG Moral Graph Triangulated Graph Identifying Cliques Junction Tree
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Constructing the Moral Graph
B D C E G F H
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Constructing The Moral Graph
Add undirected edges to all co-parents which are not currently joined –Marrying parents A B D C E G F H
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Constructing The Moral Graph
Add undirected edges to all co-parents which are not currently joined –Marrying parents Drop the directions of the arcs A B D C E G F H
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Triangulating An undirected graph is triangulated iff every cycle of length >3 contains an edge to connects two nonadjacent nodes A B D C E G F H
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Identifying Cliques A clique is a subgraph of an undirected graph that is complete and maximal A B D C E G F H EGH ADE ABD ACE DEF CEG
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Junction Tree A junction tree is a subgraph of the clique graph that
is a tree contains all the cliques satisfies the running intersection property EGH ADE ABD ACE DEF CEG ADE ABD ACE AD AE CEG CE DEF DE EGH EG
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Principle of Inference
DAG Junction Tree Inconsistent Junction Tree Initialization Consistent Junction Tree Propagation Marginalization
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Example: Create Join Tree
HMM with 2 time steps: X1 X2 Y1 Y2 Junction Tree: X1,X2 X1,Y1 X2,Y2 X1 X2
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Example: Initialization
X1,X2 X1,Y1 X2,Y2 X1 X2 Variable Associated Cluster Potential function X1 X1,Y1 Y1 X2 X1,X2 Y2 X2,Y2
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Example: Collect Evidence
Choose arbitrary clique, e.g. X1,X2, where all potential functions will be collected. Call recursively neighboring cliques for messages: 1. Call X1,Y1. 1. Projection: 2. Absorption:
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Example: Collect Evidence (cont.)
2. Call X2,Y2: 1. Projection: 2. Absorption: X1,X2 X1,Y1 X2,Y2 X1 X2
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Example: Distribute Evidence
Pass messages recursively to neighboring nodes Pass message from X1,X2 to X1,Y1: 1. Projection: 2. Absorption:
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Example: Distribute Evidence (cont.)
Pass message from X1,X2 to X2,Y2: 1. Projection: 2. Absorption: X1,X2 X1,Y1 X2,Y2 X1 X2
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Example: Inference with evidence
Assume we want to compute: P(X2|Y1=0,Y2=1) (state estimation) Assign likelihoods to the potential functions during initialization:
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Example: Inference with evidence (cont.)
Repeating the same steps as in the previous case, we obtain:
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Next Time Approximate Probabilistic Inference via sampling Gibbs
Priority MCMC
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THE END
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Example: Naïve Bayesian Model
A common model in early diagnosis: Symptoms are conditionally independent given the disease (or fault) Thus, if X1,…,Xp denote whether the symptoms exhibited by the patient (headache, high-fever, etc.) and H denotes the hypothesis about the patients health then, P(X1,…,Xp,H) = P(H)P(X1|H)…P(Xp|H), This naïve Bayesian model allows compact representation It does embody strong independence assumptions
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Elimination on Trees Formally, for any tree, there is an elimination ordering with induced width = 1 Thm Inference on trees is linear in number of variables
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