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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. Use g = 10 m/s2 a) What happens to the fridge if you push on it with 460 N of force? Explain. 100 kg
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. Fridge is stationary, so you are pushing against STATIC Friction FA = 460 N Static Friction can provide UP TO 520 N of force Ff = ? But if I only push with 460 N of force then…
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. FA = 460 N Ff = 460 N …then friction only pushes back with 460 N of force
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. b) Suppose your friend helps by pushing with an additional 350 N. What happens to the fridge? Show Calculation. 100 kg
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. Now the applied force pushing to the right is 810 N FA = 350 N FA = 460 N Which is bigger than the maximum Static friction (520N) Ff = ? But once it is moving, how much friction are the two of you pushing against?
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. Now the applied force pushing to the right is 810 N FA = 350 N FA = 460 N Which is bigger than the maximum Static friction (520N) Ff = 340 N But once it is moving, how much friction are the two of you pushing against?
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. So Now calculate the net force and acceleration of the fridge… FA = 350 N FA = 460 N 810 N – 340 N = (100 kg )a 4.7 m/s2 = a Ff = 340 N
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A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a mass of 100 kg. FA = 520 N c) What is the minimum force that you must push with to just get the fridge started moving? What force to push at const vel? 100 kg FA = 340 N
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A 4 kg Block gets pushed to the right and slides with a uniform acceleration for 35 m in 5.0 s from an initial velocity of 3.0 m/s. If µ = 0.30, what is magnitude of the force applied to the block by the outside push? (start with a force diagram)
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A 4 kg Block gets pushed to the right and slides with a uniform acceleration for 35 m in 5.0 s from an initial velocity of 3.0 m/s. If µ = 0.30, what is magnitude of the force applied to the block by the outside push? (start with a force diagram) Ff = µ mg FA = ? 4 kg Solve for acceleration: FA – Ff = ma FA = Ff + ma (algebra step) d = 35 m t = 5 s v1 = 3 m/s d = v1t +1/2 a t2 FA = µ mg + ma (substitution step) FA = (0.3)(4kg)(9.8 m/s2) + (4kg)(1.6 m/s2) FA = (11.76 N) + (6.4 N) FA = N a = 1.6 m/s2
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