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Mass Relationships in Chemical Formulas

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Presentation on theme: "Mass Relationships in Chemical Formulas"— Presentation transcript:

1 Mass Relationships in Chemical Formulas

2 Put the following chemical formulas into two categories
Put the following chemical formulas into two categories. Be able to tell me why/how you separated them. C6H6, CH4, H2O, N2O4, C2H8, H2O2, NO2, CH  

3 A molecular formula shows the exact number of atoms of each element in the smallest unit of a substance. An empirical formula shows the simplest whole-number ratio of the atoms in a substance. H2O molecular empirical H2O CH2O C6H12O6 O O3 NH2 N2H4 C2H5 C4H10 Butane

4 Write the empirical formulas for the following molecules:
acetylene (C2H2), which is used in welding torches glucose (C6H12O6), a substance known as blood sugar nitrous oxide (N2O), a gas that is used as an anesthetic gas (“laughing gas”) and as an aerosol propellant for whipped creams.

5 Percent Composition and Empirical Formulas
Steps: Percent to mass Mass to moles Divide by small Multiply ‘til whole **If you have a 100g sample, the percent composition is the same as the mass

6 Ascorbic acid (vitamin C) cures scurvy.
It is composed of percent carbon (C), 4.58 percent hydrogen (H), and percent oxygen (O) by mass. Determine its empirical formula.

7 Molecular Formula Steps: Find empirical formula
Determine the molar mass of the empirical formula Find multiplier (molar mass given/empirical molar mass) Multiply empirical formula subscripts by the multiplier

8 A sample of a compound contains 30. 46 percent nitrogen and 69
A sample of a compound contains percent nitrogen and percent oxygen by mass, as determined by a mass spectrometer. In a separate experiment, the molar mass of the compound is found to be between 90 g and 95 g. Determine the molecular formula and the accurate molar mass of the compound.

9 A compound composed of 40. 68% carbon, 5. 08% hydrogen and 54
A compound composed of 40.68% carbon, 5.08% hydrogen and 54.24% oxygen has a molar mass of g/mol. Determine the empirical and molecular formula.

10 Combustion Analysis —technique used to determine elemental composition (empirical/molecular formula) of an organic compound by combusting (reacting with O2) it under conditions where the resulting products can be quantitatively analyzed. Example: Combust 11.5 g ethanol composed of: C, H, O Collect 22.0 g CO2 and 13.5 g H2O

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12 Suppose a substance has been prepared that is composed of carbon, hydrogen and nitrogen. When g of this compound is reacted with oxygen, g of carbon dioxide and g of water are collected. The molar mass of the compound is g/mol. Determine the formula of the compound.

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