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A function f is increasing on an open interval I if, for any choice of x1 and x2 in I, with x1 < x2, we have f(x1) < f(x2). A function f is decreasing.

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Presentation on theme: "A function f is increasing on an open interval I if, for any choice of x1 and x2 in I, with x1 < x2, we have f(x1) < f(x2). A function f is decreasing."— Presentation transcript:

1 A function f is increasing on an open interval I if, for any choice of x1 and x2 in I, with x1 < x2, we have f(x1) < f(x2). A function f is decreasing on an open interval I if, for any choice of x1 and x2 in I, with x1 < x2, we have f(x1) > f(x2). A function f is constant on an open interval I if, for any choice of x in I, the values of f(x) are equal.

2 y (2, 3) (4, 0) (1, 0) x (10, -3) (0, -3) (7, -3) Increasing (0,2)
Decreasing (2,7) 2 < x < 7 4 (2, 3) Constant (7,10) 7 < x < 10 (4, 0) (1, 0) x (10, -3) (0, -3) (7, -3) -4

3 A function f has a local maximum at c if there is an interval I containing c so that, for all x in I, f(x) < f(c). We call f(c) a local maximum of f. A function f has a local minimum at c if there is an interval I containing c so that, for all x in I, f(x) > f(c). We call f(c) a local minimum of f.

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6 g(-z) = -(-z)2+2 =-z2+2

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11 (1, 3)

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