1. Find The Net Force on These
F = 6 N, Right
F = 80 N, Down

2. Find The Net Force on These
F = 1070 N, Uphill
F = 103 N, Downhill

3. NOW Find The Net Force on This

4. NOW Find The Net Force on This
(120 N)2 + (200 N)2 = (ΣF)2 F
233.2 N = ΣF
120 N
θ = ?
θ = 31º
200 N
Recall: Tip-to-Tail addition of vectors

5. NOW Find The Net Force on This
Start by simplifying this into a single East-West vector and a single North-South Vector

6. NOW Find The Net Force on This
Start by simplifying this into a single East-West vector and a single North-South Vector

7. NOW Find The Net Force on This
Start by simplifying this into a single East-West vector and a single North-South Vector

8. NOW Find The Net Force on This
Now add these “tip-to-tail”

9. NOW Find The Net Force on This
θ = 35.5º N of E
100 N
140 N
Now add these “tip-to-tail”

10. Try Ch 5 - page 142 # 89
89.

11. How could we Find The Net Force on This?

12. 120 N
60
Let’s try to make this look like previous net force Question
75
70 N

13. 120 N
Consider that this 120 N force is pulling partially East and partially North
60
Consider that this 200 N force is pulling partially West and partially South
75
70 N

14. 104 N
60 N
18 N
68 N

15. Now we can treat this like the previous example where we found ONE simplified east-west vector and ONE north-south vector.
55 N
36 N
104 N
41°
42 N
18 N
60 N
68 N

17. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
50 N
25 N

18. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

19. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
50 N
25 N

20. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
50 N
25 N
40°
30°

21. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

22. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
32.1 N
12.5 N
38.3 N
21.7 N

23. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
32.1 N
12.5 N
38.3 N
21.7 N

24. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

25. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
38.3 N
21.7 N

26. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
38.3 N
21.7 N

27. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
16.6 N

28. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

29. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
32.1 N
12.5 N

30. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
12.5 N
32.1 N

31. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
44.6 N

32. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
44.6 N
16.6 N

33. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

34. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
44.6 N
16.6 N

35. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

36. A 25 N force is applied to a box at 30 while a 50 N force acts on the box at 140. Find the net force on the box.
F = ____ @ ____
47.6 N
44.6 N
69.6
16.6 N

37. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

39. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos

40. Find the net force on the box below…
625 78 N of W
325 65 S of W
412 55 S of E

41. Find the net force on the box below►
611.3 N
129.9 N
236.3 N
137.4 N
294.6 N
337.5 N

42. Find the net force on the box below►
611.3 N
129.9 N
236.3 N
137.4 N
294.6 N
337.5 N

43. Find the net force on the box below►
611.3 N
129.9 N
236.3 N
137.4 N
294.6 N
337.5 N

44. Find the net force on the box below►
129.9 N
236.3 N
137.4 N

45. Find the net force on the box below►
611.3 N
294.6 N
337.5 N

46. Find the net force on the box below
Now Simplify into one vector in the x-direction and one vector in the y-direction.
31 N θ
20.8 N F
31 N ►
20.8 N
Then Use Pythagorean Thm to solve for F

47. Find the net force on the box below
Now Simplify into one vector in the x-direction and one vector in the y-direction.
31 N
33.9°
20.8 N
S from W
37.3 N
31 N ►
20.8 N ►
Then Use Pythagorean Thm to solve for F

48. By definition, an object in equilibrium has balanced forces.
Suppose one person applied an additional force to give this crate balanced forces. How much force and in what direction must it be applied?
33.9°
S from W
37.3 N
This force is called the Equilibrant force. It puts the object into a state of equilibrium.
By definition, an object in equilibrium has balanced forces.

49. WS #1
44 N
33 N
38 N
22 N

50. WS #1
33 N
38 N
22 N

51. WS #1 33 N 38 N 74.4 N 22 N 71 N 17º E of N θ 73º N of E 22 N
also describes this resultant vector direction θ
73º N of E
22 N

52. Find x and y components for each vector at an angle.
Calculate “net X” (Fx)
Calculate “net Y” (Fy)
Add net X and net Y tip-to-tail
Pythagorean Theorem
Find  using inverse Tan, Sin or Cos