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Sequences and Series Day 7
Good afternoon Happy Tuesday!
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Warm-Up How can we identify if a sequence is arithmetic, geometric or neither? Given π π = πβ1 what is the first term in the sequence? 3) Find the sum: π=3 6 π 2
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Questions on the homework?
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Partial Sum of Geometric Sequences
Just like arithmetic sequences we are going use partial sums with geometric sequences(aka geometric series) . For the geometric sequence π, ππ, π π 2 ,π π 3 ,β¦ ππ πβ1 ,β¦the nth partial sum is π π = π=1 π π π πβ1 =π+ππ+π π 2 +π π 3 +β¦+π π πβ1
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Partial Sum formula With out going through the proof: We need to multiply π π by π and subtract that from π π π π βπ π π =πβπ π π β π π 1βπ =π 1β π π So π π = π 1β π π 1βπ , πβ 1
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Summary The formula to find the nth partial sum of a geometric sequence is π π =π 1β π π 1βπ
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Practice Find the sum of the first five terms of the geometric sequence: 1,0.7,0.49,0.343 π=1, π=0.7 Using the formula for π π and n=5 We get π 5 =1β 1β β0.7 = So the sum of the first five terms is
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Practice Find the sum π=1 5 7 β 2 3 π We need find a, r and n. Then use the formula, keep in fraction form.
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Answer Find the sum π=1 5 7 β 2 3 π π=5, π=β 2 3 , π=7ββ 2 3 =β ππ π
π=5, π=β 2 3 , π=7ββ 2 3 =β ππ π Why is a=β 14 3 and not 7 ? since k is 1, we start there. If k=0 then a=7 Formula π π =β β 1β β ββ 2 3 = β 14 3 β =β =β3.1687
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You Try Are the following geometric if so what is the common ratio? 3,6,12,24β¦ 2,4,6,8β¦ 1 2 , 1 6 , 1 18 , 1 54 β¦ Find the partial sum π π of the geometric sequence that satisfies the given conditions 4) π=3, π=4, π=6 5) π= 5 6 , π= 1 6 , π=4
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Solutions 1) Yes, r=2 2) No, arithmetic 3) Yes , r= 1/3 4) π 6 =3 1β 4 6 1β4 =4095 5) π 4 = 5 6 1β β 1 6 =
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Homework Tonight Page 840:#βs 23-25,27-30, 31,33, 35 (hint for 25 you will have to find π and π first)
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Infinite Series
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